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100+ Free RBSE SS Mathematics Practice Questions

Rajasthan RBSE Senior Secondary (Class 12) Mathematics — Code 015 practice questions are available now; exam metadata is being verified.

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2026 Statistics

Key Facts: RBSE SS Mathematics Exam

015

RBSE subject code for Mathematics

RBSE 2026 subject-wise statistics

Theory 80 + Sessional 20

Typical full marks / assessment pattern

RBSE syllabus examination scheme

3 h 15 m

Typical theory paper duration (where applicable)

RBSE Class 12 / Praveshika schemes

33%

Common minimum pass threshold under RBSE regulations

RBSE examination regulations (confirm circular)

2026

Main examination cycle evidenced in official subject-wise statistics

rajeduboard.rajasthan.gov.in/statistics2026.htm

MCQ study aid

Local bank adapts knowledge to four-option MCQs; official paper is mixed/performance format

OpenExamPrep assessment-format policy

RBSE Senior Secondary (Class 12) Mathematics (code 015): Theory 80 + Sessional 20 = 100; 3 hours 15 minutes (theory paper). Pass about 33% per RBSE rules (confirm circular). Fee as per board notification. Free English MCQ study aid — not a full official-format simulation.

Sample RBSE SS Mathematics Practice Questions

Try these sample questions to test your RBSE SS Mathematics exam readiness. Each question includes a detailed explanation. Start the interactive quiz above for the full 100+ question experience with AI tutoring.

1On the set A = {1, 2, 3}, the relation R = {(1, 1), (2, 2), (3, 3), (1, 3), (3, 1)} is:
A.Reflexive, symmetric and transitive
B.Reflexive and symmetric but not transitive
C.Symmetric and transitive but not reflexive
D.Reflexive and transitive but not symmetric
Explanation: All diagonal pairs are present, so R is reflexive. (1,3) and (3,1) are both in R, so R is symmetric. Compositions involving (1,3) and (3,1) recover (1,1) and (3,3), already in R, so R is transitive. Hence R is an equivalence relation.
2Let f: ℝ → ℝ be given by f(x) = 5x − 2. Then f is:
A.One-one and onto
B.One-one but not onto
C.Onto but not one-one
D.Neither one-one nor onto
Explanation: f(x₁)=f(x₂) ⇒ 5x₁−2=5x₂−2 ⇒ x₁=x₂, so f is injective. For any y∈ℝ, x=(y+2)/5 satisfies f(x)=y, so f is surjective. Thus f is bijective.
3If f(x) = 2x + 1 and g(x) = x² − 3, then (g ∘ f)(x) equals:
A.4x² + 4x − 2
B.2x² − 5
C.4x² − 2
D.2x² + 1
Explanation: (g ∘ f)(x) = g(f(x)) = g(2x+1) = (2x+1)² − 3 = 4x² + 4x + 1 − 3 = 4x² + 4x − 2.
4The inverse of the bijective function f: ℝ → ℝ, f(x) = 3x − 9, is:
A.f⁻¹(x) = (x + 9)/3
B.f⁻¹(x) = (x − 9)/3
C.f⁻¹(x) = 3x + 9
D.f⁻¹(x) = x/3 − 9
Explanation: y = 3x − 9 ⇒ x = (y + 9)/3, so f⁻¹(x) = (x + 9)/3. Check: f(f⁻¹(x)) = 3·((x+9)/3) − 9 = x.
5If A = {a, b, c} and a binary operation * on A is given by the Cayley table with a*a=a, a*b=b, a*c=c, b*a=b, b*b=a, b*c=a, c*a=c, c*b=a, c*c=a, then the identity element is:
A.a
B.b
C.c
D.Does not exist
Explanation: An identity e satisfies x*e = e*x = x for all x. Checking a: a*a=a, b*a=b, c*a=c and a*b=b, a*c=c. So a is the identity.
6The principal value of sin⁻¹(1/2) is:
A.π/6
B.π/3
C.π/4
D.π/2
Explanation: sin(π/6)=1/2 and π/6 ∈ [−π/2, π/2], the principal range of sin⁻¹. Hence sin⁻¹(1/2)=π/6.
7The principal value of cos⁻¹(−1/2) is:
A.2π/3
B.π/3
C.π/6
D.5π/6
Explanation: cos(2π/3)=−1/2 and 2π/3 ∈ [0, π], the principal range of cos⁻¹. Hence cos⁻¹(−1/2)=2π/3.
8If tan⁻¹ x + tan⁻¹ y = π/4 and xy < 1, then:
A.x + y = 1 − xy
B.x + y = 1 + xy
C.x − y = 1 + xy
D.xy = 1
Explanation: tan(tan⁻¹x + tan⁻¹y) = tan(π/4)=1. The addition formula gives (x+y)/(1−xy)=1 (valid when xy<1), so x+y = 1−xy.
9d/dx [sin⁻¹(x)] equals:
A.1/√(1 − x²)
B.−1/√(1 − x²)
C.1/(1 + x²)
D.1/√(1 + x²)
Explanation: Standard derivative: d/dx sin⁻¹(x) = 1/√(1−x²) for x ∈ (−1,1).
10The value of tan⁻¹(1) + tan⁻¹(2) + tan⁻¹(3) equals:
A.π
B.π/2
C.π/4
D.3π/4
Explanation: tan⁻¹1=π/4. Also tan⁻¹2 + tan⁻¹3 = π + tan⁻¹((2+3)/(1−6)) = π + tan⁻¹(−1) but since 2·3>1 the sum is in (π/2,π): tan⁻¹2+tan⁻¹3=π−π/4=3π/4. Total: π/4+3π/4=π.

About the RBSE SS Mathematics Practice Questions

Verified exam format metadata for Rajasthan RBSE Senior Secondary (Class 12) Mathematics — Code 015 is pending. The practice questions above remain available while official exam length, timing, passing score, fee, and administrator details are reviewed.