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100+ Free Odisha BSE Madhyama Mathematics Practice Questions

Board of Secondary Education, Odisha (BSE Odisha) Madhyama Class X Mathematics (MATH) — Sanskrit pathway practice questions are available now; exam metadata is being verified.

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Key Facts: Odisha BSE Madhyama Mathematics Exam

Class X Madhyama

Sanskrit pathway secondary Mathematics under BSE Odisha

BSE Odisha Madhyama regulations / subject list

Mixed paper

Official format is objective + subjective (HSC-style), not pure MCQ

BSE Odisha Madhyama / Class X board pattern practice

Fee in Madhyama fee

Mathematics included in Madhyama exam fee as notified

BSE Odisha Madhyama fee / form-fill-up circulars

bseodisha.nic.in

Primary official portal for Madhyama syllabus, pattern, and schedules

Board of Secondary Education, Odisha

Class 10 scope

Algebra, geometry, mensuration, trig, statistics, probability

Madhyama Class X Mathematics syllabus scope

English MCQ adaptation

This free local bank is not the official mixed paper format

OpenExamPrep practice policy

BSE Odisha Madhyama

Administrator body for Madhyama Class X Mathematics

Board of Secondary Education, Odisha

BSE Odisha Madhyama Class X Mathematics is a Sanskrit-pathway board subject with mixed objective + subjective paper (HSC-style). Fee is included in the Madhyama exam fee as notified. Pass marks follow the year’s Madhyama circular. This free 2026 bank is an English MCQ study adaptation — not an official paper simulation.

Sample Odisha BSE Madhyama Mathematics Practice Questions

Try these sample questions to test your Odisha BSE Madhyama Mathematics exam readiness. Each question includes a detailed explanation. Start the interactive quiz above for the full 100+ question experience with AI tutoring.

1Using Euclid's division algorithm, HCF(867, 255) is:
A.51
B.17
C.85
D.15
Explanation: 867 = 255×3 + 102; 255 = 102×2 + 51; 102 = 51×2 + 0. Last non-zero remainder is 51, so HCF = 51.
2If a = 2³ × 3² × 5 and b = 2 × 3³ × 7, then HCF(a, b) is:
A.2 × 3
B.2 × 3²
C.2³ × 3³
D.2³ × 3² × 5 × 7
Explanation: HCF takes minimum exponents of common primes: 2¹ × 3², written 2 × 3².
3If a = 2³ × 3² × 5 and b = 2 × 3³ × 7, then LCM(a, b) is:
A.2³ × 3³ × 5 × 7
B.2 × 3²
C.2⁴ × 3⁵ × 35
D.2³ × 3² × 5
Explanation: LCM takes maximum exponents: 2³ × 3³ × 5 × 7.
4The decimal expansion of 7/8 is:
A.0.875 (terminating)
B.Non-terminating non-repeating
C.0.777… only
D.An irrational expansion
Explanation: 7/8 = 0.875. Denominator in lowest terms is 2³, so the decimal terminates.
5Which of the following is irrational?
A.√4
B.√9 / √25
C.√2
D.0.25
Explanation: √2 cannot be written as a ratio of integers. √4 = 2, √9/√25 = 3/5, and 0.25 = 1/4 are rational.
6If HCF(a, b) = 12 and a × b = 1800, then LCM(a, b) is:
A.150
B.120
C.180
D.240
Explanation: For positive integers, HCF × LCM = a × b. LCM = 1800 / 12 = 150.
7The largest number that divides 70 and 125 leaving remainders 5 and 8 respectively is:
A.13
B.65
C.15
D.25
Explanation: Required number divides 70−5 = 65 and 125−8 = 117. HCF(65, 117): 117 = 65×1 + 52; 65 = 52×1 + 13; 52 = 13×4 + 0. So the number is 13.
8If α and β are zeros of x² − 5x + 6, then α + β equals:
A.5
B.6
C.−5
D.1
Explanation: For x² − (sum)x + product, sum of zeros = 5.
9If α and β are zeros of x² − 5x + 6, then αβ equals:
A.5
B.6
C.−6
D.1
Explanation: Product of zeros = constant / leading coefficient = 6.
10A quadratic polynomial whose zeros are 2 and −3 is:
A.x² + x − 6
B.x² − x − 6
C.x² + 5x − 6
D.x² − 5x + 6
Explanation: Sum = −1, product = −6. Polynomial x² − (sum)x + product = x² + x − 6.

About the Odisha BSE Madhyama Mathematics Practice Questions

Verified exam format metadata for Board of Secondary Education, Odisha (BSE Odisha) Madhyama Class X Mathematics (MATH) — Sanskrit pathway is pending. The practice questions above remain available while official exam length, timing, passing score, fee, and administrator details are reviewed.