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Panhellenic Economic & Computer Studies (Οικονομικών & Πληροφορικής) Track (Greece)

Practice Questions100 questions

Exam Review

Key Facts: Panhellenic Health Sciences Exam

Field 3

Scientific Field Designation

Ministry of Education (ΥΠΑΙΘΑ)

3 Papers

Orientation Subjects Examined

Central Examination Committee (ΚΕΕ)

180 min

Duration Per Subject Paper

Panhellenic Regulations

€0

Examination Fee

Greek Public Education System

The Panhellenic Health Sciences track governs admission to all Greek medical, dental, pharmaceutical, and biological faculties. Administered by ΥΠΑΙΘΑ, candidates sit three 3-hour national papers in Biology, Chemistry, and Physics. The examination is free in the public school system, with admission demanding near-perfect scores across molecular genetics, biochemical equilibria, and physical mechanics.

Sample Panhellenic Health Sciences Practice Questions

Try these sample questions to review concepts for the Panhellenic Health Sciences exam. Each question includes a detailed explanation. Start the interactive quiz above for the full 100+ question experience with AI tutoring.

1During DNA replication in Escherichia coli, which enzyme is primarily responsible for unwinding the double helix at the replication fork by breaking hydrogen bonds between complementary base pairs?

A.DNA helicase (DnaB)

B.DNA topoisomerase (DNA gyrase)

C.Single-stranded DNA-binding protein (SSB)

D.DNA primase (DnaG)

Explanation: DNA helicase (specifically DnaB in E. coli) utilizes energy derived from ATP hydrolysis to break the hydrogen bonds holding the two antiparallel strands together, thereby unwinding the double helix and advancing the replication fork.

2DNA polymerase III in prokaryotes possesses both 5'→3' polymerase and 3'→5' exonuclease activities. What critical physiological function is mediated specifically by its 3'→5' exonuclease activity?

A.Removal of ribonucleotide primers on the lagging strand during maturation

B.Proofreading by excising incorrectly paired terminal nucleotides immediately after incorporation

C.Nick translation along damaged DNA templates during nucleotide excision repair

D.Degradation of RNA transcripts following transcription termination

Explanation: The 3'→5' exonuclease domain of DNA polymerase III functions as a proofreading mechanism. When an incorrect nucleotide is incorporated, the mismatched 3' terminus stalls the polymerase; the exonuclease clips off the incorrect mononucleotide in the reverse 3'→5' direction, allowing synthesis to resume with high fidelity.

3On the lagging strand during eukaryotic DNA replication, synthesis occurs discontinuously in Okazaki fragments. Which sequence of enzymatic events correctly describes the completion and sealing of adjacent Okazaki fragments?

A.DNA ligase joins the RNA primer to DNA; telomerase extends the repetitive 3' overhang; helicase terminates synthesis

B.DNA Pol δ displaces the 5' end of the preceding RNA primer creating a flap, FEN1 cleaves the flap, and DNA ligase I catalyzes phosphodiester bond synthesis

C.DNA Pol III hydrolyzes the RNA primer via its 3'→5' exonuclease, DNA Pol II fills the gap, and topoisomerase seals the nick

D.Reverse transcriptase converts RNA primers into DNA, and DNA recombinase covalently fuses the duplex ends

Explanation: In eukaryotes, lagging-strand synthesis is conducted by DNA polymerase δ. When Pol δ encounters the 5' terminus of the downstream Okazaki fragment, it displaces the RNA primer and initial DNA segment into a single-stranded flap. Flap endonuclease 1 (FEN1) cleaves this flap, and DNA ligase I subsequently catalyzes the formation of a phosphodiester bond between the adjacent 3'-OH and 5'-phosphate groups.

4A circular bacterial chromosome contains 4.8 × 10⁶ base pairs and replicates bidirectionally from a single origin of replication (oriC). If each replication fork advances at a constant rate of 800 base pairs per second, how long will it take for the bacterium to replicate its entire chromosome?

A.50 minutes

B.100 minutes

C.25 minutes

D.12.5 minutes

Explanation: Because replication is bidirectional from a single origin, there are 2 replication forks advancing in opposite directions. The total rate of DNA synthesis by both forks combined is 2 × 800 bp/s = 1,600 bp/s. The total time required is: t = (4.8 × 10⁶ bp) / (1,600 bp/s) = 3,000 seconds. Converting to minutes: 3,000 s / 60 s/min = 50 minutes.

5In prokaryotic transcription, which component of the RNA polymerase holoenzyme is directly responsible for specifically recognizing the promoter region at the -10 (Pribnow box) and -35 consensus sequences?

