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100+ Free Tamil Nadu HSE Second Year Physics Practice Questions

Tamil Nadu Higher Secondary Second Year (HSE +2 / Class 12) Physics under the Directorate of Government Examinations (DGE), Tamil Nadu practice questions are available now; exam metadata is being verified.

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2026 Statistics

Key Facts: Tamil Nadu HSE Second Year Physics Exam

10:00–1:15

Official March 2026 HSE+2 theory sitting window including reading/verification time (dge.tn.gov.in timetable)

DGE TN HSE+2 March 2026 public examination timetable

35/100

Minimum pass mark per subject under the HSE new pattern, subject to theory/practical floor rules

DGE HSE_E.pdf scheme of examination

3 hours

Approximate theory writing duration after reading and particulars verification in the public exam schedule

DGE TN HSE+2 March 2026 timetable

DGE TN

Administered by the Directorate of Government Examinations, Chennai, for Tamil Nadu State Board Higher Secondary

dge.tn.gov.in

SCERT syllabus

Class 12 textbooks and syllabus prescribed by SCERT / School Education Department (Samacheer Kalvi)

DGE HSE scheme — syllabus prescribed by SCERT/DSE

English MCQ bank

This practice set is an English-language MCQ study adaptation, not the official mixed written paper

OpenExamPrep practice-content policy

₹150/₹200

School exam fee band for groups without/with practical subjects plus certificate/service charges (concessions apply)

DGE HSE_E.pdf school candidate fee table

March 2026

HSE Second Year public theory examinations scheduled 2–26 March 2026 with practicals 9–14 February 2026

DGE TN official timetable PDF 04.11.2025

Free English MCQ practice for Tamil Nadu HSE +2 Physics (DGE). Official paper is mixed written theory on the Samacheer Kalvi Class 12 syllabus — this bank is a study adaptation, not a format simulation.

Sample Tamil Nadu HSE Second Year Physics Practice Questions

Try these sample questions to test your Tamil Nadu HSE Second Year Physics exam readiness. Each question includes a detailed explanation. Start the interactive quiz above for the full 100+ question experience with AI tutoring.

1According to Coulomb's law, the electrostatic force between two point charges is proportional to:
A.the product of the charges and inversely proportional to the square of the separation
B.the sum of the charges and inversely proportional to the separation
C.the product of the charges and directly proportional to the separation
D.the difference of the charges and inversely proportional to the square of the separation
Explanation: Coulomb's law states F = (1/(4πε₀))·(q₁q₂/r²). The force magnitude is proportional to the product of the charges and inversely proportional to the square of the distance between them. The force is attractive for opposite signs and repulsive for like signs.
2The SI unit of electric field intensity is:
A.N C⁻¹
B.N m
C.C m⁻²
D.J C
Explanation: Electric field E is force per unit charge, so its SI unit is newton per coulomb (N C⁻¹). Equivalently, E = −dV/dr gives the unit volt per metre (V m⁻¹), which is identical to N C⁻¹.
3Two point charges +4 µC and +9 µC are separated by 30 cm in free space. The electric field is zero at a point on the line joining them that is:
A.12 cm from the +4 µC charge (toward the +9 µC charge)
B.18 cm from the +4 µC charge (toward the +9 µC charge)
C.between them, 15 cm from each
D.outside the segment, closer to the larger charge
Explanation: For two like charges the electric field is zero between them, closer to the smaller charge. Set k(4 µC)/x² = k(9 µC)/(30−x)², so 2/x = 3/(30−x). Cross-multiplying gives 2(30−x) = 3x ⇒ 60 = 5x ⇒ x = 12 cm from the +4 µC charge.
4Gauss's law states that the net electric flux through any closed surface is equal to:
A.the enclosed charge divided by ε₀
B.the enclosed charge multiplied by ε₀
C.the surface charge density only
D.zero always, regardless of enclosed charge
Explanation: In SI units, ∮ E·dA = Q_enclosed/ε₀. The flux depends only on the net charge enclosed, not on how charges are distributed outside or on the shape of the Gaussian surface (provided it is closed).
5The electric field due to an infinite plane sheet of uniform surface charge density σ is:
A.σ/(2ε₀) and independent of distance from the sheet
B.σ/ε₀ and decreases as 1/r²
C.σ/(4πε₀) and independent of distance
D.σ/(2ε₀r) along the normal
Explanation: Using a Gaussian pillbox through an infinite sheet gives E = σ/(2ε₀) on each side, directed normal to the sheet. Magnitude does not depend on distance from an ideal infinite sheet.
6Electric potential at a point is defined as:
A.work done by an external agent per unit positive charge in bringing it slowly from infinity to that point (without KE change)
B.force per unit charge at that point
C.product of charge and electric field
D.flux of electric field through unit area
Explanation: Potential V is work per unit positive test charge by a quasi-static external agent from the reference (usually infinity) to the point. Force per unit charge is the electric field E, not V.
7The capacitance of a parallel-plate capacitor with plate area A and separation d (air-filled) is:
A.ε₀A/d
B.ε₀d/A
C.A/(ε₀d)
D.ε₀Ad
Explanation: For an ideal parallel-plate capacitor, C = ε₀A/d. Capacitance increases with area and decreases with plate separation. Inserting a dielectric of constant κ multiplies C by κ.
8Three capacitors of 2 µF, 3 µF and 6 µF are connected in series. The equivalent capacitance is:
A.1 µF
B.11 µF
C.3 µF
D.0.5 µF
Explanation: For series capacitors, 1/C_eq = 1/2 + 1/3 + 1/6 = 3/6 + 2/6 + 1/6 = 6/6 = 1, so C_eq = 1 µF. Series equivalent is always less than the smallest capacitor.
9An electric dipole of moment p is placed in a uniform electric field E. The torque on the dipole has magnitude:
A.pE sinθ
B.pE cosθ
C.pE
D.zero always because the field is uniform
Explanation: Torque τ = p × E, so |τ| = pE sinθ, where θ is the angle between p and E. Net force in a uniform field is zero, but torque is generally not zero and tends to align p with E.
10A 12 µF capacitor is charged to 100 V and then disconnected from the battery. If a dielectric of dielectric constant κ = 3 completely fills the gap, the new potential difference across the plates is:
A.100/3 V
B.300 V
C.100 V
D.33 V approximately only if connected to battery
Explanation: With battery disconnected, charge Q is constant. Inserting dielectric multiplies capacitance by κ, so V' = Q/C' = Q/(κC) = V/κ = 100/3 V. Energy stored also falls by the factor κ.

About the Tamil Nadu HSE Second Year Physics Practice Questions

Verified exam format metadata for Tamil Nadu Higher Secondary Second Year (HSE +2 / Class 12) Physics under the Directorate of Government Examinations (DGE), Tamil Nadu is pending. The practice questions above remain available while official exam length, timing, passing score, fee, and administrator details are reviewed.