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100+ Free C&G 2365-03 Level 3 Practice Questions

City & Guilds 2365-03 Level 3 Diploma in Electrical Installations (Buildings & Structures) practice questions are available now; exam metadata is being verified.

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2026 Statistics

Key Facts: C&G 2365-03 Level 3 Exam

100

Practice Questions

OpenExamPrep

Level 3

Advanced Diploma

City & Guilds

Multiple

e-volve Unit Exams

City & Guilds

~60%

Typical MCQ Pass Mark

City & Guilds

BS 7671

Wiring Regulations Applied

IET/BSI

6 units

Knowledge Areas

City & Guilds 2365-03

The City & Guilds 2365-03 Level 3 Diploma in Electrical Installations (Buildings & Structures) is the advanced underpinning-knowledge qualification for UK electricians, building on the Level 2 (2365-02) Diploma. It is assessed through several City & Guilds e-volve online multiple-choice unit exams (Units 301, 303, 304 and 305, typically 27-60 questions each with around 60% to pass), alongside written papers, a design assignment and practical assessments, rather than one single exam. Content covers advanced electrical principles and science (AC theory, transformers, motors and power factor), electrical systems design to BS 7671 (cable calculations, correction factors, the adiabatic equation, Zs and protective devices), inspection, testing and commissioning, fault diagnosis and rectification, environmental technology systems, and the electrotechnical industry. This free prep includes 100 research-based practice questions with explanations and an AI tutor.

Sample C&G 2365-03 Level 3 Practice Questions

Try these sample questions to test your C&G 2365-03 Level 3 exam readiness. Each question includes a detailed explanation. Start the interactive quiz above for the full 100+ question experience with AI tutoring.

1A single-phase transformer has 800 primary turns and 200 secondary turns. If the primary is supplied at 230 V, what is the approximate secondary voltage?
A.920 V
B.57.5 V
C.115 V
D.460 V
Explanation: For an ideal transformer, Vp/Vs = Np/Ns. So Vs = Vp x (Ns/Np) = 230 x (200/800) = 230 x 0.25 = 57.5 V. With fewer secondary turns the transformer steps the voltage down.
2A four-pole three-phase induction motor is supplied at 50 Hz. What is its synchronous speed?
A.1000 rev/min
B.1500 rev/min
C.3000 rev/min
D.750 rev/min
Explanation: Synchronous speed Ns = (120 x f) / p, where p is the number of poles. Ns = (120 x 50) / 4 = 6000 / 4 = 1500 rev/min. The rotor runs slightly below this due to slip.
3An induction motor has a synchronous speed of 1500 rev/min and runs at a full-load speed of 1440 rev/min. What is the percentage slip?
A.6%
B.4%
C.2%
D.10%
Explanation: Slip = ((Ns - Nr) / Ns) x 100 = ((1500 - 1440) / 1500) x 100 = (60 / 1500) x 100 = 4%. Typical full-load slip for a standard induction motor is in the 3-5% region.
4In a purely inductive AC circuit, what is the phase relationship between current and voltage?
A.Current and voltage are in phase
B.Current lags the voltage by 90 degrees
C.Current leads the voltage by 90 degrees
D.Current lags the voltage by 45 degrees
Explanation: In a purely inductive circuit the current lags the applied voltage by 90 degrees because the inductor opposes the change in current. The memory aid CIVIL gives 'in an Inductor, current (I) lags voltage (V)'.
5A coil has a resistance of 6 ohms and an inductive reactance of 8 ohms. What is its impedance?
A.14 ohms
B.10 ohms
C.2 ohms
D.48 ohms
Explanation: In a series R-L circuit, impedance Z = square root of (R squared + XL squared) = square root of (6^2 + 8^2) = square root of (36 + 64) = square root of 100 = 10 ohms. R, XL and Z form a right-angled impedance triangle.
6For the circuit with R = 6 ohms and Z = 10 ohms, what is the power factor?
A.0.8 lagging
B.0.6 lagging
C.1.0
D.0.6 leading
Explanation: Power factor = cos(phi) = R / Z = 6 / 10 = 0.6. Because the circuit is inductive (R-L), the power factor is lagging as the current lags the voltage.
7Why is a low (poor) power factor undesirable for an industrial consumer?
A.It increases the supply voltage
B.It increases the current drawn for a given real power, raising losses and demand charges
C.It reduces the kVA rating required
D.It improves the efficiency of transformers
Explanation: For a given real power (kW), a lower power factor means a higher apparent power (kVA) and therefore a higher current. This increases I-squared-R cable losses, requires larger conductors and switchgear, and often attracts reactive-power demand charges from the supplier.
8Which component is normally connected in parallel with an inductive load to correct a lagging power factor?
A.A series inductor
B.A capacitor
C.An additional resistor
D.A step-up transformer
Explanation: A capacitor draws a leading current that cancels part of the lagging reactive current of the inductive load, raising the overall power factor toward unity. Capacitor banks are the standard means of power-factor correction.
9A three-phase balanced load draws a line current of 20 A at 400 V line voltage with a power factor of 0.85. What is the approximate real power consumed?
A.11.8 kW
B.13.9 kW
C.6.8 kW
D.8.0 kW
Explanation: For a balanced three-phase load, P = square root of 3 x VL x IL x cos(phi) = 1.732 x 400 x 20 x 0.85 = approximately 11 778 W, or about 11.8 kW. The square root of 3 factor links line and phase quantities in a three-phase system.
10In a star (wye) connected three-phase system, how does the line voltage relate to the phase voltage?
A.Line voltage equals phase voltage
B.Line voltage equals square root of 3 times the phase voltage
C.Line voltage equals 3 times the phase voltage
D.Line voltage equals phase voltage divided by square root of 3
Explanation: In a star connection, VL = square root of 3 x Vph, while the line current equals the phase current. This is why a 230 V phase voltage gives a 400 V line voltage (230 x 1.732 = 400).

About the C&G 2365-03 Level 3 Practice Questions

Verified exam format metadata for City & Guilds 2365-03 Level 3 Diploma in Electrical Installations (Buildings & Structures) is pending. The practice questions above remain available while official exam length, timing, passing score, fee, and administrator details are reviewed.