All Practice Exams

100+ Free IMU CET Practice Questions

Pass your Indian Maritime University Common Entrance Test exam on the first try — instant access, no signup required.

✓ No registration✓ No credit card✓ No hidden fees✓ Start practicing immediately
100+ Questions
100% Free

Loading practice questions...

2026 Statistics

Key Facts: IMU CET Exam

200 MCQs

Total number of multiple-choice questions in the exam

IMU CET Admission Brochure

3 hours

Total exam duration (180 minutes)

IMU CET Academic Guidelines

-0.25 marks

Negative marking penalty for each incorrect response

IMU CET Marking Scheme

₹1,000 / ₹700

Application fee for General/OBC and SC/ST respectively

IMU CET Fee Structure

60% PCM

Minimum required Class 12 aggregate in PCM for eligibility

IMU CET Eligibility Rules

50% English

Minimum English score required in Class 10 or 12

IMU CET Eligibility Rules

IMU CET is a CBT entrance exam for maritime UG courses. The 3-hour exam has 200 MCQs spanning Physics, Chemistry, Maths, English, and Aptitude with negative marking (-0.25). Registration fee is ₹1,000 for General/OBC and ₹700 for SC/ST.

Sample IMU CET Practice Questions

Try these sample questions to test your IMU CET exam readiness. Each question includes a detailed explanation. Start the interactive quiz above for the full 100+ question experience with AI tutoring.

1A ship travels 12 km due North and then 5 km due East. What is the magnitude of the ship's net displacement from its starting point?
A.17 km
B.7 km
C.12.5 km
D.13 km
Explanation: The ship's path forms a right-angled triangle with sides 12 km (North) and 5 km (East). The net displacement is the hypotenuse, calculated using the Pythagorean theorem: d = sqrt(12^2 + 5^2) = sqrt(144 + 25) = sqrt(169) = 13 km.
2A force of 15 N is applied to a mass of 3 kg. What is the acceleration produced in the mass, assuming a frictionless surface?
A.45 m/s²
B.0.2 m/s²
C.5 m/s²
D.18 m/s²
Explanation: According to Newton's Second Law of Motion, F = ma. Rearranging for acceleration gives a = F / m = 15 N / 3 kg = 5 m/s².
3An engine does 6000 J of work in 2 minutes. What is the average power developed by the engine?
A.3000 W
B.50 W
C.50 kW
D.300 W
Explanation: Power is the rate of doing work, P = W / t. The time must be in seconds, so 2 minutes = 120 seconds. Thus, P = 6000 J / 120 s = 50 W.
4If the distance between two point charges is doubled, what happens to the electrostatic force between them?
A.It becomes one-fourth
B.It is halved
C.It is doubled
D.It becomes four times
Explanation: According to Coulomb's Law, the electrostatic force (F) between two charges is inversely proportional to the square of the distance (r) between them (F ∝ 1/r²). Doubling the distance (2r) makes the force proportional to 1/(2r)² = 1/(4r²), which is one-fourth of the original force.
5Which of the following thermal processes occurs at a constant volume?
A.Isobaric process
B.Isothermal process
C.Adiabatic process
D.Isochoric process
Explanation: An isochoric process is a thermodynamic process during which the volume of the closed system undergoing such a process remains constant. Consequently, no boundary work is done by or on the system.
6A convex lens has a focal length of 20 cm. What is its power in diopters?
A.-5 D
B.+0.05 D
C.+5 D
D.+20 D
Explanation: The power of a lens P is given by P = 1/f, where f is the focal length in meters. Converting 20 cm to meters gives f = 0.2 m. Thus, P = 1 / 0.2 = +5 D.
7What is the maximum wavelength of electromagnetic radiation required to eject electrons from a metal surface having a work function of 2.0 eV? (Take h = 6.63 x 10⁻³⁴ J·s, c = 3.0 x 10⁸ m/s, and 1 eV = 1.6 x 10⁻¹⁹ J)
A.310 nm
B.621 nm
C.1242 nm
D.450 nm
Explanation: The threshold wavelength λ is given by λ = hc / Φ, where Φ is the work function. Converting Φ to Joules: 2.0 * 1.6 * 10⁻¹⁹ J = 3.2 * 10⁻¹⁹ J. Then, λ = (6.63 * 10⁻³⁴ * 3.0 * 10⁸) / (3.2 * 10⁻¹⁹) = 1.989 * 10⁻²⁵ / (3.2 * 10⁻¹⁹) ≈ 6.21 * 10⁻⁷ m = 621 nm.
8A projectile is launched from the ground at an angle of 30° with an initial velocity of 40 m/s. What is the horizontal range of the projectile? (Take g = 10 m/s²)
A.80√3 m
B.40√3 m
C.160 m
D.80 m
Explanation: The horizontal range R is given by R = (u² * sin(2θ)) / g. Here, u = 40 m/s and θ = 30°, so 2θ = 60°. Therefore, R = (40² * sin(60°)) / 10 = (1600 * √3/2) / 10 = 80√3 m.
9A body of mass 2 kg is rotated in a horizontal circle of radius 0.5 m at a constant speed. If the tension in the string is 16 N, what is the angular velocity of the body?
A.8 rad/s
B.16 rad/s
C.2 rad/s
D.4 rad/s
Explanation: The tension in the string provides the necessary centripetal force. Therefore, T = m * ω² * r. Rearranging for angular velocity ω: ω = sqrt(T / (m * r)) = sqrt(16 / (2 * 0.5)) = sqrt(16 / 1) = 4 rad/s.
10A bullet of mass 20 g moving with a speed of 150 m/s penetrates a sandbag and comes to rest in 0.03 seconds. What is the average retarding force exerted by the sand on the bullet?
A.10 N
B.1000 N
C.100 N
D.300 N
Explanation: According to the impulse-momentum theorem, Force F = Δp / Δt = m * (v - u) / t. Mass m = 0.02 kg, initial velocity u = 150 m/s, final velocity v = 0, and t = 0.03 s. So, F = (0.02 * (0 - 150)) / 0.03 = -3 / 0.03 = -100 N. The magnitude of the retarding force is 100 N.

