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100+ Free Kerala SSLC Mathematics Practice Questions

Kerala Secondary School Leaving Certificate (SSLC / Class 10) Mathematics under Kerala Pareeksha Bhavan and SCERT Kerala practice questions are available now; exam metadata is being verified.

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2026 Statistics

Key Facts: Kerala SSLC Mathematics Exam

100 marks

Subject total via TE + CE (typically TE 80 + CE 20 as notified)

Kerala SSLC assessment pattern (Pareeksha Bhavan)

~2.5 h incl. cool-off

Typical Mathematics theory duration for SSLC

Kerala SSLC timetable logistics

D+ / ~30%

Common pass grade/aggregate with separate TE floor (~24/80 often cited)

Kerala SSLC grading / pass criteria reporting

TE + CE

Official format is mixed written TE plus CE, not pure MCQ

Kerala SSLC Mathematics assessment pattern

EN + ML

English and Malayalam media commonly available

Kerala SSLC language media practice

English MCQ adaptation

This free local bank is not the official mixed paper format

OpenExamPrep practice policy

Pareeksha Bhavan / SCERT

Administrator and syllabus authority for Kerala SSLC Mathematics

Government of Kerala secondary education system

Kerala SSLC Mathematics totals 100 marks via TE + CE (typically TE 80 + CE 20); theory is commonly ~2.5 h including cool-off. Pass is commonly D+/~30% aggregate with ~30% in TE separately (TE floor often ~24/80). Fees are paid through schools. This free 2026 bank is an English MCQ study adaptation — not an official paper simulation.

Sample Kerala SSLC Mathematics Practice Questions

Try these sample questions to test your Kerala SSLC Mathematics exam readiness. Each question includes a detailed explanation. Start the interactive quiz above for the full 100+ question experience with AI tutoring.

1The first term of an arithmetic sequence is 7 and the common difference is 3. The 12th term is:
A.37
B.40
C.43
D.46
Explanation: aₙ = a + (n−1)d = 7 + 11×3 = 7 + 33 = 40.
2In the AP 5, 9, 13, 17, … the common difference is:
A.3
B.4
C.5
D.2
Explanation: d = 9 − 5 = 4 (and 13 − 9 = 4).
3The sum of the first 10 terms of the AP 2, 5, 8, 11, … is:
A.155
B.165
C.175
D.185
Explanation: a = 2, d = 3. Sₙ = n/2 [2a + (n−1)d] ⇒ S₁₀ = 10/2 [4 + 9×3] = 5(4+27) = 5×31 = 155.
4If the 5th term of an AP is 18 and the 9th term is 30, the common difference is:
A.2
B.3
C.4
D.5
Explanation: a₅ = a+4d = 18, a₉ = a+8d = 30. Subtract: 4d = 12 ⇒ d = 3.
5How many terms of the AP 3, 7, 11, 15, … must be taken so that their sum is 300?
A.10
B.12
C.15
D.20
Explanation: a=3, d=4. Sₙ = n/2 [6 + (n−1)4] = 300 ⇒ n[6+4n−4] = 600 ⇒ n(4n+2)=600 ⇒ n(2n+1)=300. For n=12: 12×25=300.
6The 20th term of the AP −5, −1, 3, 7, … is:
A.67
B.71
C.75
D.79
Explanation: a=−5, d=4. a₂₀ = −5 + 19×4 = −5 + 76 = 71.
7If a = 5 and S₁₀ = 185 for an AP, the common difference d is:
A.2
B.3
C.4
D.5
Explanation: S₁₀ = 10/2 [2×5 + 9d] = 185 ⇒ 5(10+9d)=185 ⇒ 10+9d=37 ⇒ 9d=27 ⇒ d=3.
8The sum of the first n natural numbers is Sₙ = n(n+1)/2. S₂₀ equals:
A.190
B.200
C.210
D.220
Explanation: S₂₀ = 20×21/2 = 210.
9In an AP, a₇ = 17 and a₁₃ = 35. The first term a is:
A.−1
B.1
C.2
D.3
Explanation: a+6d=17, a+12d=35. Subtract: 6d=18 ⇒ d=3. Then a+18=17 ⇒ a=−1.
10Three numbers in AP have sum 24 and product 440. The numbers in increasing order are:
A.5, 8, 11
B.4, 8, 12
C.2, 8, 14
D.6, 8, 10
Explanation: Let the numbers be a−d, a, a+d. Sum: 3a=24 ⇒ a=8. Product: 8(64−d²)=440 ⇒ 64−d²=55 ⇒ d²=9 ⇒ d=3. Numbers: 5, 8, 11.

About the Kerala SSLC Mathematics Practice Questions

Verified exam format metadata for Kerala Secondary School Leaving Certificate (SSLC / Class 10) Mathematics under Kerala Pareeksha Bhavan and SCERT Kerala is pending. The practice questions above remain available while official exam length, timing, passing score, fee, and administrator details are reviewed.