3.3 Mechanics of Materials
Key Takeaways
- Axial normal stress σ = P/A and elastic axial deformation δ = PL/AE; Hooke's law gives σ = Eε.
- Flexure (bending) stress is σ = Mc/I, maximum at the extreme fiber; transverse shear stress is τ = VQ/(Ib).
- Torsional shear stress in a circular shaft is τ = Tr/J with J = πr⁴/2 (πd⁴/32) for a solid shaft.
- The slope of the shear diagram equals the load; the slope of the moment diagram equals the shear (dM/dx = V).
- Euler critical buckling load is Pcr = π²EI/(KL)², with K = 1.0 pinned-pinned, 0.5 fixed-fixed, 2.0 fixed-free.
The Analytical Core of FE Civil
Mechanics of Materials carries 6–9 questions and underpins every Structural Engineering problem. The skill tested is matching a loading (axial, torsion, bending, shear, combined) to the correct stress equation and the right section property.
Stress, Strain, and Hooke's Law
Normal stress is force per unit area, σ = P/A. Normal strain is ε = δ/L. In the elastic range they follow Hooke's law:
where E is the modulus of elasticity (≈ 29,000 ksi / 200 GPa for steel). Poisson's ratio ν relates lateral to axial strain (ν ≈ 0.3 for steel). The shear modulus is G = E / [2(1 + ν)].
Axial Loading
Elastic axial deformation of a prismatic bar:
Thermal elongation is δ = αLΔT. If the bar is restrained, a thermal stress σ = EαΔT develops.
Torsion
For a circular shaft, the torsional shear stress is:
The polar moment of inertia J = πr⁴/2 = πd⁴/32 (solid). Stress is maximum at the outer surface and zero at the center.
Shear and Moment Diagrams
The load, shear, and moment are linked by calculus:
| Relationship | Meaning |
|---|---|
| dV/dx = −w | slope of shear = −distributed load |
| dM/dx = V | slope of moment = shear |
| ΔV = −∫w dx | change in shear = area under load |
| ΔM = ∫V dx | change in moment = area under shear |
Maximum bending moment occurs where shear crosses zero. For a simply supported beam of span L with a central point load P, M_max = PL/4; with a uniform load w, M_max = wL²/8.
Bending and Transverse Shear Stress
Flexure stress varies linearly through the depth:
maximum at the extreme fiber (distance c from the neutral axis). Transverse shear stress is τ = VQ/(Ib), maximum at the neutral axis where Q (first moment of area) is largest.
Beam Deflection
Standard cases are tabulated in the NCEES FE Reference Handbook — look them up, do not derive:
- Simply supported, central point load P: δ_max = PL³/(48EI)
- Simply supported, uniform load w: δ_max = 5wL⁴/(384EI)
- Cantilever, end point load P: δ_max = PL³/(3EI)
Combined Stress and Mohr's Circle
When axial, bending, and torsion act together, superpose normal stresses and use Mohr's circle to find principal stresses and maximum shear:
The maximum in-plane shear stress equals the circle's radius, τ_max = √[((σx − σy)/2)² + τxy²].
Columns and Buckling
Long, slender columns fail by elastic (Euler) buckling, not crushing:
The effective-length factor K depends on end conditions: K = 1.0 (pinned–pinned), 0.5 (fixed–fixed), 0.7 (fixed–pinned), 2.0 (fixed–free cantilever). Buckling controls when the slenderness ratio KL/r is large. These K values are tabulated in the handbook — confirm the support condition before selecting K.
A simply supported beam spans 6 m and carries a uniformly distributed load of 10 kN/m over its entire length. What is the maximum bending moment?
A pinned-pinned steel column is 4 m long with I = 8 × 10⁶ mm⁴ and E = 200 GPa. What is the Euler critical buckling load? (Use K = 1.0.)