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100+ Free VWO Wiskunde C Practice Questions

Netherlands VWO Wiskunde C — Centraal Examen and Schoolexamen practice questions are available now; exam metadata is being verified.

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2026 Statistics

Key Facts: VWO Wiskunde C Exam

3 Hours

Centraal Examen written paper duration

Examenblad.nl 2026

5 Domains

Algebra, growth, probability, statistics, and spatial perspective

CvTE Syllabus

100 MCQs

English practice items aligned to VWO syllabus

OpenExamPrep

1–10 Scale

Dutch grading scale; pass threshold average ≥ 5.5

Dutch Secondary Education Act

CE + SE

Combined national exam (50%) and school exam (50%)

CvTE Regulations

Graphic Calc

Allowed in exam mode alongside standard drawing tools

Examenblad.nl Regulations

Humanities

Tailored for Cultuur & Maatschappij VWO pathway

SLO Wiskunde C

Free

No separate fee for regular secondary candidates

Examenblad.nl

Official VWO Wiskunde C 2026 is CE (3-hour written exam) plus school SE. These 100 English MCQs provide mathematical calculation and geometric practice aligned to CvTE VWO Wiskunde C subdomains.

Sample VWO Wiskunde C Practice Questions

Try these sample questions to test your VWO Wiskunde C exam readiness. Each question includes a detailed explanation. Start the interactive quiz above for the full 100+ question experience with AI tutoring.

1Solve the linear equation for x: 4(2x - 3) = 5x + 9.
A.x = 5
B.x = 7
C.x = 9
D.x = 21
Explanation: Expand the left side: 8x - 12 = 5x + 9. Subtract 5x from both sides: 3x - 12 = 9. Add 12 to both sides: 3x = 21. Divide by 3: x = 7.
2Find the solutions to the quadratic equation: x^2 - 7x + 12 = 0.
A.x = 3 and x = 4
B.x = -3 and x = -4
C.x = 2 and x = 6
D.x = 1 and x = 12
Explanation: Factor the quadratic expression: x^2 - 7x + 12 = (x - 3)(x - 4) = 0. Setting each factor to zero yields x - 3 = 0 or x - 4 = 0, so x = 3 or x = 4.
3Rearrange the perimeter formula P = 2L + 2W to make W the subject.
A.W = (P - 2L) / 2
B.W = P - L
C.W = (P + 2L) / 2
D.W = 2P - 2L
Explanation: Start with P = 2L + 2W. Subtract 2L from both sides: P - 2L = 2W. Divide both sides by 2: W = (P - 2L) / 2.
4Simplify the expression: (3x^2 y^3)^2 / (9x^3 y).
A.x y^5
B.x^2 y^5
C.3x y^4
D.y^5 / x
Explanation: Square the numerator: (3x^2 y^3)^2 = 9 x^4 y^6. Divide by denominator: (9 x^4 y^6) / (9 x^3 y) = (9/9) * x^(4-3) * y^(6-1) = 1 * x^1 * y^5 = x y^5.
5Given the power formula y = 5 * x^1.5, calculate y when x = 4.
A.20
B.30
C.40
D.80
Explanation: Calculate x^1.5: 4^1.5 = (4^0.5)^3 = 2^3 = 8. Multiply by 5: y = 5 * 8 = 40.
6Evaluate the logarithm: ^2log(32).
A.4
B.5
C.6
D.16
Explanation: By definition, ^2log(32) is the power to which 2 must be raised to equal 32. Since 2^5 = 32, ^2log(32) = 5.
7Solve the logarithmic equation for x: log(x) + log(x - 3) = 1 (base 10).
A.x = 5
B.x = -2
C.x = 5 and x = -2
D.x = 10
Explanation: Combine logarithms: log(x(x - 3)) = 1. Convert to exponential form: x(x - 3) = 10^1 = 10. Expand: x^2 - 3x - 10 = 0. Factor: (x - 5)(x + 2) = 0, giving x = 5 or x = -2. Since log(x) requires x > 0, the only valid solution is x = 5.
8Solve the system of equations: 3x + 2y = 18 and 2x - y = 5.
A.x = 3, y = 1
B.x = 4, y = 3
C.x = 5, y = 5
D.x = 2, y = 6
Explanation: From the second equation, isolate y: y = 2x - 5. Substitute into the first equation: 3x + 2(2x - 5) = 18 => 3x + 4x - 10 = 18 => 7x = 28 => x = 4. Then y = 2(4) - 5 = 3.
9A parabola has vertex form y = 2(x - 3)^2 + 5. What is y when x = 1?
A.9
B.13
C.17
D.21
Explanation: Substitute x = 1 into the formula: y = 2(1 - 3)^2 + 5 = 2(-2)^2 + 5 = 2(4) + 5 = 8 + 5 = 13.
10For the rational function y = (3x + 6) / (x - 2), find the value of y when x = 4.
A.6
B.9
C.12
D.18
Explanation: Substitute x = 4 into the numerator and denominator: Numerator = 3(4) + 6 = 12 + 6 = 18. Denominator = 4 - 2 = 2. So y = 18 / 2 = 9.

About the VWO Wiskunde C Practice Questions

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