100+ Free UPPSC AE Mechanical Practice Questions

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2026 Statistics

Key Facts: UPPSC AE Mechanical Exam

250 MCQs

Total number of multiple-choice questions across Paper 1 and Paper 2

UPPSC Combined State Engineering Services Notification

5 hours

Total written exam duration (2.5 hours per paper)

UPPSC AE Exam Pattern

-1 mark

Negative marking penalty for each incorrect response (one-third penalty)

UPPSC Marking Scheme

₹125 / ₹65

Application fee for Gen/OBC/EWS and SC/ST respectively

UPPSC AE Recruitment Details

21 - 40 Years

Standard age limit for general category candidates

UPPSC Age Eligibility

40% / 35%

Minimum qualifying percentage for Gen/OBC and SC/ST respectively

UPPSC Efficiency Standard

UPPSC AE Mechanical is a recruitment exam comprising two written objective papers (750 marks total, 125 MCQs each) and an interview (100 marks). Scoring awards +3 marks and penalizes -1 mark. Registration fee is ₹125 for Gen/OBC and ₹65 for SC/ST.

Sample UPPSC AE Mechanical Practice Questions

Try these sample questions to test your UPPSC AE Mechanical exam readiness. Each question includes a detailed explanation. Start the interactive quiz above for the full 100+ question experience with AI tutoring.

1A steel bar of 20 mm diameter and 2 m length is subjected to an axial tensile load of 50 kN. If the Young's modulus of steel is 200 GPa, what is the elongation of the bar?

A.1.59 mm

B.0.796 mm

C.3.18 mm

D.0.398 mm

Explanation: Elongation is calculated using the formula delta = PL / AE. The cross-sectional area A = (pi/4) * d^2 = (pi/4) * (0.02)^2 = 3.1416 * 10^-4 m^2. P = 50,000 N, L = 2 m, and E = 200 * 10^9 Pa. Thus, delta = (50000 * 2) / (3.1416 * 10^-4 * 200 * 10^9) = 100000 / 62831853 = 0.00159 m = 1.59 mm.

2A body of mass 10 kg is placed on a rough horizontal surface with a coefficient of static friction of 0.4. If a horizontal force of 30 N is applied to the body, what is the magnitude of the frictional force acting on it? (Take g = 10 m/s²)

A.40 N

B.30 N

C.10 N

D.0 N

Explanation: The maximum static frictional force (limiting friction) is f_max = mu_s * R = mu_s * m * g = 0.4 * 10 * 10 = 40 N. Since the applied force of 30 N is less than the limiting friction of 40 N, the body remains at rest, and the actual frictional force acting on it is equal to the applied force, which is 30 N.

3A cantilever beam of length L carries a concentrated load W at its free end. If the flexural rigidity of the beam is EI, what is the maximum deflection of the beam?

A.WL³ / 3EI

B.WL³ / 8EI

C.WL³ / 48EI

D.WL³ / 2EI

Explanation: For a cantilever beam with a point load W at the free end, the maximum deflection occurs at the free end and is given by delta = WL^3 / (3EI) according to standard deflection formulas derived from Euler-Bernoulli beam theory.

4A solid circular shaft of diameter D is subjected to a torque T. What is the maximum shear stress induced in the shaft?

A.16T / (pi * D³)

B.32T / (pi * D³)

C.64T / (pi * D³)

D.8T / (pi * D³)

Explanation: From the torsion equation T/J = tau/r, the maximum shear stress occurs at the outer surface (r = D/2). The polar moment of inertia for a solid shaft is J = (pi/32) * D^4. Therefore, tau_max = T * (D/2) / [(pi/32) * D^4] = 16T / (pi * D^3).

5At a point in a strained material, the principal stresses are sigma_x = 80 MPa (tensile) and sigma_y = 20 MPa (compressive). What is the maximum shear stress at this point?

A.50 MPa

B.30 MPa

C.100 MPa

D.40 MPa

Explanation: The maximum shear stress in a two-dimensional stress state is given by tau_max = (sigma_1 - sigma_2) / 2. Here, the principal stresses are sigma_1 = 80 MPa and sigma_2 = -20 MPa (since it is compressive). Thus, tau_max = [80 - (-20)] / 2 = 100 / 2 = 50 MPa.

