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Key Facts: MAHA TAIT Exam

200

Total Questions

MSCE Pune

120 mins

Time Limit

MSCE Pune

₹950

Open Category Fee

MSCE Pune

₹850

Reserved Category Fee

MSCE Pune

60%

Aptitude Weightage

MSCE Pune Syllabus

40%

Intelligence Weightage

MSCE Pune Syllabus

The MAHA TAIT is a 2-hour, 200-question computer-based recruitment exam conducted by MSCE Pune for government school teacher vacancies in Maharashtra. The fee is ₹950 for open category and ₹850 for reserved categories. It contains Aptitude (60%) and Intelligence (40%) sections with no negative marking. Recruitment is managed through Pavitra Portal based on these scores.

Sample MAHA TAIT Practice Questions

Try these sample questions to test your MAHA TAIT exam readiness. Each question includes a detailed explanation. Start the interactive quiz above for the full 100+ question experience with AI tutoring.

1Solve the following mathematical expression: 120 ÷ (15 - 3) × 4 + 6 = ?
A.46
B.36
C.16
D.56
Explanation: According to the BODMAS rule, we must solve brackets first, then division, multiplication, addition, and subtraction. Step 1: Solve the Bracket: (15 - 3) = 12. The expression becomes: 120 ÷ 12 × 4 + 6. Step 2: Perform Division: 120 ÷ 12 = 10. The expression becomes: 10 × 4 + 6. Step 3: Perform Multiplication: 10 × 4 = 40. The expression becomes: 40 + 6. Step 4: Perform Addition: 40 + 6 = 46. Therefore, the final answer is 46.
2A student has to secure 40% marks to pass an exam. He gets 178 marks and fails by 22 marks. What are the maximum marks for the exam?
A.400
B.450
C.500
D.600
Explanation: Let the maximum marks be M. The student gets 178 marks and fails by 22 marks, which means the passing marks are 178 + 22 = 200. Since the passing marks are 40% of the maximum marks: 40% of M = 200 => (40/100) × M = 200. M = (200 × 100) ÷ 40 = 20000 ÷ 40 = 500. Therefore, the maximum marks are 500.
3A dealer buys an article for ₹1,200 and sells it at a loss of 10%. If he wanted to gain 15% instead, what should be the selling price of the article?
A.₹1,320
B.₹1,380
C.₹1,440
D.₹1,500
Explanation: Cost Price (CP) of the article = ₹1,200. To gain 15%, the selling price (SP) must be calculated as follows: New SP = CP × (100 + Gain%) ÷ 100 New SP = 1,200 × (100 + 15) ÷ 100 New SP = 1,200 × 1.15 = ₹1,380. Therefore, the selling price should be ₹1,380. Note that the initial loss of 10% is dummy information designed to test focus.
4The average weight of 8 men is increased by 1.5 kg when one of the men, who weighs 65 kg, is replaced by a new man. What is the weight of the new man?
A.73 kg
B.75 kg
C.77 kg
D.79 kg
Explanation: Number of men = 8. Increase in average weight = 1.5 kg. Total increase in weight = 8 × 1.5 kg = 12 kg. Since the new man replaced a man weighing 65 kg and caused the total weight to increase by 12 kg: Weight of new man = Weight of replaced man + Total increase = 65 kg + 12 kg = 77 kg.
5If A : B = 2 : 3, B : C = 4 : 5, and C : D = 6 : 7, what is the ratio of A : D?
A.16 : 35
B.8 : 15
C.12 : 35
D.18 : 35
Explanation: We can find the ratio of A : D by multiplying the individual ratios: A / D = (A / B) × (B / C) × (C / D) A / D = (2 / 3) × (4 / 5) × (6 / 7) A / D = (2 × 4 × 6) ÷ (3 × 5 × 7) = 48 ÷ 105. Simplifying the fraction by dividing both the numerator and the denominator by 3: Numerator = 48 ÷ 3 = 16. Denominator = 105 ÷ 3 = 35. Therefore, A : D = 16 : 35.
