13.2 Molar Solutions, Normality & Buffer Preparation

Key Takeaways

  • Grams of solute for a molar solution equals molarity multiplied by formula weight multiplied by volume in litres.
  • Hydrated salts must be weighed using the formula weight that includes the waters of crystallization, or the buffer will be under-concentrated.
  • Normality equals molarity multiplied by the number of reactive equivalents, so 1 M sulfuric acid is 2 N while 1 M sodium hydroxide is 1 N.
  • The molarity of a concentrated acid equals ten times its percent purity times its density, divided by its formula weight; concentrated hydrochloric acid is approximately 12 M.
  • pH meters are calibrated with at least two standard buffers that bracket the expected sample pH, and the electrode is stored in its manufacturer-specified storage solution rather than distilled water.
Last updated: September 2026

13.2 Molar Solutions, Normality & Buffer Preparation

ASCP HT Exam Focus: Molar solutions is a named sub-topic under Laboratory Mathematics. Molarity questions on the ASCP HT examination almost always involve either a hydrated salt or a concentrated acid, because those are the two places where a plausible-looking wrong answer is easy to construct.


Molarity

A mole is the formula weight of a substance expressed in grams. Molarity (M) is moles of solute per litre of finished solution.

Grams=M×formula weight×volume in litres\text{Grams} = M \times \text{formula weight} \times \text{volume in litres}

Worked example. Prepare 500 mL of 0.1 M citric acid (formula weight 192.12 g/mol) for a retrieval buffer:

Grams=0.1×192.12×0.500=9.61 g\text{Grams} = 0.1 \times 192.12 \times 0.500 = \mathbf{9.61\text{ g}}

Worked example. Prepare 2 L of 0.5 M sodium chloride (formula weight 58.44):

Grams=0.5×58.44×2.0=58.44 g\text{Grams} = 0.5 \times 58.44 \times 2.0 = \mathbf{58.44\text{ g}}

Millimolar (mM). Retrieval buffers are usually written in millimolar: $10\text{ mM} = 0.010\text{ M}$. A 10 mM citrate buffer is therefore one hundredth the mass of a 1 M solution.


Waters of Hydration

Many laboratory salts are supplied as hydrates, and the water is part of the mass you weigh.

SaltAnhydrous FWHydrated formHydrated FW
Sodium phosphate dibasic141.96$\text{Na}_2\text{HPO}_4 \cdot 7\text{H}_2\text{O}$268.07
Sodium citrate258.07$\text{Na}_3\text{C}_6\text{H}_5\text{O}_7 \cdot 2\text{H}_2\text{O}$294.10
Copper sulfate159.61$\text{CuSO}_4 \cdot 5\text{H}_2\text{O}$249.68
EDTA disodium336.21$\text{Na}_2\text{EDTA} \cdot 2\text{H}_2\text{O}$372.24

Worked example. Prepare 1 L of 10 mM sodium citrate buffer using the dihydrate:

Grams=0.010×294.10×1.0=2.94 g\text{Grams} = 0.010 \times 294.10 \times 1.0 = \mathbf{2.94\text{ g}}

Using the anhydrous formula weight by mistake would give 2.58 g - a buffer roughly 12 percent weak, which in a heat-induced epitope retrieval protocol shows up as weak, patchy immunostaining.

Rule: read the label, not the name. If the bottle says "dihydrate", use the dihydrate formula weight printed on that label.


Normality and Equivalents

Normality (N) is equivalents of solute per litre. An equivalent is the amount of substance that supplies one mole of reactive units - one mole of $\text{H}^{+}$ for an acid, one mole of $\text{OH}^{-}$ for a base, or one mole of charge for a salt.