6A column of length L has both ends pinned. If the critical buckling load is P, what will be the critical buckling load if both ends are fixed?

A.P / 4

B.2P

C.4P

D.16P

Explanation: The Euler buckling load is given by P_cr = (pi^2 * EI) / L_e^2. For pinned-pinned ends, the effective length L_e = L, so P = (pi^2 * EI) / L^2. For fixed-fixed ends, the effective length is L_e = L / 2. Thus, the buckling load becomes P_new = (pi^2 * EI) / (L/2)^2 = 4 * (pi^2 * EI) / L^2 = 4P.

7A thin cylindrical pressure vessel of internal diameter d and thickness t is subjected to an internal pressure p. What is the ratio of hoop stress to longitudinal stress in the cylinder wall?

A.1:2

B.2:1

C.1:1

D.4:1

Explanation: The hoop (circumferential) stress is sigma_h = pd / 2t and the longitudinal stress is sigma_l = pd / 4t. The ratio is sigma_h / sigma_l = (pd / 2t) / (pd / 4t) = 2. Therefore, the ratio of hoop stress to longitudinal stress is 2:1.

8A simply supported beam of span 6 m carries a uniformly distributed load of 10 kN/m over its entire length. What is the maximum bending moment in the beam?

A.45 kNm

B.90 kNm

C.30 kNm

D.60 kNm

Explanation: For a simply supported beam with a uniformly distributed load w over a span L, the maximum bending moment occurs at the center and is given by M_max = wL^2 / 8. Here, w = 10 kN/m and L = 6 m. Thus, M_max = 10 * 6^2 / 8 = 360 / 8 = 45 kNm.

9A pin-jointed truss is shown in a diagram where three members meet at a joint. If two of the members are collinear and no external load acts on the joint, what is the force in the third, non-collinear member?

A.Equal to the force in one of the collinear members

B.Zero

C.Equal to the sum of the forces in the collinear members

D.Dependent on the angle of the third member

Explanation: According to the principles of truss analysis, if three members meet at a joint where two of the members are collinear and there is no external force or support reaction acting at the joint, the third non-collinear member must be a zero-force member to satisfy equilibrium perpendicular to the collinear members.

10A rectangular bar of width b, depth d, and length L is subjected to an axial tensile force P. If the Poisson's ratio of the material is v, what is the volumetric strain (e_v) of the bar in terms of longitudinal strain (e)?

A.e * (1 - 2v)

B.e * (1 - v)

C.e * (1 + v)

D.2e * (1 - v)

Explanation: Volumetric strain e_v is the sum of linear strains in three perpendicular directions. For a bar under axial load, longitudinal strain is e. The lateral strains are -v*e and -v*e. Thus, e_v = e_x + e_y + e_z = e - v*e - v*e = e * (1 - 2v).

About the UPPSC AE Mechanical Exam

The UPPSC Combined State Engineering Services Assistant Engineer (Mechanical) Exam is a premier recruitment test for engineering graduates seeking Class-II gazetted officer posts under various departments of the Uttar Pradesh government. The exam comprises two written objective papers checking General Hindi, General Studies, and comprehensive Mechanical Engineering subjects, followed by an interview. This practice test bank provides 100 high-quality, syllabus-aligned technical questions covering mechanical design, thermal, fluid, and production engineering disciplines.

Assessment

The UPPSC Assistant Engineer written exam consists of two papers, each of 2.5 hours duration. Paper 1 contains 25 questions of General Hindi and 100 questions of Mechanical Engineering Paper I (total 375 marks). Paper 2 contains 25 questions of General Studies and 100 questions of Mechanical Engineering Paper II (total 375 marks). Marking scheme: +3 for correct answers, -1 for incorrect answers. Shortlisted candidates are called for a 100-mark personal interview.

Time Limit

5 hours (2.5 hours per paper)

Passing Score

Qualifying marks are 40% for General, EWS, and OBC candidates, and 35% for SC and ST candidates.