A.Beta (β) catalytic subunit

B.Beta-prime (β') catalytic subunit

C.Sigma (σ) factor

D.Alpha (α) subunit dimer

Explanation: The core RNA polymerase enzyme (α2ββ'ω) possesses catalytic activity but lacks sequence-specific DNA-binding capability. Association with the sigma (σ) factor forms the complete holoenzyme, wherein the σ factor specifically recognizes and binds the -35 and -10 promoter consensus elements, positioning the polymerase at the transcription start site (+1).

6A segment of the DNA template (antisense) strand reads: 3'-TAC-GGC-TTA-CTA-ACT-5'. Which sequence represents the primary RNA transcript produced from this segment, oriented in the standard 5'→3' direction?

A.5'-AUG-CCG-AAU-GAU-UGA-3'

B.5'-UCA-AUC-AUU-CGG-CAU-3'

C.5'-AUG-CCG-AAT-GAT-TGA-3'

D.5'-TAC-GGC-TTA-CTA-ACT-3'

Explanation: RNA polymerase reads the template strand in the 3'→5' direction and synthesizes RNA antiparallel in the 5'→3' direction. Complementary base pairing rules dictate: 3'-T→5'-A, 3'-A→5'-U, 3'-C→5'-G, 3'-G→5'-C. Applying this triplet by triplet: 3'-TAC-5' → 5'-AUG-3'; 3'-GGC-5' → 5'-CCG-3'; 3'-TTA-5' → 5'-AAU-3'; 3'-CTA-5' → 5'-GAU-3'; 3'-ACT-5' → 5'-UGA-3'. Resulting transcript: 5'-AUG-CCG-AAU-GAU-UGA-3'.

7Which chemical modification occurs cotranscriptionally at the 5' terminus of eukaryotic pre-mRNA, and what is its primary structural feature?

A.Addition of a polyadenine tract consisting of 200–250 adenylate residues via a 3'-5' phosphodiester linkage

B.Addition of 7-methylguanosine linked via an unusual 5'-to-5' triphosphate bridge

C.Methylation of cytosine residues at CpG islands to repress ribosomal binding

D.Enzymatic conversion of uridine into pseudouridine catalyzed by snRNPs

Explanation: The 5' cap of eukaryotic pre-mRNA consists of a 7-methylguanosine (m7G) residue attached to the first transcribed nucleotide via a unique 5'→5' triphosphate bridge. This modification protects the transcript from 5' exonucleolytic degradation, facilitates nuclear export, and serves as the primary recognition site for the eIF4E translation initiation factor.

8A eukaryotic gene consists of 6 exons (E1 to E6) and 5 intervening introns. If alternative splicing permits any combination of the internal exons (E2, E3, E4, E5) to be independently included or skipped, but constitutive exons E1 and E6 must always be present at the 5' and 3' ends respectively, and the order of exons cannot be rearranged, how many distinct mature mRNA isoforms can theoretically be produced?

A.16

B.64

C.8

D.32

Explanation: Constitutive exons E1 and E6 are fixed (1 choice each). The 4 internal exons (E2, E3, E4, E5) are independent binary choices: each can either be included (1) or excluded/skipped (0). Therefore, the total number of unique exon combinations is 2⁴ = 16 distinct mature mRNA isoforms.

9The genetic code is described as 'degenerate' (or redundant). What does this term specifically mean in molecular genetics?

A.A single codon can specify several different amino acids depending on cellular conditions

B.Different codons can specify the same amino acid

C.Over evolutionary time, codons lose their functional coding capacity and degenerate into introns

D.Codons overlap such that a single nucleotide is shared across adjacent reading frames

Explanation: Degeneracy of the genetic code means that multiple distinct triplet codons (synonymous codons) can code for the same single amino acid. For instance, leucine and arginine are each encoded by 6 different codons, and glycine by 4 codons.

10According to Crick's Wobble Hypothesis, non-Watson-Crick base pairing can occur between which positions of the mRNA codon and the tRNA anticodon?

A.The 1st base (5' end) of the mRNA codon and the 3rd base (3' end) of the tRNA anticodon

B.The 3rd base (3' end) of the mRNA codon and the 1st base (5' end) of the tRNA anticodon

C.The 2nd base of both the mRNA codon and the tRNA anticodon

D.Any position along the codon-anticodon duplex when inosine is present in mRNA

Explanation: The wobble hypothesis posits that spatial constraints are relaxed at the 3rd position (3' end) of the mRNA codon, allowing non-standard base pairing with the 1st position (5' end) of the tRNA anticodon. For example, a 5'-G in the anticodon can pair with either 3'-C or 3'-U in the codon, and a 5'-inosine (I) can pair with 3'-U, 3'-C, or 3'-A.

