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2026 Statistics
Key Facts: VWO Bewegen, sport en maatschappij Exam
100
English Practice MCQs
OpenExamPrep Adaptation
SE Only
Assessment Mode
CvTE / Examenblad.nl
1–10
Dutch Grading Scale
Secondary Education Act (WVO)
≥ 5.5
Subject Passing Grade
CvTE Standard
5 Domains
Curriculum Framework
SLO / KVLO Core Specs
140–200 hrs
Estimated Study Hours
VWO Curriculum Guideline
VWO 4–6
Secondary School Level
Dutch Pre-University Track
PTA
School Assessment Plan
School-Based Testing
Official VWO BSM is a school-based SE subject combining physical performance and theoretical science. These 100 English MCQs provide practice on sports physiology, movement theory, and sports management.
Sample VWO Bewegen, sport en maatschappij Practice Questions
Try these sample questions to test your VWO Bewegen, sport en maatschappij exam readiness. Each question includes a detailed explanation. Start the interactive quiz above for the full 100+ question experience with AI tutoring.
1Which class of lever is represented when nodding the head, where the fulcrum (atlanto-occipital joint) lies between the effort force (neck extensor muscles) and the resistance load (weight of the head)?
A.First-class lever
B.Second-class lever
C.Third-class lever
D.Fourth-class lever
Explanation: A first-class lever has its fulcrum (axis) located between the effort force and the load/resistance (Force-Axis-Resistance). Nodding the head is a classic anatomical example: the atlanto-occipital joint acts as the axis, the neck extensor muscles apply effort posteriorly, and the weight of the anterior skull acts as the resistance.
2During a standing calf raise, the ball of the foot acts as the fulcrum, the body weight through the ankle acts as the load, and the gastrocnemius contraction acts as the effort. Which lever class does this movement demonstrate?
A.First-class lever
B.Second-class lever
C.Third-class lever
D.Fourth-class lever
Explanation: A second-class lever positions the load/resistance between the fulcrum (axis) and the effort force (Axis-Resistance-Force). In a calf raise, the metatarsophalangeal joints act as the axis, body weight applied through the talus is the resistance, and the Achilles tendon pulls upward as the effort, providing a mechanical advantage greater than 1.
3Why are most muscle-joint systems in the human body (such as the biceps brachii during a elbow flexion forearm curl) classified as third-class levers?
A.Because the load is positioned directly between the fulcrum and the effort
B.Because the effort is applied between the fulcrum and the load, prioritizing range of motion and speed over force production
C.Because third-class levers always provide a mechanical advantage greater than 1
D.Because the axis of rotation moves continuously along the lever arm
Explanation: Third-class levers have the effort force applied between the fulcrum (joint axis) and the resistance load (Axis-Force-Resistance). Because the effort arm is shorter than the resistance arm, mechanical advantage is less than 1. This anatomical trade-off requires greater muscle force output but allows large range of motion and high speed of movement at the distal end of the limb.
4A musculoskeletal lever system has an effort arm of 4 cm and a resistance arm of 20 cm. What is the mechanical advantage (MA) of this system, and what does it imply?
A.MA = 5; muscle force required is less than the resistance load
B.MA = 0.2; muscle force required is greater than the resistance load, but movement speed at the distal end is amplified
C.MA = 1.6; muscle force and resistance load are balanced equally
D.MA = 80; the system operates as a second-class lever
Explanation: Mechanical advantage is calculated as Effort Arm divided by Resistance Arm ($MA = d_e / d_r$). Here, $MA = 4 / 20 = 0.2$. An $MA < 1$ signifies a mechanical disadvantage in force production (the muscle must exert $5\ imes$ more force than the load), but it enables rapid velocity and large displacement at the resistance end.
5Which of Newton's Laws of Motion explains why a speed skater continues gliding forward across smooth ice even after stopping active pushing, until external forces like friction and air resistance bring them to a halt?
