4.6 Inverse Functions & Their Properties

Key Takeaways

  • A function f has an inverse function f^(-1) if and only if f is one-to-one (1-to-1), passing the Horizontal Line Test.
  • Cancellation equations guarantee f(f^(-1)(x)) = x for all x in Domain(f^(-1)) and f^(-1)(f(x)) = x for all x in Domain(f).
  • Domain and range swap completely between inverse pairs: Domain(f^(-1)) = Range(f) and Range(f^(-1)) = Domain(f).
  • To calculate f^(-1)(x) algebraically: set y = f(x), interchange x and y, solve for y, and replace y with f^(-1)(x).
  • Geometrically, the graph of f^(-1)(x) is a reflection of the graph of f(x) across the identity line y = x, mapping points (a, b) -> (b, a).
Last updated: August 2026

4.6 Inverse Functions & Their Properties

In mathematics, an inverse function undoes or reverses the operational effect of the original function. If a function ff maps an input xx to an output yy, its inverse function f1f^{-1} maps that output yy directly back to the original input xx.

f(x)=y    f1(y)=xf(x) = y \iff f^{-1}(y) = x

NOTATION WARNING: The superscript 1-1 in f1(x)f^{-1}(x) denotes an inverse function, NOT an exponent or reciprocal! f1(x)1f(x)f^{-1}(x) \ne \frac{1}{f(x)}. The multiplicative inverse (reciprocal) is written as [f(x)]1=1f(x)[f(x)]^{-1} = \frac{1}{f(x)}.


1. One-to-One Functions and the Horizontal Line Test

Not every function possesses a valid inverse function. For an inverse relation to satisfy the Vertical Line Test (and thus be a true function), the original function must be one-to-one (1-to-1).

  • Formal Definition: A function ff is one-to-one if no two distinct inputs x1x2x_1 \ne x_2 map to the exact same output value f(x1)=f(x2)f(x_1) = f(x_2). Algebraically: f(x1)=f(x2)    x1=x2f(x_1) = f(x_2) \implies x_1 = x_2

The Horizontal Line Test (HLT)

Graphically, a function f(x)f(x) has a valid inverse function f1(x)f^{-1}(x) if and only if no horizontal line intersects the graph of f(x)f(x) in more than one point.

  • Fails HLT: The parabola f(x)=x2f(x) = x^2 fails the horizontal line test (e.g., horizontal line y=4y = 4 intersects at (2,4)(-2, 4) and (2,4)(2, 4)). Reversing these points gives (4,2)(4, -2) and (4,2)(4, 2), which fails the Vertical Line Test. Thus, f(x)=x2f(x) = x^2 is not one-to-one on (,)(-\infty, \infty) and lacks a general inverse function.
  • Passes HLT: The cubic curve f(x)=x3f(x) = x^3 passes the horizontal line test everywhere. It is one-to-one and possesses a valid inverse function f1(x)=x3f^{-1}(x) = \sqrt[3]{x}.

2. Fundamental Inverse Cancellation Identities & Domain-Range Swapping

If ff and f1f^{-1} are inverse functions, they satisfy two mandatory cancellation equations:

  1. f(f1(x))=xfor all xDomain(f1)f\Big(f^{-1}(x)\Big) = x \quad \text{for all } x \in \text{Domain}\left(f^{-1}\right)
  2. f1(f(x))=xfor all xDomain(f)f^{-1}\Big(f(x)\Big) = x \quad \text{for all } x \in \text{Domain}(f)

Complete Domain and Range Interchange

Because an inverse function swaps input and output roles, the domain and range of ff and f1f^{-1} are completely interchanged:

Domain(f1)=Range(f)\text{Domain}\left(f^{-1}\right) = \text{Range}(f) Range(f1)=Domain(f)\text{Range}\left(f^{-1}\right) = \text{Domain}(f)


3. Four-Step Algebraic Algorithm to Compute f1(x)f^{-1}(x)

To derive the explicit algebraic equation for the inverse of a one-to-one function f(x)f(x):

  1. Step 1: Replace f(x)f(x) with yy.
  2. Step 2: Interchange the variables xx and yy (replace every xx with yy, and yy with xx).
  3. Step 3: Solve the resulting equation for yy in terms of xx.
  4. Step 4: Replace yy with inverse notation f1(x)f^{-1}(x), and state any domain restrictions.

Worked Example 1: Rational Function Inverse

Find the inverse of f(x)=4x+1x3f(x) = \frac{4x + 1}{x - 3} for x3x \ne 3.

  1. Step 1 (Set yy): y=4x+1x3y = \frac{4x + 1}{x - 3}
  2. Step 2 (Swap xx and yy): x=4y+1y3x = \frac{4y + 1}{y - 3}
  3. Step 3 (Solve for yy): Cross-multiply: x(y3)=4y+1    xy3x=4y+1x(y - 3) = 4y + 1 \implies xy - 3x = 4y + 1. Collect yy terms on one side: xy4y=3x+1    y(x4)=3x+1    y=3x+1x4xy - 4y = 3x + 1 \implies y(x - 4) = 3x + 1 \implies y = \frac{3x + 1}{x - 4}
  4. Step 4 (Write f1(x)f^{-1}(x)): f1(x)=3x+1x4,x4f^{-1}(x) = \frac{3x + 1}{x - 4}, \quad x \ne 4

4. Restricting Domains of Non-One-to-One Functions

When a function fails the Horizontal Line Test over its natural domain, we can restrict its domain to a monotonic sub-interval where it passes the HLT, allowing an inverse function to be constructed.

Worked Example 2: Domain-Restricted Quadratic Inverse

Find the inverse of f(x)=(x2)2+5f(x) = (x - 2)^2 + 5 restricted to domain x2x \ge 2.

  1. Domain & Range Analysis:
    • Restricted Domain of ff: [2,)[2, \infty).
    • Range of ff: Since (x2)20(x-2)^2 \ge 0, f(x)5    [5,)f(x) \ge 5 \implies [5, \infty).
  2. Swap and Solve: x=(y2)2+5    x5=(y2)2x = (y - 2)^2 + 5 \implies x - 5 = (y - 2)^2 Take the principal (positive) square root because y2y \ge 2: x5=y2    y=x5+2\sqrt{x - 5} = y - 2 \implies y = \sqrt{x - 5} + 2
  3. Conclusion: f1(x)=x5+2with Domain [5,)f^{-1}(x) = \sqrt{x - 5} + 2 \quad \text{with Domain } [5, \infty)

5. Geometric Reflection Property Across y=xy = x

The graph of y=f1(x)y = f^{-1}(x) is a precise reflection of the graph of y=f(x)y = f(x) across the identity line y=xy = x.

  • If ordered pair (a,b)(a, b) lies on the graph of f(x)f(x), then the reversed ordered pair (b,a)(b, a) must lie on the graph of f1(x)f^{-1}(x).
  • Any points of intersection between f(x)f(x) and f1(x)f^{-1}(x) must lie directly along the line of symmetry y=xy = x.
Test Your Knowledge

What is the inverse function f^(-1)(x) for the rational function f(x) = (2x + 5) / (x - 3)?

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Test Your Knowledge

If f(x) and g(x) are inverse functions, which of the following statements MUST be true?

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Test Your Knowledge

The function f(x) = sqrt(x - 3) + 4 has domain [3, ∞) and range [4, ∞). What is the domain of f^(-1)(x)?

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Test Your Knowledge

What is the inverse function f^(-1)(x) for the domain-restricted quadratic function f(x) = (x - 4)^2 + 1 for x >= 4?

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