N=M×number of equivalentsEquivalent weight=formula weightnumber of equivalentsN = M \times \text{number of equivalents} \qquad \text{Equivalent weight} = \frac{\text{formula weight}}{\text{number of equivalents}}

ReagentEquivalentsRelationship
HCl11 M = 1 N
NaOH11 M = 1 N
$\text{H}_2\text{SO}_4$21 M = 2 N
$\text{Ca}(\text{OH})_2$21 M = 2 N

Worked example. Prepare 500 mL of 1 N sulfuric acid from the solid-equivalent calculation: the equivalent weight is $98.08 / 2 = 49.04$, so $1 \times 49.04 \times 0.500 = \mathbf{24.52\text{ g}}$ of equivalent mass, delivered in practice by diluting the concentrated acid.


Converting a Concentrated Acid to Molarity

Concentrated reagents are labelled as percent weight/weight with a density, not as molarity. The conversion is:

M=10×% (w/w)×density in g/mLformula weightM = \frac{10 \times \%\ (\text{w/w}) \times \text{density in g/mL}}{\text{formula weight}}

Concentrated reagentPercent (w/w)DensityFormula weightApproximate molarity
Hydrochloric acid371.1936.4612.1 M
Sulfuric acid961.8498.0818.0 M
Nitric acid701.4263.0115.8 M
Glacial acetic acid99.71.0560.0517.4 M
Ammonium hydroxide280.9035.057.2 M

Worked example. Prepare 1 L of 1 M hydrochloric acid from the concentrated reagent: $V_1 = (1 \times 1000)/12.1 = \mathbf{82.6\text{ mL}}$ of concentrated HCl added slowly to roughly 900 mL of water, then brought to 1 L. Acid is always added to water, because the heat of dilution released at the interface can flash-boil water added to acid.


Buffers That Histology Actually Prepares

BufferCompositionpHUse
Citrate10 mM sodium citrate6.0Standard heat-induced epitope retrieval
Tris-EDTA10 mM Tris base with 1 mM EDTA9.0High-pH retrieval for nuclear hormone receptors
Phosphate-buffered saline (PBS)Sodium phosphate with sodium chloride7.2 to 7.4Antibody diluent and wash buffer
Neutral buffered formalinSodium phosphate monobasic and dibasic6.8 to 7.2Routine fixative
Scott tap water substituteMagnesium sulfate with sodium bicarbonateapproximately 8.0Bluing hematoxylin

A buffer resists pH change because it contains a weak acid and its conjugate base in equilibrium, described by the Henderson-Hasselbalch relationship:

pH=pKa+log[conjugate base][weak acid]\text{pH} = \text{p}K_a + \log\frac{[\text{conjugate base}]}{[\text{weak acid}]}

Buffering capacity is greatest when the two species are roughly equal, which is one pH unit either side of the $\text{p}K_a$. A buffer used far from its $\text{p}K_a$ drifts, which is why citrate is used near pH 6 and Tris near pH 8 to 9 rather than interchangeably.


pH Meter Calibration

  • Calibrate with at least two standard buffers that bracket the expected sample pH - typically pH 7.00 with pH 4.01 for acidic work, or pH 7.00 with pH 10.01 for alkaline retrieval buffers.
  • Verify the electrode slope falls within the manufacturer's acceptance range; a drifting or out-of-slope electrode is a replacement item, not a recalibration item.
  • Use temperature compensation, because electrode response and buffer pH both change with temperature. Measure standards and samples at the same temperature.
  • Store the electrode in the manufacturer-specified storage solution (commonly potassium chloride), never in distilled water, which leaches ions out of the junction.
  • Rinse with deionized water between measurements and blot rather than wipe, to avoid static charge on the bulb.
  • Document calibration in the instrument log with the standards used, lot numbers, and the technologist's initials.
Test Your Knowledge

A technician must prepare 1 L of 10 mM sodium citrate retrieval buffer and has sodium citrate dihydrate, formula weight 294.10, on the shelf. How many grams are weighed?

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Test Your Knowledge

Concentrated hydrochloric acid is labelled 37 percent (w/w) with a density of 1.19 g/mL and a formula weight of 36.46. Approximately what volume is needed to prepare 500 mL of 1 M hydrochloric acid, and in what order are the liquids combined?

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Test Your Knowledge

A laboratory prepares 1 M sulfuric acid and labels the bottle '1 N sulfuric acid.' Why is this label incorrect?

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