A.Newton's First Law (Law of Inertia)
B.Newton's Second Law (Law of Acceleration)
C.Newton's Third Law (Law of Action-Reaction)
D.Newton's Law of Universal Gravitation
Explanation: Newton's First Law states that an object at rest remains at rest, and an object in motion continues moving at a constant velocity in a straight line unless acted upon by a net external force. In speed skating, the athlete's inertia maintains forward motion across the low-friction surface until external resistive forces decelerate them.
6If two shot putters exert the exact same net force on a shot put, but Athlete A uses a 4 kg shot put while Athlete B uses a 7.26 kg shot put, what will happen according to Newton's Second Law ($F = ma$)?
A.Both shot puts will accelerate at the exact same rate
B.The 4 kg shot put will experience greater acceleration because mass is inversely proportional to acceleration for a given force
C.The 7.26 kg shot put will experience greater acceleration because heavier objects store more kinetic energy
D.Neither shot put will move unless force exceeds the coefficient of restitution
Explanation: Newton's Second Law dictates that acceleration is directly proportional to net force and inversely proportional to mass ($a = F / m$). With equal force, the lighter 4 kg shot put will experience higher acceleration than the heavier 7.26 kg shot put.
7When a sprinter explodes out of the starting blocks, they push backward and downward against the blocks. How does Newton's Third Law apply to this interaction?
A.The starting blocks absorb all force without returning any impulse to the runner
B.The starting blocks exert an equal and opposite reaction force forward and upward on the runner's feet, propelling them forward
C.The athlete's forward momentum is generated entirely by internal muscular forces independent of external contact surfaces
D.The reaction force acts perpendicular to the ground regardless of the block angle
Explanation: Newton's Third Law states that for every action force, there is an equal and opposite reaction force. When the sprinter exerts a backward/downward force vector on the starting blocks, the blocks exert an equal magnitude reaction force in the forward/upward direction against the runner, providing horizontal acceleration.
8In high jump, how does the Fosbury Flop technique allow athletes to clear a crossbar higher than their physical maximum Center of Gravity (CoG) elevation?
A.By increasing total flight time through air resistance
B.By arching the back so that the Center of Gravity passes below or through the crossbar while individual body segments clear it sequentially
C.By generating additional upward velocity after leaving the ground
D.By altering the acceleration due to gravity ($g$) during airborne flight
Explanation: The Fosbury Flop bends the high jumper's body into a hyper-extended arch over the bar. Because the Center of Gravity (CoG) is the mathematical average location of total body mass, this arch positions the CoG outside the physical body, allowing the CoG to travel underneath the crossbar while each body segment clears the bar individually.
9To maximize physical stability against an opponent pushing from the front in judo or wrestling, how should an athlete adjust their stance?
A.Narrow the feet and raise the Center of Gravity
B.Widen the base of support in the direction of the force (front-to-back) and lower the Center of Gravity
C.Stand on tiptoes and lean backward away from the force
D.Keep the line of gravity outside the edge of the base of support
Explanation: Stability is maximized by widening the Base of Support (BoS) in the direction of anticipated incoming force, lowering the Center of Gravity (CoG) relative to the ground, and ensuring the Line of Gravity falls near the center of the base of support.
10Theoretical projectile motion equations show that a 45° launch angle achieves maximum horizontal range on flat ground. Why do elite shot putters release the shot at a lower angle (around 35° to 38°)?
A.Because shot puts are aerodynamic and experience lift forces at lower angles
B.Because the release height is above the ground level and human muscles can generate greater velocity at flatter release angles
C.Because gravity acts horizontally on objects heavier than 5 kg
D.Because release angle is inversely proportional to initial launch velocity
Explanation: When release height is higher than landing height (as in shot put where the ball leaves the hand ~2 meters above the ground), the optimal launch angle for maximum horizontal distance drops below 45°. Furthermore, human shoulder biomechanics allow athletes to exert higher force and velocity at angles around 35°–38°.
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