AC Circuits and Three-Phase Power
Key Takeaways
- An AC sinusoid v(t) = V_m sin(ωt + φ) has angular frequency ω = 2πf; US line frequency is 60 Hz.
- RMS values do the work of power: V_rms = V_m/√2 ≈ 0.707 V_m; "120 V" household power is RMS (peak ≈ 170 V).
- Impedance Z = R + jX; inductive reactance X_L = ωL, capacitive reactance X_C = 1/(ωC); |Z| = √(R² + X²).
- ELI the ICE man: in an inductor voltage (E) leads current (I); in a capacitor current (I) leads voltage (E).
- Power factor PF = cos φ = P/S; real power P (W), reactive Q (VAR), apparent S (VA), with S² = P² + Q².
- Balanced three-phase power: P = √3 V_L I_L cos φ; in wye V_L = √3 V_φ, in delta I_L = √3 I_φ.
AC Fundamentals and RMS
Alternating current varies sinusoidally with time: where V_m is the peak (amplitude), ω = 2πf is the angular frequency in rad/s, f is the frequency in hertz (60 Hz in North America, 50 Hz in much of the world), and φ is the phase angle. 707,V_m, \qquad I_{rms} = \frac{I_m}{\sqrt{2}}$$ Every AC voltage rating you see — 120 V outlets, 480 V industrial feeders — is an RMS value; the 120 V outlet actually peaks near 170 V. ** A frequent FE error is plugging peak values into P = VI or treating a quoted line voltage as a peak.
Impedance and Reactance
In AC circuits, capacitors and inductors oppose current in a frequency-dependent, phase-shifting way described by impedance Z, the AC generalization of resistance, expressed as a complex number:
| Element | Impedance | Reactance | Phase relationship |
|---|---|---|---|
| Resistor | Z = R | X = 0 | V and I in phase |
| Inductor | Z = jωL | X_L = ωL | current LAGS voltage 90° |
| Capacitor | Z = −j/(ωC) | X_C = 1/(ωC) | current LEADS voltage 90° |
The mnemonic ELI the ICE man captures the phasing: in an inductor (L), voltage E leads current I (ELI); in a capacitor (C), current I leads voltage E (ICE). Reactance grows with frequency for an inductor (X_L = ωL) but shrinks for a capacitor (X_C = 1/ωC) — at very high frequency an inductor blocks and a capacitor passes current.
Series RLC, Resonance, and the Power Triangle
For a series RLC circuit the reactances of L and C subtract because they are 90° out of phase with each other (opposite signs): At the resonant frequency the two reactances are equal (X_L = X_C) and cancel, leaving Z = R (purely resistive) and current at its maximum:
Worked impedance example. A series circuit has R = 30 Ω, X_L = 40 Ω, X_C = 10 Ω. Net reactance = 40 − 10 = 30 Ω (inductive). |Z| = √(30² + 30²) = √1,800 = 42.4 Ω, with phase angle arctan(30/30) = 45° (current lags). At 120 V_rms, I = 120/42.4 = 2.83 A.
The power triangle. In AC, current and voltage may be out of phase, splitting power into three parts:
| Quantity | Symbol | Formula | Unit |
|---|---|---|---|
| Real (active) power | P | VI cos φ = I²R | watts (W) |
| Reactive power | Q | VI sin φ = I²X | VAR |
| Apparent power | S | VI = I²·|Z| | VA |
They relate by S² = P² + Q², i.e. S = √(P² + Q²). Only real power P does useful work or shows as heat; reactive power Q sloshes back and forth into inductors/capacitors each cycle. The power factor is: Inductive (lagging) loads — motors, transformers — dominate industry. Utilities penalize low power factor because it raises line current for the same useful power; adding capacitors corrects a lagging PF toward unity, cutting current and losses.
Three-Phase Power
Large power systems use three-phase AC: three voltages 120° apart, delivering constant total power and using conductors efficiently. Loads connect in wye (Y / star) or delta (Δ):
| Configuration | Voltage relation | Current relation |
|---|---|---|
| Wye (Y) | V_L = √3 V_φ | I_L = I_φ |
| Delta (Δ) | V_L = V_φ | I_L = √3 I_φ |
where V_L is line-to-line voltage, V_φ phase voltage, I_L line current, I_φ phase current. For a balanced load, total real and apparent power are: Using line quantities, the √3 already accounts for all three phases — do not multiply by 3 again. The common 480/277 V building system is wye: 480 V between lines, 277 V (= 480/√3) line-to-neutral.
Worked power-factor example. A load draws P = 5 kW of real power and Q = 4 kVAR of reactive power. Apparent power S = √(P² + Q²) = √(5² + 4²) = √41 = 6.40 kVA, so PF = P/S = 5/6.40 = 0.78 lagging. To raise the PF to unity, a capacitor bank supplying 4 kVAR of leading reactive power is added, canceling the load's 4 kVAR and dropping line current.
Worked three-phase example. A balanced three-phase motor runs at V_L = 480 V, draws I_L = 10 A, PF = 0.85, with 90% efficiency. Input power P_in = √3 × 480 × 10 × 0.85 = 7,064 W. Output power P_out = 0.90 × 7,064 = 6,358 W ≈ 8.5 hp (÷ 745.7 W/hp).
Measuring devices. A voltmeter (high internal resistance) connects in parallel; an ammeter (low resistance) connects in series; a wattmeter uses a parallel voltage coil and a series current coil; an ohmmeter is used only on a de-energized circuit. Connecting an ammeter in parallel (a near-short) is a classic destructive mistake.
A series RLC circuit has R = 30 Ω, X_L = 40 Ω, and X_C = 10 Ω. The impedance magnitude is:
A load draws 5 kW of real power and 4 kVAR of reactive power. The power factor is closest to:
In a balanced wye-connected three-phase system with a 480 V line-to-line voltage, the phase (line-to-neutral) voltage is:
At resonance in a series RLC circuit, which statement is true?