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100+ Free RBSE Praveshika Mathematics Practice Questions

Rajasthan RBSE Praveshika Mathematics — Code 009 practice questions are available now; exam metadata is being verified.

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2026 Statistics

Key Facts: RBSE Praveshika Mathematics Exam

9

RBSE subject code for Mathematics

RBSE Secondary/Praveshika 2026 subject-wise statistics

80 + 20

Typical Theory + Sessional full marks pattern (total 100)

RBSE Class 10 syllabus examination scheme

3 h 15 m

Typical theory paper duration

RBSE Class 10 syllabus

33%

Common minimum pass threshold under RBSE regulations

RBSE examination regulations (confirm circular)

2026

Main examination cycle evidenced in official subject-wise statistics

rajeduboard.rajasthan.gov.in/statistics2026.htm

MCQ study aid

Local bank adapts knowledge to four-option MCQs; official paper is mixed format

OpenExamPrep assessment-format policy

RBSE Praveshika Mathematics (code 9): mixed board paper, typically Theory 80 + Sessional 20 = 100, 3h15m. Pass about 33% per RBSE rules. Fee as per board notification. Free English MCQ study aid — not a full mixed-paper simulation.

Sample RBSE Praveshika Mathematics Practice Questions

Try these sample questions to test your RBSE Praveshika Mathematics exam readiness. Each question includes a detailed explanation. Start the interactive quiz above for the full 100+ question experience with AI tutoring.

1Using Euclid's division algorithm, HCF(945, 231) is:
A.21
B.63
C.77
D.33
Explanation: 945 = 231×4 + 21; 231 = 21×11 + 0. The last non-zero remainder is 21, so HCF(945, 231) = 21.
2If a = 2⁴×3×7² and b = 2²×3³×5, then LCM(a, b) is:
A.2⁴×3³×5×7²
B.2²×3×7²
C.2⁴×3³×5×7
D.2⁶×3⁴×5×7²
Explanation: LCM takes the maximum power of each prime: 2⁴, 3³, 5¹, 7² → 2⁴×3³×5×7².
3The decimal expansion of 17/80 terminates after how many places?
A.2
B.3
C.4
D.5
Explanation: 80 = 2⁴×5. The highest power among 2 and 5 in the denominator is 4, so after writing with denominator 10⁴ the decimal terminates after 4 places.
4Which expression is irrational?
A.√(64/9)
B.√72 / √8
C.√7 − √28
D.0.414141…
Explanation: √7 − √28 = √7 − 2√7 = −√7, which is irrational. √(64/9)=8/3; √72/√8=3; 0.41̅=41/99.
5If HCF(144, 180) = 36, then LCM(144, 180) is:
A.720
B.360
C.1440
D.540
Explanation: HCF × LCM = product of numbers ⇒ LCM = (144×180)/36. 144/36=4, so LCM=4×180=720.
6The product of two numbers is 2160 and their HCF is 12. Their LCM is:
A.180
B.160
C.200
D.240
Explanation: LCM = product / HCF = 2160/12 = 180.
7After how many decimal places does 7/56 terminate? (Simplify first.)
A.1
B.2
C.3
D.It does not terminate
Explanation: 7/56 = 1/8 = 1/2³. The decimal is 0.125, terminating after 3 places.
8If n is a natural number, 6ⁿ never ends with the digit 0 because:
A.6ⁿ is always even
B.6ⁿ is never divisible by 5
C.6ⁿ is always odd
D.6ⁿ is always divisible by 9
Explanation: To end with 0, a number must be divisible by 10 = 2×5. 6ⁿ = (2×3)ⁿ is always divisible by 2 but never by 5, so it never ends with 0.
9If one zero of the polynomial p(x) = x² − 5x + k is 2, then k equals:
A.6
B.4
C.10
D.−6
Explanation: p(2)=0 ⇒ 4 − 10 + k = 0 ⇒ k = 6.
10The zeros of x² − 7x + 12 are:
A.3 and 4
B.2 and 6
C.−3 and −4
D.1 and 12
Explanation: x² − 7x + 12 = (x−3)(x−4); zeros are 3 and 4.

About the RBSE Praveshika Mathematics Practice Questions

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