6.2 T-Scores, Z-Scores, and Reference Database Selection

Key Takeaways

  • T-score equals patient BMD minus the young-adult reference mean, divided by the young-adult reference standard deviation.
  • Z-score equals patient BMD minus the age-matched reference mean, divided by the age-matched reference standard deviation.
  • T-scores are used for diagnosis in postmenopausal women and men age 50 and older; Z-scores are used for premenopausal women, men under 50, and children and adolescents.
  • A Z-score of -2.0 or lower is reported as below the expected range for age, and a Z-score above -2.0 is within the expected range for age.
  • ISCD directs that diagnostic classification use the lowest of the PA lumbar spine, femoral neck, and total hip, and that Ward's area and the trochanter alone must not be used for diagnosis.
Last updated: September 2026

6.2 T-Scores, Z-Scores, and Reference Database Selection

Quick Answer: Both scores express a patient's BMD in standard deviations, and they differ only in what they compare against. The T-score uses a young-adult reference mean and SD; the Z-score uses an age-matched reference. T-scores drive WHO diagnostic classification in postmenopausal women and men 50 and older. Z-scores are the correct score for premenopausal women, men under 50, and children — where a value of −2.0 or lower is reported as "below the expected range for age."

The Two Formulas

T-score=Patient BMDYoung-Adult Mean BMDYoung-Adult SD\text{T-score} = \frac{\text{Patient BMD} - \text{Young-Adult Mean BMD}}{\text{Young-Adult SD}}

Z-score=Patient BMDAge-Matched Mean BMDAge-Matched SD\text{Z-score} = \frac{\text{Patient BMD} - \text{Age-Matched Mean BMD}}{\text{Age-Matched SD}}

The numerator is the patient's distance from the reference center. The denominator converts that distance into standard-deviation units so that values from different sites and different scanners are expressed on a common scale.

Worked Example

A 62-year-old woman has a femoral neck BMD of 0.652 g/cm². The reference database gives a young-adult mean of 0.858 g/cm² with SD 0.120, and an age-matched mean for 62-year-old women of 0.736 g/cm² with SD 0.118.

T-score=0.6520.8580.120=0.2060.120=1.72\text{T-score} = \frac{0.652 - 0.858}{0.120} = \frac{-0.206}{0.120} = -1.72

Z-score=0.6520.7360.118=0.0840.118=0.71\text{Z-score} = \frac{0.652 - 0.736}{0.118} = \frac{-0.084}{0.118} = -0.71

Both numbers describe the same bone. The T-score of −1.7 places her in the osteopenic range against young adults; the Z-score of −0.7 says she is close to typical for her age. Nothing is contradictory — age-related bone loss is normal, and "normal for 62" is still a level of bone mass associated with fracture risk. That is precisely why the T-score, not the Z-score, drives diagnosis in this population.

Which Score for Which Patient

Patient groupScore usedReason
Postmenopausal womenT-scoreWHO diagnostic criteria are defined against a young-adult reference
Men age 50 and olderT-scoreWHO criteria extended to this group
Premenopausal womenZ-scorePeak bone mass may not be attained; WHO criteria were not derived for this group
Men younger than 50Z-scoreSame rationale
Children and adolescentsZ-scoreSkeleton is still growing; areal BMD is confounded by body size
Women in the menopausal transitionClinical judgment; Z-score generally preferred until postmenopausalReference selection depends on menopausal status rather than age alone

Reporting Z-Scores

The ISCD terminology is specific and appears on exams verbatim:

  • Z-score of −2.0 or lower: report as "below the expected range for age."
  • Z-score above −2.0: report as "within the expected range for age."

Notice what is absent: the words osteoporosis and osteopenia. Those terms belong to WHO T-score classification and are not applied on the basis of a Z-score. A premenopausal woman with a Z-score of −2.4 is not "osteoporotic" on densitometry alone; she has bone mass below the expected range for her age, which prompts a search for a secondary cause. Diagnosing osteoporosis in that patient requires clinical criteria such as a fragility fracture or a documented secondary cause.

A low Z-score at any age is a signal to investigate secondary causes — hyperparathyroidism, malabsorption, hypogonadism, glucocorticoid exposure, myeloma — because it means the patient has lost more bone than her age explains.

Reference Database Selection

The reference database is the hidden variable in every score. Change it and the T-score changes while the measured BMD does not.

  • Femoral neck and total hip: the NHANES III database is the accepted reference standard in the United States, and ISCD recommends a uniform Caucasian (non-race-adjusted) female reference for computing T-scores at these sites in both women and men.
  • Lumbar spine: manufacturers supply their own young-adult reference data, which is one reason spine T-scores are less standardized across systems than hip T-scores.
  • Sex-matching for men: ISCD's United States position applies a white female reference for hip T-scores in men. Some manufacturers offer male reference options; consistency within a facility matters more than the choice, and the reference used should be stated in the report.
  • Software and database updates change T-scores without any change in the patient. This is a core reason serial comparison uses absolute BMD in g/cm², never T-scores.

The practical technologist rules are short: enter demographics accurately, apply the facility's chosen reference database consistently, and never silently switch reference options between a baseline and a follow-up study.

Which Sites Are Used for Diagnosis

Not every region the software reports is diagnostically valid. ISCD guidance:

Site or regionUse for WHO diagnostic classification
PA lumbar spine (L1–L4)Yes
Femoral neckYes
Total hipYes
33% (one-third) radiusYes, when the spine or hip cannot be measured or interpreted, in hyperparathyroidism, or in very obese patients above the table weight limit
Ward's areaNo — never used for diagnosis
Trochanter aloneNo
Lateral spineNo
Total bodyNo
Calcaneus and other peripheral sitesNo

The lowest of the valid sites governs classification. If the PA spine gives −1.8, the femoral neck −2.6, and the total hip −2.3, the diagnostic T-score is −2.6 and the classification is osteoporosis.

Ward's area deserves its own note because it is the trap. It is a small, low-density triangular region defined by the intersection of trabecular bundles in the femoral neck. It reliably produces the lowest T-score on the report and it has poor precision, so using it would over-diagnose osteoporosis and would monitor poorly. The software displays it; the report does not classify from it.

Percent of Young Adult and Percent of Age-Matched

Some reports also show percent-of-reference values:

Percent of young adult=Patient BMDYoung-Adult Mean×100\text{Percent of young adult} = \frac{\text{Patient BMD}}{\text{Young-Adult Mean}} \times 100

In the worked example above, $0.652 \div 0.858 \times 100 = 76%$ of the young-adult mean. These percentages are descriptive only. Diagnostic classification uses the T-score, not the percentage, because a given percentage corresponds to different numbers of standard deviations at different sites depending on the reference SD.

Common Errors

  • Applying a T-score to a 34-year-old woman and calling her osteopenic.
  • Using the Z-score to diagnose osteoporosis in a 70-year-old — her Z-score may be normal precisely because her peers have also lost bone.
  • Classifying from Ward's area because it produced the lowest number.
  • Comparing T-scores between a baseline and a follow-up after a software or database update.
  • Averaging T-scores across sites rather than taking the lowest.
Test Your Knowledge

A 34-year-old premenopausal woman has a lumbar spine T-score of -2.6 and a Z-score of -2.3. How should this be reported?

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Test Your Knowledge

A report shows PA spine -1.8, femoral neck -2.6, total hip -2.3, and Ward's area -3.4. What T-score governs diagnostic classification?

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Test Your Knowledge

A woman's femoral neck BMD is 0.652 g/cm-squared. The young-adult reference mean is 0.858 with an SD of 0.120. What is her T-score?

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