6A can complete a piece of work in 12 days, and B can do the same work in 15 days. They work together for 5 days, and then A leaves. How many days will B take to finish the remaining work alone?
A.1.25 days
B.2.5 days
C.3.75 days
D.4.5 days
Explanation: Total work can be assumed as the LCM of 12 and 15, which is 60 units. Efficiency of A = 60 ÷ 12 = 5 units/day. Efficiency of B = 60 ÷ 15 = 4 units/day. Combined efficiency of A and B = 5 + 4 = 9 units/day. Work done by both in 5 days = 9 × 5 = 45 units. Remaining work = 60 - 45 = 15 units. Time taken by B alone to finish the remaining work = Remaining work ÷ Efficiency of B = 15 ÷ 4 = 3.75 days.
7A train 150 meters long passes a telegraph post in 12 seconds. In how many seconds will it cross a bridge 250 meters long?
A.20 seconds
B.24 seconds
C.32 seconds
D.36 seconds
Explanation: Speed of the train = Distance ÷ Time = Length of train ÷ Time to pass post = 150 meters ÷ 12 seconds = 12.5 m/s. To cross a bridge 250 meters long, the total distance to be covered = Length of train + Length of bridge = 150 + 250 = 400 meters. Time taken to cross the bridge = Total distance ÷ Speed of train = 400 meters ÷ 12.5 m/s = 32 seconds.
8At what rate percent per annum simple interest will a sum of money double itself in 8 years?
A.10.0%
B.12.5%
C.15.0%
D.16.5%
Explanation: Let the principal be P. For the sum to double itself, the Simple Interest (SI) earned must be equal to the principal P. So, SI = P. Formula for Simple Interest: SI = (P × R × T) ÷ 100. Substituting SI = P, T = 8: P = (P × R × 8) ÷ 100 1 = (R × 8) ÷ 100 8R = 100 R = 100 ÷ 8 = 12.5%. Therefore, the rate of interest is 12.5% per annum.
9What is the difference between simple interest and compound interest on ₹8,000 for 2 years at 5% per annum?
A.₹10
B.₹20
C.₹30
D.₹40
Explanation: The formula for the difference (D) between compound interest and simple interest for 2 years is: D = P × (R ÷ 100)^2 where P is the principal (₹8,000) and R is the annual rate of interest (5%). D = 8,000 × (5 ÷ 100)^2 D = 8,000 × (1 ÷ 20)^2 D = 8,000 × (1 ÷ 400) D = 8,000 ÷ 400 = ₹20. Therefore, the difference is ₹20.
10Find the largest 4-digit number that is exactly divisible by 88.
A.9988
B.9966
C.9944
D.9912
Explanation: The largest 4-digit number is 9,999. We divide 9,999 by 88 to find the remainder: 9,999 ÷ 88: 99 ÷ 88 = 1 remainder 11 119 ÷ 88 = 1 remainder 31 319 ÷ 88 = 3 (since 88 × 3 = 264) Remainder = 319 - 264 = 55. To find the largest 4-digit number divisible by 88, we subtract this remainder from 9,999: 9,999 - 55 = 9,944. Therefore, 9,944 is the correct number.

About the MAHA TAIT Exam

The Maharashtra Teacher Aptitude and Intelligence Test (MAHA TAIT) is a state-level teacher recruitment examination conducted online by the Maharashtra State Council of Examination (MSCE), Pune. The test is designed to measure the mathematical capability, linguistic competency, classroom adjustment skills, personality, and intelligence of candidates seeking teaching posts in government, local body, and aided private schools across Maharashtra. Unlike qualifying exams like TET, TAIT scores directly determine the recruitment merit ranking on the Pavitra Portal, making it highly competitive.

