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5.1 Descriptive Statistics & Data Measures

Key Takeaways

  • The arithmetic mean is equal to sum / n, whereas the median is the middle value of ordered data; mean is sensitive to extreme outliers, whereas median is robust.

  • Adding a constant k to all data points shifts the mean and median by k but leaves standard deviation (SD) and range completely unchanged.

  • Multiplying all data points by a positive constant k multiplies the mean, median, range, and standard deviation all by k (and multiplies variance by k²).

  • Under the 68-95-99.7 empirical rule for normal distributions, approximately 68% of data lies within 1 SD of the mean, 95% within 2 SDs, and 99.7% within 3 SDs.

Last updated: July 2026

5.1 Descriptive Statistics & Data Measures

Descriptive statistics forms a cornerstone of the GRE Quantitative Reasoning section. The exam tests your capacity to summarize data sets, evaluate central tendencies, measure variability, understand how mathematical transformations alter data summaries, and apply properties of symmetrical distributions such as the normal curve.


Measures of Central Tendency

Central tendency measures describe the center or typical value of a numerical data set. The three primary metrics tested on the GRE are the arithmetic mean, median, and mode.

1. Arithmetic Mean & Weighted Average

The arithmetic mean (commonly referred to simply as the average) of a set of nn numbers is the sum of all values divided by nn:

Mean=xˉ=∑i=1nxin=x1+x2+⋯+xnn\text{Mean} = \bar{x} = \frac{\sum_{i=1}^{n} x_i}{n} = \frac{x_1 + x_2 + \dots + x_n}{n}

Key Properties of the Mean:

  • Sum Formula: Sum=Mean×n\text{Sum} = \text{Mean} \times n. In many GRE word problems, finding the sum of elements is the essential first step.
  • Balance Point: The sum of the deviations of each data point from the mean is always zero: ∑(xi−xˉ)=0\sum (x_i - \bar{x}) = 0.
  • Sensitivity to Outliers: Extreme values heavily pull the mean toward them.

Weighted Average

When combining groups of different sizes or weights, you cannot simply average their individual means. Instead, use the weighted average formula:

Weighted Mean=w1x1+w2x2+⋯+wkxkw1+w2+⋯+wk\text{Weighted Mean} = \frac{w_1 x_1 + w_2 x_2 + \dots + w_k x_k}{w_1 + w_2 + \dots + w_k}

Worked Example (Weighted Mean): Class A has 20 students with a test mean of 80. Class B has 30 students with a test mean of 90. What is the combined mean for all 50 students?

Combined Mean=(20×80)+(30×90)20+30=1600+270050=430050=86\text{Combined Mean} = \frac{(20 \times 80) + (30 \times 90)}{20 + 30} = \frac{1600 + 2700}{50} = \frac{4300}{50} = 86

2. Median & Mode

Median (Q2Q_2)

The median is the middle number when a data set is arranged in ascending or descending order.

  • Odd nn: The median is the single middle value located at position n+12\frac{n+1}{2}. For example, in {3,7,9,12,15}\{3, 7, 9, 12, 15\}, n=5n=5, and the median is 99.
  • Even nn: The median is the average of the two central numbers at positions n2\frac{n}{2} and n2+1\frac{n}{2} + 1. For example, in {4,8,11,17,20,25}\{4, 8, 11, 17, 20, 25\}, n=6n=6, and the median is 11+172=14\frac{11 + 17}{2} = 14.
  • Robustness: Unlike the mean, the median is resistant to extreme outliers. Adding an extreme value like 1,0001,000 to the set {3,7,9,12,15}\{3, 7, 9, 12, 15\} changes the mean drastically but changes the median only slightly.

Mode

The mode is the value that appears most frequently in a data set.

  • A data set can have one mode (unimodal), more than one mode (bimodal or multimodal), or no mode at all (if every number appears with equal frequency).
  • Example: In {2,4,4,7,9,9,9,12}\{2, 4, 4, 7, 9, 9, 9, 12\}, the mode is 99.