Exam Fee

₹125 for General/OBC/EWS, ₹65 for SC/ST, and ₹25 for PwBD candidates. (Uttar Pradesh Public Service Commission (UPPSC))

UPPSC AE Mechanical Exam Content Outline

15%

Engineering Mechanics & Strength of Materials

Equilibrium, trusses, stress-strain, bending, torsion, deflection of beams, thin/thick cylinders, columns.

15%

Theory of Machines & Machine Design

Planar mechanisms, cams, gears, flywheels, governors, balancing, vibration, design of joints, shafts, bearings, clutches.

15%

Fluid Mechanics & Hydraulic Machines

Fluid properties, kinematics, dynamics, boundary layer, pipe flow, dimensional analysis, pumps, turbines.

20%

Thermodynamics, Heat Transfer & RAC

First/second laws, properties of pure substances, thermodynamic cycles, conduction, convection, radiation, vapor compression and absorption refrigeration.

15%

Power Plants & IC Engines

Steam boilers, Rankine cycle, gas turbines, diesel and petrol IC engine cycles, combustion, testing and performance.

20%

Manufacturing & Industrial Engineering

Metal casting, forming, welding, machining, metrology, CNC, production planning, inventory control, linear programming, PERT/CPM.

How to Pass the UPPSC AE Mechanical Exam

What You Need to Know

Passing score: Qualifying marks are 40% for General, EWS, and OBC candidates, and 35% for SC and ST candidates.
Assessment: The UPPSC Assistant Engineer written exam consists of two papers, each of 2.5 hours duration. Paper 1 contains 25 questions of General Hindi and 100 questions of Mechanical Engineering Paper I (total 375 marks). Paper 2 contains 25 questions of General Studies and 100 questions of Mechanical Engineering Paper II (total 375 marks). Marking scheme: +3 for correct answers, -1 for incorrect answers. Shortlisted candidates are called for a 100-mark personal interview.
Time limit: 5 hours (2.5 hours per paper)
Exam fee: ₹125 for General/OBC/EWS, ₹65 for SC/ST, and ₹25 for PwBD candidates.

Keys to Passing

Complete 500+ practice questions
Score 80%+ consistently before scheduling
Focus on highest-weighted sections
Use our AI tutor for tough concepts

UPPSC AE Mechanical Study Tips from Top Performers

1Focus deeply on core technical subjects as they carry 600 out of the 750 marks in the written exam.

2Practice numerical problems in strength of materials, fluid mechanics, thermodynamics, and machine design.

3Don't ignore the General Hindi and General Studies sections, as they cover 150 marks and can significantly boost your merit rank.

4Practice previous years' questions of both UPPSC AE and UPSC Engineering Services Exam (ESE/IES) for conceptual depth.

5Develop speed and accuracy to handle 125 questions in 150 minutes, and be cautious of the -1 negative marking.

Frequently Asked Questions

What is the exam pattern for UPPSC AE Mechanical?

The written exam consists of two papers. Paper 1 has 25 questions of General Hindi and 100 questions of Mechanical Engineering Paper I. Paper 2 has 25 questions of General Studies and 100 questions of Mechanical Engineering Paper II. Each paper is of 2.5 hours duration, with each question carrying 3 marks.

Is there negative marking in the UPPSC AE exam?

Yes, there is a negative marking of 1 mark for each incorrect answer, which is equal to one-third of the weightage of a question (+3 marks).

What is the eligibility criteria for UPPSC AE Mechanical?

Candidates must have a B.E. or B.Tech degree in Mechanical Engineering from a recognized university. The age limit is 21 to 40 years, with relaxations for reserved categories of Uttar Pradesh.

What is the application fee for UPPSC AE?

The application fee is ₹125 for General/OBC/EWS candidates, ₹65 for SC/ST candidates, and ₹25 for PwBD candidates.

What are the minimum qualifying marks for UPPSC AE?

The minimum qualifying efficiency standard is 40% for General, EWS, and OBC candidates, and 35% for SC and ST candidates in the aggregate of the written exam.

100+ Free UPPSC AE Mechanical Practice Questions

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