7.1 Rates & Speed/Distance/Time
Key Takeaways
A rate is a ratio comparing two quantities with different units; a unit rate has denominator 1.
Speed = Distance ÷ Time; cover the quantity you need in the triangle — multiply for distance, divide for speed or time.
Always convert units so numerator and denominator match before dividing or multiplying inside a rate problem.
IV flow rate follows the same relationship: Rate = Volume ÷ Time (mL/h for pumps, gtt/min for gravity drips using the drop factor on the tubing).
In work problems, add the individual rates (work per hour), not the individual times, then take the reciprocal to find the combined time.
7.1 Rates & Speed/Distance/Time
Quick Answer: A rate compares two quantities with different units, like kilometers per hour or dollars per pound. Speed is the rate distance ÷ time. To find any one of speed, distance, or time, cover that variable in the formula triangle and the remaining two tell you the operation to perform.
What Is a Rate?
A rate is a ratio that compares two quantities measured in different units. When you see the word "per," the phrase "for every," or a fraction bar between unlike units, you are working with a rate. Common NEX examples include dollars per kilogram, miles per gallon, and milliliters per hour.
A unit rate simplifies a rate so the denominator is 1. If 12 ounces of infant formula cost $3.00, the unit rate is $3.00 ÷ 12 oz = $0.25 per ounce. Unit rates let you compare options side by side: the better buy is the one with the smaller unit price.
Always reduce a rate to its simplest fractional form first. Writing the units into the fraction keeps you honest — when the units cancel, the answer lands in the right unit.
The Speed Triangle
Speed, distance, and time form a tight relationship:
| Quantity | Formula |
|---|---|
| Speed | Distance ÷ Time |
| Distance | Speed × Time |
| Time | Distance ÷ Speed |
A memory triangle helps. Write Distance on top, Speed and Time side by side below it. Cover the quantity you need; the remaining two show the operation. Cover Distance → Speed and Time sit side by side, so multiply. Cover Speed → Distance sits over Time, so divide. Cover Time → Distance sits over Speed, so divide.
Worked example 1. An ambulance travels 168 miles in 3 hours at a constant speed. Find the speed.
Cover Speed in the triangle: Distance ÷ Time. 168 mi ÷ 3 h = 56 mi/h. The speed is 56 mph.
Worked example 2. An IV pump delivers 120 mL/h. How much volume is infused in 4.5 hours?
Cover Distance (here, volume): Speed × Time. 120 mL/h × 4.5 h = 540 mL. Check the units: h cancels, leaving mL.
Worked example 3. A patient walks 2.4 km at 0.8 km/h. How long does the walk take?
Cover Time: Distance ÷ Speed. 2.4 km ÷ 0.8 km/h = 3 h.
Converting Units Inside a Rate
Rates on the NEX frequently arrive in mixed units. Convert before dividing or multiplying so the rate matches what the question asks.
Worked example 4. A runner covers 400 meters in 50 seconds. Give the speed in km/h.
First convert distance: 400 m = 0.4 km. Then speed = 0.4 km ÷ 50 s = 0.008 km/s. To switch seconds to hours, multiply by 3600 (the number of seconds in one hour): 0.008 × 3600 = 28.8 km/h. Alternatively, convert time first: 50 s = 50/3600 h, then speed = 0.4 km ÷ (50/3600) h = 28.8 km/h. Same result.
The useful shortcut: 1 m/s = 3.6 km/h. So 400 m ÷ 50 s = 8 m/s, and 8 × 3.6 = 28.8 km/h.
Nursing Drip-Rate Basics
IV flow rates are rates — nothing new mathematically. The core relationship is:
Rate = Volume ÷ Time
If an order is 1,000 mL over 8 hours, the pump rate is 1,000 ÷ 8 = 125 mL/h. If a 500 mL bag must run over 10 hours, the rate is 50 mL/h.
For gravity drips (no pump), the rate is expressed in drops per minute (gtt/min):
gtt/min = (Volume × drop factor) ÷ Time in minutes
The drop factor (gtt/mL) is printed on the tubing package — common values are 10, 15, and 60. The NEX does not require you to memorize drop factors; the question gives you one.
Worked example 5. Infuse 1,200 mL over 6 hours using tubing with a drop factor of 15 gtt/mL. Find the drip rate.
Time in minutes = 6 × 60 = 360 min. Volume × drop factor = 1,200 × 15 = 18,000 gtt. Drip rate = 18,000 ÷ 360 = 50 gtt/min.
Work Problems (Combined Rates)
When more than one worker or pump works together, add their rates, not their times.
Worked example 6. One pump fills a tank in 6 hours; a second pump fills the same tank in 3 hours. How long do they take together?
Rates: 1/6 tank per hour and 1/3 tank per hour. Combined rate = 1/6 + 1/3 = 1/6 + 2/6 = 3/6 = 1/2 tank per hour. Time to fill one tank = 1 ÷ (1/2) = 2 hours.
If three identical pumps each fill a tank in 6 hours, together their rate is 3 × (1/6) = 1/2 tank per hour, so the fill time is again 2 hours.
Common Traps
- Unit mismatch in numerator/denominator. Distance in miles but time in minutes — convert one before dividing.
- Dividing the wrong way. Speed is distance ÷ time, not time ÷ distance. The larger quantity (usually distance) goes on top.
- Adding times instead of rates in work problems. Add rates (tanks per hour), never the hours themselves.
- Forgetting to convert minutes to hours when the rate is per hour but the time is given in minutes.
- Drop-factor confusion. gtt/mL is the number of drops per 1 mL — multiply by volume, then divide by minutes.
A patient receives an IV infusion of 1,000 mL over 8 hours. What is the pump rate in mL/h?
125 mL/h
100 mL/h
80 mL/h
150 mL/h
A runner covers 400 meters in 50 seconds. Using the shortcut 1 m/s = 3.6 km/h, what is the speed in km/h?
18 km/h
24 km/h
20 km/h
28.8 km/h
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