Measures of Dispersion: Range & Standard Deviation

While central tendency pinpoints the middle of a data set, measures of dispersion describe how spread out the data values are.

MeasureDefinitionFormulaKey Characteristic
RangeDifference between highest and lowest valuesMax−Min\text{Max} - \text{Min}Highly sensitive to extreme outliers
VarianceAverage of squared deviations from the meanσ2=∑(xi−xˉ)2n\sigma^2 = \frac{\sum (x_i - \bar{x})^2}{n}Measured in squared units
Standard Deviation (SD)Square root of varianceσ=∑(xi−xˉ)2n\sigma = \sqrt{\frac{\sum (x_i - \bar{x})^2}{n}}Measured in same units as raw data

Step-by-Step Variance and Standard Deviation Calculation

Consider the data set {2,4,4,4,6}\{2, 4, 4, 4, 6\} (n=5n = 5):

  1. Find the Mean: xˉ=2+4+4+4+65=205=4\bar{x} = \frac{2 + 4 + 4 + 4 + 6}{5} = \frac{20}{5} = 4.
  2. Compute Deviations from Mean (xi−xˉx_i - \bar{x}): −2,0,0,0,+2-2, 0, 0, 0, +2.
  3. Square Each Deviation ((xi−xˉ)2(x_i - \bar{x})^2): 4,0,0,0,44, 0, 0, 0, 4.
  4. Calculate Variance (Average of Squared Deviations): σ2=4+0+0+0+45=85=1.6\sigma^2 = \frac{4 + 0 + 0 + 0 + 4}{5} = \frac{8}{5} = 1.6.
  5. Calculate Standard Deviation: σ=1.6≈1.265\sigma = \sqrt{1.6} \approx 1.265.

Operational Properties of Standard Deviation on the GRE

GRE Quantitative Reasoning frequently tests standard deviation conceptually without requiring laborious arithmetic. Memorize these transformation rules:

  1. Adding/Subtracting a Constant (+k+k or −k-k): If a constant kk is added to (or subtracted from) every data point in a set:

    • Mean increases by kk: xˉnew=xˉ+k\bar{x}_{new} = \bar{x} + k.
    • Median increases by kk: Mediannew=Median+k\text{Median}_{new} = \text{Median} + k.
    • Standard Deviation remains UNCHANGED: σnew=σ\sigma_{new} = \sigma. (Shifting the entire data set along the number line does not alter the distance between data points).
    • Range remains UNCHANGED: Rangenew=Range\text{Range}_{new} = \text{Range}.
  2. Multiplying/Dividing by a Constant (×k\times k for k>0k > 0): If every data point in a set is multiplied by a positive constant kk:

    • Mean is multiplied by kk: xˉnew=k⋅xˉ\bar{x}_{new} = k \cdot \bar{x}.
    • Median is multiplied by kk: Mediannew=k⋅Median\text{Median}_{new} = k \cdot \text{Median}.
    • Standard Deviation is multiplied by kk: σnew=k⋅σ\sigma_{new} = k \cdot \sigma.
    • Variance is multiplied by k2k^2: σnew2=k2⋅σ2\sigma^2_{new} = k^2 \cdot \sigma^2.
    • Range is multiplied by kk: Rangenew=k⋅Range\text{Range}_{new} = k \cdot \text{Range}.
  3. Spread Comparison:

    • A data set whose values are clustered tightly around the mean has a smaller SD.
    • A data set whose values are spread far from the mean has a larger SD.

The Normal Distribution & The 68-95-99.7 Empirical Rule

A normal distribution is a symmetric, bell-shaped continuous probability distribution. Its central axis of symmetry occurs at the mean μ\mu, which equals both the median and the mode (Mean = Median = Mode).