Assessment

200 Multiple-Choice Questions (120 Aptitude, 80 Intelligence)

Time Limit

2 hours

Passing Score

60% for Open (120/200), 50% for OBC (100/200), 40% for SC/ST (80/200)

Exam Fee

₹950 (Open), ₹850 (Reserved) (MSCE (Maharashtra State Council of Examination), Pune)

MAHA TAIT Exam Content Outline

60%

Teacher Aptitude

120 questions assessing Mathematical Ability, Marathi Language Ability, English Language Ability, Speed and Accuracy, Adjustment & Personality, and Inclination & Interest.

40%

Intelligence

80 questions evaluating Comprehension, Classification, Coding-Decoding, Correlation/Analogy, Series Completion, Ranking Hierarchy, and Logical Reasoning.

How to Pass the MAHA TAIT Exam

What You Need to Know

  • Passing score: 60% for Open (120/200), 50% for OBC (100/200), 40% for SC/ST (80/200)
  • Assessment: 200 Multiple-Choice Questions (120 Aptitude, 80 Intelligence)
  • Time limit: 2 hours
  • Exam fee: ₹950 (Open), ₹850 (Reserved)

Keys to Passing

  • Complete 500+ practice questions
  • Score 80%+ consistently before scheduling
  • Focus on highest-weighted sections
  • Use our AI tutor for tough concepts

MAHA TAIT Study Tips from Top Performers

1Master Marathi grammar topics like Pr प्रयोग, Samas समास, Synonyms, and Antonyms, as language skills represent highly scoring sections.
2Engage in daily practice of speed-calculation techniques for Quantitative Aptitude, aiming to solve arithmetic questions in under 30 seconds.
3Familiarize yourself with teacher-student behavior and pedagogical scenarios to score high on the Personality & Adjustment portion.
4Solve logical puzzles daily, focusing heavily on series, seating arrangement, coding-decoding, and syllogisms.
5Take timed mock exams to get used to the constraint of solving 200 questions in 120 minutes, which averages only 36 seconds per question.
6Do not leave any questions blank since there is no negative marking, but prioritize easier questions first.

Frequently Asked Questions

What is the MAHA TAIT exam?

The MAHA TAIT (Maharashtra Teacher Aptitude and Intelligence Test) is a competitive exam conducted by MSCE Pune to recruit primary, upper primary, secondary, and higher secondary teachers in government, municipal, and aided schools in Maharashtra.

What is the difference between MAHA TET and MAHA TAIT?

MAHA TET (Teacher Eligibility Test) is an entry-level eligibility test that candidates must pass to qualify as a teacher. MAHA TAIT is the actual competitive recruitment exam where scores directly determine selection and placement on the Pavitra Portal merit list.

What is the exam structure for MAHA TAIT?

The exam is a computer-based test comprising 200 multiple-choice questions to be completed in 120 minutes. It is divided into two sections: Teacher Aptitude (120 questions, 60% weightage) and Intelligence (80 questions, 40% weightage). There is no negative marking.

Is there negative marking in MAHA TAIT?

No, there is no negative marking in the MAHA TAIT exam. Candidates are rewarded 1 mark for every correct response, and 0 marks for incorrect or unanswered questions.

What is the Pavitra Portal and how does it work?

The Pavitra Portal is an online centralized teacher recruitment system run by the Maharashtra School Education Department. Candidates register on the portal with their TAIT marks, academic details, and preferences, and the portal dynamically generates merit lists for school allotments based on available vacancies.

What are the eligibility criteria for appearing in MAHA TAIT?

Candidates must have a degree (Graduation or Post-Graduation) along with professional qualifications like D.Ed, D.El.Ed, or B.Ed. For teaching classes 1 to 8, passing MAHA TET or CTET is also mandatory.

What is the application fee for MAHA TAIT?

The application fee is ₹950 for candidates from the Open (General) category and ₹850 for candidates belonging to Reserved categories (OBC, SC, ST, EWS, Orphans, and PwD).