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100+ Free Karnataka II PUC Basic Mathematics (KSEAB) Practice Questions

Karnataka School Examination and Assessment Board (KSEAB) II PUC Class 12 Basic Mathematics (Subject Code 75) practice questions are available now; exam metadata is being verified.

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2026 Statistics

Key Facts: Karnataka II PUC Basic Mathematics (KSEAB) Exam

Code 75

Official II PUC Basic Mathematics subject code

KSEAB / DPUE II PUC blueprint 2025–26

≠ Code 35

Distinct from II PUC Mathematics (science-stream full maths)

KSEAB subject codes / DPUE blueprints

~80 theory

Commonly described written theory marks pattern (confirm year notice)

KSEAB II PUC assessment reporting / model papers

~3 hours

Typical II PUC exam duration (confirm date sheet)

KSEAB II PUC exam logistics reporting

~30% / ~33%

Commonly reported per-subject minimum and overall aggregate pass range

KSEAB pass criteria reporting (confirm current circular)

Mixed paper

Official format is objective + subjective, not pure MCQ

KSEAB II PUC Basic Mathematics blueprint Parts A–E style

English MCQ adaptation

This free local bank is not the official mixed paper format

OpenExamPrep practice policy

KSEAB II PUC Basic Mathematics (code 75) is the commerce/arts Class 12 board maths paper — mixed objective + subjective (~3 h), theory commonly ~80 marks plus internal. Pass is commonly ~30% per subject and ~33% aggregate as notified. Distinct from full Maths (35). This free 2026 bank is an English MCQ study adaptation with calculations — not an official paper simulation.

Sample Karnataka II PUC Basic Mathematics (KSEAB) Practice Questions

Try these sample questions to test your Karnataka II PUC Basic Mathematics (KSEAB) exam readiness. Each question includes a detailed explanation. Start the interactive quiz above for the full 100+ question experience with AI tutoring.

1If A = [[2, 3], [1, 4]] and B = [[1, 0], [2, 1]], what is the product matrix AB?
A.[[8, 3], [9, 4]]
B.[[2, 0], [2, 4]]
C.[[5, 3], [9, 4]]
D.[[8, 0], [9, 1]]
Explanation: Matrix multiplication uses row-by-column products: (1,1)=2·1+3·2=8, (1,2)=2·0+3·1=3, (2,1)=1·1+4·2=9, (2,2)=1·0+4·1=4. Therefore AB = [[8, 3], [9, 4]].
2Find the determinant of the matrix [[5, 2], [3, 4]].
A.26
B.14
C.−2
D.20
Explanation: For a 2×2 matrix [[a, b], [c, d]], det = ad − bc = 5·4 − 2·3 = 20 − 6 = 14.
3If A = [[1, 2], [3, 4]], what is A + Aᵀ (the sum of A and its transpose)?
A.[[2, 4], [6, 8]]
B.[[1, 5], [5, 4]]
C.[[2, 5], [5, 8]]
D.[[0, −1], [1, 0]]
Explanation: Aᵀ = [[1, 3], [2, 4]]. Adding entrywise gives (1,1)=2, (1,2)=5, (2,1)=5, (2,2)=8. So A + Aᵀ = [[2, 5], [5, 8]], which is symmetric.
4Solve for x if |[[x, 2], [3, 4]]| = 10.
A.x = 5
B.x = 2
C.x = 1
D.x = 4
Explanation: Determinant condition: 4x − 6 = 10 ⇒ 4x = 16 ⇒ x = 4.
5If A = [[2, 1], [0, 3]], find A⁻¹ using (1/det A)·adj A.
A.[[1/2, −1/6], [0, 1/3]]
B.[[3, −1], [0, 2]]
C.[[1/2, 1/6], [0, 1/3]]
D.[[2, −1], [0, 3]]
Explanation: det A = 2·3 − 1·0 = 6. adj A = [[3, −1], [0, 2]]. So A⁻¹ = (1/6)·[[3, −1], [0, 2]] = [[1/2, −1/6], [0, 1/3]].
6Evaluate the 3×3 determinant |[[1, 2, 3], [0, 4, 5], [0, 0, 6]]|.
A.0
B.24
C.30
D.12
Explanation: An upper-triangular matrix has determinant equal to the product of its diagonal entries: 1·4·6 = 24.
7If A is a 2×2 matrix with det(A) = 5, what is det(3A)?
A.15
B.5
C.45
D.9
Explanation: For an n×n matrix, det(kA) = kⁿ det(A). Here n = 2, so det(3A) = 3²·5 = 9·5 = 45.
8The system 2x + y = 5 and 4x + 2y = 10 has:
A.A unique solution
B.No solution
C.Exactly two solutions
D.Infinitely many solutions
Explanation: The second equation is exactly twice the first, so the equations are dependent. The coefficient determinant |[[2,1],[4,2]]| = 0 with a consistent right-hand side, giving infinitely many solutions.
9If A = [[0, −2], [2, 0]], which statement is true?
A.A is skew-symmetric and det(A) = 4
B.A is symmetric and det(A) = 0
C.A is skew-symmetric and det(A) = −4
D.A is diagonal with det(A) = 4
Explanation: Aᵀ = [[0, 2], [−2, 0]] = −A, so A is skew-symmetric. det(A) = 0·0 − (−2)·2 = 4.
10Using Cramer’s rule, solve x + 2y = 8 and 3x − y = 3 for x.
A.x = 14
B.x = 2
C.x = 3
D.x = −2
Explanation: D = |[[1, 2], [3, −1]]| = −1 − 6 = −7. Dₓ = |[[8, 2], [3, −1]]| = −8 − 6 = −14. Therefore x = Dₓ/D = (−14)/(−7) = 2. Check: y = (8−2)/2 = 3 and 3(2)−3 = 3.

About the Karnataka II PUC Basic Mathematics (KSEAB) Practice Questions

Verified exam format metadata for Karnataka School Examination and Assessment Board (KSEAB) II PUC Class 12 Basic Mathematics (Subject Code 75) is pending. The practice questions above remain available while official exam length, timing, passing score, fee, and administrator details are reviewed.