                      Normal Curve (68-95-99.7 Rule)
                                  | 
                               .  |  .
                             .    |    .
                           .      |      .
                        .   34%   |   34%  .
                     . 13.5%      |      13.5% .
                 . 2.35%          |          2.35% .
             ---------------------------------------------------
              μ-3σ   μ-2σ   μ-1σ  μ   μ+1σ   μ+2σ   μ+3σ

The 68-95-99.7 Empirical Rule Breakdown:

  • μ±1σ\mu \pm 1\sigma: Approximately 68% of all data falls within 1 standard deviation of the mean (34% between μ−1σ\mu - 1\sigma and μ\mu, 34% between μ\mu and μ+1σ\mu + 1\sigma).
  • μ±2σ\mu \pm 2\sigma: Approximately 95% of all data falls within 2 standard deviations of the mean (13.5% between 1σ1\sigma and 2σ2\sigma on each side).
  • μ±3σ\mu \pm 3\sigma: Approximately 99.7% of all data falls within 3 standard deviations of the mean (2.35% between 2σ2\sigma and 3σ3\sigma on each side).
  • Tails: Only 0.15% of data lies beyond +3σ+3\sigma, and 0.15% lies below −3σ-3\sigma.

Worked Example (Empirical Rule): Test scores are normally distributed with a mean of 72 and a standard deviation of 8. In a group of 1,000 test takers, how many students scored between 64 and 88?

  • 64=72−8=μ−1σ64 = 72 - 8 = \mu - 1\sigma.
  • 88=72+2(8)=μ+2σ88 = 72 + 2(8) = \mu + 2\sigma.
  • Between μ−1σ\mu - 1\sigma and μ\mu: 34%34\%.
  • Between μ\mu and μ+2σ\mu + 2\sigma: 95%/2=47.5%95\% / 2 = 47.5\%.
  • Total percentage = 34%+47.5%=81.5%34\% + 47.5\% = 81.5\%.
  • Number of students = 81.5%×1000=81581.5\% \times 1000 = 815 students.

GRE Exam Tips & Quantitative Comparison Strategies

  1. QC Strategy - Estimating SD without Calculation: If Quantitative Comparison asks you to compare the SD of Set A {10,20,30,40,50}\{10, 20, 30, 40, 50\} vs Set B {10,10,30,50,50}\{10, 10, 30, 50, 50\}, notice that Set B has more numbers further from its mean of 30 (10,10,50,5010, 10, 50, 50) than Set A (20,4020, 40). Thus, Set B has a larger standard deviation.
  2. Mean vs Median Skewness Trap:
    • Right-Skewed (Positively Skewed): Long tail to the right   ⟹  Mean>Median\implies \text{Mean} > \text{Median}.
    • Left-Skewed (Negatively Skewed): Long tail to the left   ⟹  Mean<Median\implies \text{Mean} < \text{Median}.
    • Symmetric: Mean=Median\text{Mean} = \text{Median}.
Test Your Knowledge

Class A contains 20 students with a mean test score of 80, and Class B contains 30 students with a mean test score of 90. What is the combined mean test score for all 50 students?

A

84

B

85

C

88

D

86

Test Your Knowledge

A data set consists of 6 positive integers: {3, 7, 7, X, 10, 15}, written in ascending order. If the median of the set is 8.5, what is the value of X?

A

8

B

9

C

10

D

11

Test Your Knowledge

A list of numerical data has a mean of 50 and a standard deviation of 6. If every number in the list is multiplied by 3 and then increased by 10, what are the new mean and new standard deviation?

A

New Mean = 150, New Standard Deviation = 18

B

New Mean = 160, New Standard Deviation = 6

C

New Mean = 160, New Standard Deviation = 28

D

New Mean = 160, New Standard Deviation = 18

Test Your Knowledge

Exam scores in a large administration are normally distributed with a mean of 72 and a standard deviation of 8. Out of 1,000 test takers, approximately how many scored between 64 and 88?

A

680

B

815

C

950

D

840

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