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100+ Free BSEB Matric Adv Math (Opt) Practice Questions

Bihar School Examination Board (BSEB) Matric Advanced Mathematics — Optional (Class 10 / model 114 OPT-ADV.MATH) practice questions are available now; exam metadata is being verified.

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2026 Statistics

Key Facts: BSEB Matric Adv Math (Opt) Exam

~3h 15m

Typical BSEB Matric theory exam duration

BSEB Matric exam pattern (secondary + board logistics)

Model 114

Illustrative OPT-ADV.MATH model-paper style code for Optional Advanced Mathematics

BSEB Matric model-paper labelling (confirm current year)

~30%

Carefully cited common Matric subject pass floor — verify current circular

Widely reported BSEB Matric practice; confirm current notification

English MCQ adaptation

This free local bank is not the official Matric paper format

OpenExamPrep practice policy

BSEB Matric Optional Advanced Mathematics (model 114 OPT-ADV.MATH style) is a Class 10 elective beyond core math, with a ~3h15m mixed-format theory paper and a carefully cited ~30% pass floor. This free 2026 bank is an English MCQ study adaptation for harder algebra, inequalities, geometry, trigonometry, coordinate geometry, series, and calculus intro where in syllabus.

Sample BSEB Matric Adv Math (Opt) Practice Questions

Try these sample questions to test your BSEB Matric Adv Math (Opt) exam readiness. Each question includes a detailed explanation. Start the interactive quiz above for the full 100+ question experience with AI tutoring.

1If α and β are roots of x² − 5x + 6 = 0, what is α + β?
A.5
B.6
C.−5
D.1
Explanation: For ax² + bx + c = 0, sum of roots = −b/a. Here a = 1, b = −5, so α + β = 5. Factoring (x−2)(x−3)=0 also gives roots 2 and 3 whose sum is 5.
2If α and β are roots of x² − 5x + 6 = 0, what is αβ?
A.6
B.5
C.−6
D.11
Explanation: Product of roots αβ = c/a = 6/1 = 6. Roots are 2 and 3, and 2 × 3 = 6.
3If α and β are the roots of x² − 5x + 6 = 0, the value of α² + β² is:
A.13
B.5
C.6
D.25
Explanation: For x² − 5x + 6 = 0, sum α + β = 5 and product αβ = 6. Hence α² + β² = (α + β)² − 2αβ = 25 − 12 = 13.
4If (x − 2) is a factor of x³ − 3x² + x + 2, the other quadratic factor begins with which monic form after synthetic division?
A.x² − x − 1
B.x² − x + 1
C.x² + x − 1
D.x² − 3x + 1
Explanation: Synthetic division of x³ − 3x² + x + 2 by (x − 2): bring down 1; 1×2=2, −3+2=−1; −1×2=−2, 1+(−2)=−1; −1×2=−2, 2+(−2)=0. Quotient coefficients 1, −1, −1 give x² − x − 1.
5Solve for x: 2x + 3y = 12 and x − y = 1. The value of x is:
A.3
B.2
C.4
D.1
Explanation: From x − y = 1, x = y + 1. Substitute: 2(y+1) + 3y = 12 → 2y + 2 + 3y = 12 → 5y = 10 → y = 2 → x = 3.
6If x + 1/x = 3, then x² + 1/x² equals:
A.7
B.9
C.5
D.11
Explanation: (x + 1/x)² = x² + 2 + 1/x². So 9 = x² + 2 + 1/x² → x² + 1/x² = 7.
7If x + 1/x = 3, then x³ + 1/x³ equals:
A.18
B.27
C.24
D.9
Explanation: x³ + 1/x³ = (x + 1/x)³ − 3(x + 1/x) = 27 − 9 = 18.
8The roots of x² − 4x + 1 = 0 are:
A.2 ± √3
B.2 ± √2
C.4 ± √3
D.±2
Explanation: x = [4 ± √(16 − 4)]/2 = [4 ± √12]/2 = [4 ± 2√3]/2 = 2 ± √3.
9If one root of x² − kx + 12 = 0 is 3, then k equals:
A.7
B.4
C.9
D.15
Explanation: If 3 is a root, 9 − 3k + 12 = 0 → 21 − 3k = 0 → k = 7. Alternatively, product of roots = 12 so other root = 4 and sum = 7 = k.
10Factorise completely over the reals: x³ − 8.
A.(x − 2)(x² + 2x + 4)
B.(x − 2)(x² − 2x + 4)
C.(x + 2)(x² − 2x + 4)
D.(x − 2)³
Explanation: Difference of cubes: a³ − b³ = (a − b)(a² + ab + b²) with a = x, b = 2 yields (x − 2)(x² + 2x + 4).

About the BSEB Matric Adv Math (Opt) Practice Questions

Verified exam format metadata for Bihar School Examination Board (BSEB) Matric Advanced Mathematics — Optional (Class 10 / model 114 OPT-ADV.MATH) is pending. The practice questions above remain available while official exam length, timing, passing score, fee, and administrator details are reviewed.