About the Panhellenic Health Sciences Exam

The Panhellenic Health Sciences (Σπουδών Υγείας) track is the competitive national entrance route for admission to Greek faculties of Medicine, Dentistry, Pharmacy, Veterinary Medicine, Nursing, Physiotherapy, and Molecular Biology (3rd Scientific Field / 3ο Επιστημονικό Πεδίο). Candidates sit three specialized national papers: Biology, Chemistry, and Physics, alongside the mandatory common core paper in Modern Greek Language & Literature. Our practice bank provides an English-language MCQ study adaptation delivering detailed genetics calculations, molecular biology mechanisms, equilibrium problems, and physical biophysics scenarios.

Exam sponsor: Ministry of Education, Religious Affairs and Sports (Υπουργείο Παιδείας, Θρησκευμάτων και Αθλητισμού - ΥΠΑΙΘΑ). The requirements and fees below concern the certification or admission exam, separate from our free practice resources.

Questions

12 questions

Time Limit

180 minutes per paper (3 papers: Biology, Chemistry, Physics)

Passing Score

Calculated via departmental Minimum Admission Base (EBE) and competitive ranking up to 20,000 admission points (μόρια)

Exam / Certification Fees

€0 (Free for Greek public secondary students and registered candidates)

Exam sponsor website

Fees, eligibility, and exam policies can change. Confirm them with the exam sponsor before applying or paying.

Official sources

Our practice resources: topics covered

We aim to reflect publicly available exam outlines and topic information in our study resources. Coverage, format, and difficulty may differ from the actual exam, and we cannot guarantee that every detail is accurate or current. Confirm exam requirements, fees, and policies with the official exam sponsor.

40%

Molecular Genetics, Heredity and Biotechnology

Replication, transcription and translation, regulation of gene expression, recombinant DNA technology and PCR, Mendelian and sex-linked inheritance, mutations, and applications of biotechnology in medicine and agriculture.

30%

Chemical Kinetics, Acid-Base Equilibria & Organic Reactions

Rate laws, activation energy, buffer system calculations, amino acids and peptide bonding, and organic functional group transformations.

30%

Oscillations, Waves, Collisions, Electromagnetism and Quantum Mechanics

Simple harmonic and damped motion, standing waves, elastic and inelastic collisions, magnetic fields and induction, alternating current, and the photoelectric effect, matter waves and the uncertainty principle.

Preparing for the Panhellenic Health Sciences Exam

What You Need to Know

Passing score: Calculated via departmental Minimum Admission Base (EBE) and competitive ranking up to 20,000 admission points (μόρια)
Exam length: 12 questions
Time limit: 180 minutes per paper (3 papers: Biology, Chemistry, Physics)
Exam / certification fees: €0 (Free for Greek public secondary students and registered candidates) Official sources

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Panhellenic Health Sciences: Suggested Study Strategy

1Master the enzymatic machinery of replication, transcription and translation, and be able to read a DNA or messenger RNA sequence in the correct direction

2Practise pedigree problems that distinguish autosomal dominant, autosomal recessive and X-linked inheritance, and be ready for restriction-map and PCR calculations

3Calculate the pH of weak acids, weak bases, salts and buffers, and follow the shape of a weak acid-strong base titration curve to the equivalence point

4Work through the quantum block of the physics paper: photon energy, the photoelectric equation and stopping potential, the Compton shift and the de Broglie wavelength

Frequently Asked Questions

Which university faculties correspond to the Health Sciences track?

The 3rd Scientific Field includes Greece's seven prestigious Medical schools (Athens, Thessaloniki, Patras, Ioannina, Crete, Thessaly, Thrace), Dentistry, Pharmacy, Veterinary Medicine, Biology, and all allied healthcare disciplines.

How does the Health Sciences track differ from the Exact Sciences track?

Health Sciences candidates examine in Biology, Chemistry, and Physics, whereas Exact Sciences candidates examine in Advanced Mathematics, Chemistry, and Physics.

How important is Biology in the scoring formula for Medical schools?

Biology carries the highest weight coefficient for Medical faculties (typically 30–35%), making perfection on molecular genetics and physiological concepts essential.

Does this practice bank include genetic calculations and pedigrees?

Yes. Our practice bank includes rigorous genetic probability questions, restriction enzyme mapping, PCR cycle calculations, and buffer pH problems reflecting the Greek national curriculum.