About the IMU CET Exam

The Indian Maritime University Common Entrance Test (IMU CET) is the national-level entrance exam for admission to various undergraduate (B.Tech Marine Engineering, B.Sc Nautical Science, DNS, etc.) and postgraduate programmes offered by IMU and its affiliated institutes. The undergraduate exam evaluates candidates on 10+2 level Physics, Chemistry, and Mathematics, alongside English and General Aptitude. This practice test bank contains exactly 100 high-quality questions mapped to the IMU CET syllabus, complete with step-by-step explanations to build concepts and speed.

Assessment

The IMU CET is a computer-based test (CBT) consisting of 200 multiple-choice questions (MCQs) to be answered in 3 hours (180 minutes). The subjects covered are Physics (50 questions), Mathematics (50 questions), English (40 questions), General Aptitude (40 questions), and Chemistry (20 questions). For every correct answer, 1 mark is awarded, and 0.25 marks are deducted for every incorrect response.

Time Limit

3 hours (180 minutes)

Passing Score

Admission is based on the merit rank list generated from the CBT. Typical qualifying marks are around 120/200 (60%) for General/EWS, 108/200 (54%) for OBC-NCL, and 100/200 (50%) for SC/ST candidates.

Exam Fee

₹1,000 for General / OBC-NCL / EWS candidates; ₹700 for SC / ST candidates. (Indian Maritime University (IMU))

IMU CET Exam Content Outline

25%

Physics

Kinematics, Dynamics, Electrostatics, Electromagnetism, Optics, Thermodynamics, and Modern Physics.

25%

Mathematics

Calculus, Algebra, Probability and Statistics, Vector Algebra, Coordinate Geometry, and Trigonometry.

10%

Chemistry

Physical Chemistry, Organic Chemistry, and Inorganic Chemistry.

20%

English

Grammar, Vocabulary, Comprehension, Synonyms and Antonyms, and Idioms.

20%

General Aptitude

Quantitative Aptitude, Logical Reasoning, Spatial Ability, and Data Interpretation.

How to Pass the IMU CET Exam

What You Need to Know

  • Passing score: Admission is based on the merit rank list generated from the CBT. Typical qualifying marks are around 120/200 (60%) for General/EWS, 108/200 (54%) for OBC-NCL, and 100/200 (50%) for SC/ST candidates.
  • Assessment: The IMU CET is a computer-based test (CBT) consisting of 200 multiple-choice questions (MCQs) to be answered in 3 hours (180 minutes). The subjects covered are Physics (50 questions), Mathematics (50 questions), English (40 questions), General Aptitude (40 questions), and Chemistry (20 questions). For every correct answer, 1 mark is awarded, and 0.25 marks are deducted for every incorrect response.
  • Time limit: 3 hours (180 minutes)
  • Exam fee: ₹1,000 for General / OBC-NCL / EWS candidates; ₹700 for SC / ST candidates.

Keys to Passing

  • Complete 500+ practice questions
  • Score 80%+ consistently before scheduling
  • Focus on highest-weighted sections
  • Use our AI tutor for tough concepts

IMU CET Study Tips from Top Performers

1Review NCERT Class 11 and 12 syllabus for Physics and Mathematics, as these carry the maximum weight (50 questions each).
2Practice calculations for Kinematics, Thermodynamics, Calculus, and Coordinate Geometry.
3Focus on English grammar, synonym-antonyms, and sentence completion to score well in the 40-question English section.
4Solve logical reasoning and quantitative aptitude problems regularly.
5Keep track of time; solving 200 questions in 180 minutes requires high speed.

Frequently Asked Questions

What is the exam pattern for IMU CET UG?

The exam consists of 200 multiple-choice questions (MCQs) from Physics (50), Mathematics (50), Chemistry (20), English (40), and General Aptitude (40). The total duration is 3 hours (180 minutes).

Is there negative marking in IMU CET?

Yes, there is negative marking. For every correct answer, 1 mark is awarded, and 0.25 marks are deducted for every incorrect response.

What are the eligibility criteria for undergraduate programs?

Candidates must have completed 10+2 or equivalent with Physics, Chemistry, and Mathematics (PCM) with a minimum of 60% aggregate. They must also have scored at least 50% in English in Class 10 or 12. SC/ST candidates receive a 5% relaxation in PCM marks.

What is the application fee for IMU CET?

The application fee is ₹1,000 for General, OBC-NCL, and EWS candidates, and ₹700 for SC and ST candidates.

What is the passing score or cutoff for IMU CET?

There is no pre-defined passing score. Admission is based on the merit rank list. However, scoring above 120 marks (60%) is generally considered competitive for securing admission to preferred campuses.

Are there medical fitness requirements?

Yes, candidates aspiring for maritime programs (like B.Tech Marine Engineering and B.Sc Nautical Science) must satisfy the medical fitness standards prescribed by the Directorate General of Shipping (DGS), including eyesight and physical fitness.