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100+ Free Karnataka SSLC Mathematics (KSEAB) Practice Questions

Karnataka School Examination and Assessment Board (KSEAB) SSLC Class 10 Mathematics practice questions are available now; exam metadata is being verified.

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2026 Statistics

Key Facts: Karnataka SSLC Mathematics (KSEAB) Exam

3 h 15 m

Typical SSLC exam duration including reading time for many subjects

KSEAB SSLC exam logistics / date sheet

~30–33%

Commonly reported minimum per-subject pass mark range

KSEAB pass criteria reporting (confirm current circular)

81E / 81K

Common paper codes for Mathematics English / Kannada medium

KSEAB SSLC model question papers

80+20 pattern

Commonly described theory + internal split (confirm year notice)

KSEAB SSLC assessment reporting

Mixed paper

Official format is objective + subjective, not pure MCQ

KSEAB SSLC Mathematics model papers

English MCQ adaptation

This free local bank is not the official mixed paper format

OpenExamPrep practice policy

KSEAB SSLC Mathematics is a Class 10 board subject with a mixed objective + subjective paper lasting about 3 h 15 min (codes 81E/81K). Pass is commonly ~30–33% per subject plus aggregate rules as notified. Fees are paid through schools. This free 2026 bank is an English MCQ study adaptation — not an official paper simulation.

Sample Karnataka SSLC Mathematics (KSEAB) Practice Questions

Try these sample questions to test your Karnataka SSLC Mathematics (KSEAB) exam readiness. Each question includes a detailed explanation. Start the interactive quiz above for the full 100+ question experience with AI tutoring.

1Using Euclid's division algorithm, HCF(135, 225) is:
A.15
B.45
C.75
D.9
Explanation: 225 = 135×1 + 90; 135 = 90×1 + 45; 90 = 45×2 + 0. The last non-zero remainder is 45, so HCF(135, 225) = 45.
2If a = 2²×3×5³ and b = 2×3³×5, then LCM(a, b) is:
A.2×3×5
B.2²×3³×5
C.2²×3³×5³
D.2³×3³×5³
Explanation: LCM takes the highest powers of all primes present: 2², 3³, and 5³, so LCM = 2²×3³×5³.
3The decimal expansion of 7/80 terminates after how many places?
A.2
B.3
C.4
D.5
Explanation: 80 = 2⁴×5. Multiply numerator and denominator by 5³: 7/80 = 875/10000 = 0.0875, which terminates after 4 decimal places.
4Which of the following is irrational?
A.√(49/64)
B.√18/√2
C.√3 + √12
D.0.151515…
Explanation: √3 + √12 = √3 + 2√3 = 3√3, which is irrational. √(49/64)=7/8; √18/√2=3; 0.15̅=5/33.
5If HCF(96, 404) = 4, then LCM(96, 404) is:
A.2424
B.4848
C.1616
D.9696
Explanation: HCF × LCM = product of the numbers. LCM = 96×404/4. Since 96/4 = 24, LCM = 24×404 = 9696.
6If √2 = p/q in lowest terms with integers p, q > 0, then 2q² = p² implies:
A.p and q are both even — contradiction
B.p is odd only
C.q must equal 1
D.p² is not divisible by 2
Explanation: p² = 2q² ⇒ p² even ⇒ p even. Write p = 2k; then 4k² = 2q² ⇒ q² = 2k² ⇒ q even. Both even contradicts lowest terms, so √2 is irrational.
7If α and β are zeros of x² − 7x + 10, then α² + β² equals:
A.49
B.19
C.29
D.39
Explanation: α+β = 7 and αβ = 10. Then α²+β² = (α+β)² − 2αβ = 49 − 20 = 29.
8A monic quadratic with zeros 3 and −4 is:
A.x² + x − 12
B.x² − x − 12
C.x² + x + 12
D.x² − 7x − 12
Explanation: Sum = −1, product = −12. Form x² − (sum)x + product = x² + x − 12.
9When p(x) = x³ − 4x² + 5x − 2 is divided by (x − 2), the remainder is:
A.0
B.2
C.−2
D.4
Explanation: By the remainder theorem, p(2) = 8 − 16 + 10 − 2 = 0.
10If the sum of the zeros of 3x² − kx + 9 equals their product, then k is:
A.9
B.−9
C.3
D.6
Explanation: For 3x² − kx + 9, sum of zeros = k/3 and product = 9/3 = 3. Set sum = product: k/3 = 3 ⇒ k = 9.

About the Karnataka SSLC Mathematics (KSEAB) Practice Questions

Verified exam format metadata for Karnataka School Examination and Assessment Board (KSEAB) SSLC Class 10 Mathematics is pending. The practice questions above remain available while official exam length, timing, passing score, fee, and administrator details are reviewed.