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2026 Statistics
Key Facts: Castilla-La Mancha PAU Technology and Engineering II (Tecnología e Ingeniería II - UCLM 2026) Exam
90 min
Official PAU Technology and Engineering II exam duration
Tribunal PAU Universidad de Castilla-La Mancha
EUR 52.99
Ordinary registration fee for the Access Phase
Universidad de Castilla-La Mancha (UCLM)
0–10
Grading scale (minimum 4.0 to be weighted)
Normativa PAU UCLM
5 Blocks
Materials, Thermodynamics, Fluid Power, Control/Logic, and Robotics/Manufacturing
Temario Oficial 2º Bachillerato UCLM
100
Practice questions in this assessment bank
OpenExamPrep
Prepare for the UCLM 2026 PAU Technology and Engineering II exam with 100 high-quality practice questions covering materials, thermodynamics, fluid power, logic/control systems, and manufacturing robotics. This English-language multiple-choice bank is a study adaptation of the official written PAU paper, not a replica of it.
Sample Castilla-La Mancha PAU Technology and Engineering II (Tecnología e Ingeniería II - UCLM 2026) Practice Questions
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1A cylindrical steel test bar with an initial diameter of 10 mm is subjected to a static axial tensile load of 20 kN. What is the normal tensile stress (σ) induced in the cross-section of the specimen?
A.254.65 MPa
B.63.66 MPa
C.200.00 MPa
D.636.62 MPa
Explanation: Normal tensile stress is given by σ = F / A0. The initial cross-sectional area is A0 = π · d² / 4 = π · (10 mm)² / 4 = 78.54 mm². Converting 20 kN to 20,000 N: σ = 20,000 N / 78.54 mm² = 254.65 N/mm² = 254.65 MPa.
2A metal structural rod with an original gauge length of 250 mm elongates by 0.5 mm under an axial tensile force within its elastic limit. What is the engineering unit strain (ε) of the rod?
A.0.02 (2.0%)
B.0.002 (0.2%)
C.0.0005 (0.05%)
D.0.005 (0.5%)
Explanation: Engineering unit strain is defined as ε = ΔL / L0. Dividing the elongation by initial length: ε = 0.5 mm / 250 mm = 0.002, which corresponds to 0.2%.
3During a tensile test within the elastic region, a metallic specimen experiences a tensile stress of 420 MPa and a strain of 0.002. What is the Young's modulus (modulus of elasticity, E) of the material?
A.420 GPa
B.84 GPa
C.210 GPa
D.21 GPa
Explanation: According to Hooke's Law (σ = E · ε), Young's modulus is E = σ / ε = 420 MPa / 0.002 = 210,000 MPa = 210 GPa.
4In the standard Brinell hardness test formula HB = 2P / [π · D · (D - √(D² - d²))], what do the parameters P, D, and d represent?
A.P is applied load in N, D is indentation depth in mm, and d is indenter radius in mm.
B.P is penetration depth in mm, D is ball diameter in mm, and d is applied load in N.
C.P is hydraulic pressure in bar, D is specimen diameter in mm, and d is ball diameter in mm.
D.P is applied load in kgf, D is hard steel ball diameter in mm, and d is indentation diameter in mm.
Explanation: In the Brinell test (HB), P represents the applied test load in kilograms-force (kgf), D is the spherical indenter diameter in millimeters (mm), and d is the arithmetic mean diameter of the spherical impression left on the material surface in millimeters (mm).
5A Charpy impact test is performed on a notched specimen with a cross-sectional area at the notch of S = 0.8 cm². The pendulum absorbs 60 J of energy upon breaking the specimen. What is the impact toughness (resilience, KCV)?
A.75 J/cm²
B.48 J/cm²
C.7.5 J/cm²
D.120 J/cm²
Explanation: Charpy impact toughness (resilience) is calculated as KCV = E_absorbed / S. Substituting the given values: KCV = 60 J / 0.8 cm² = 75 J/cm².
6In the equilibrium iron-carbon (Fe-Fe3C) phase diagram, what carbon mass percentage conventionally separates carbon steels (aceros) from cast irons (fundiciones)?
A.0.77% C
B.2.11% C
C.4.30% C
D.0.022% C
Explanation: In the Fe-Fe3C phase diagram, alloys containing up to 2.11% C by weight are classified as steels (aceros), whereas ferrous alloys with carbon concentrations between 2.11% and 6.67% C are classified as cast irons (fundiciones).
7A cylindrical steel tie rod with a diameter of 12 mm is subjected to tension. If the steel has a yield strength (σy) of 350 MPa, what is the maximum tensile force the rod can withstand without permanent plastic deformation?
A.126.65 kN
B.50.89 kN
C.39.58 kN
D.12.67 kN
Explanation: To avoid permanent deformation, the load must not exceed yield force Fy = σy · A0. The cross-sectional area is A0 = π · (12 mm)² / 4 = 113.10 mm². Fy = 350 N/mm² · 113.10 mm² = 39,584.1 N ≈ 39.58 kN.
8A Brinell hardness test is conducted using a 10 mm diameter steel ball indenter under a load of 3000 kgf. The diameter of the resulting indentation is measured as 4.0 mm. What is the Brinell Hardness number (HB)?
A.312.4 HB
B.238.7 HB
C.189.5 HB
D.228.7 HB
Explanation: Brinell hardness formula: HB = 2P / [π · D · (D - √(D² - d²))]. Substituting P = 3000 kgf, D = 10 mm, d = 4.0 mm: √(D² - d²) = √(100 - 16) = √84 = 9.16515 mm. Then (D - √(D² - d²)) = 10 - 9.16515 = 0.83485 mm. HB = 6000 / [π · 10 · 0.83485] = 6000 / 26.2274 = 228.77 HB ≈ 228.7 HB.
9A Charpy pendulum hammer of mass m = 20 kg is released from a height of h1 = 1.5 m. After fracturing a V-notched specimen with a notch cross-section of S = 0.8 cm², the hammer rises to a height of h2 = 0.6 m. Taking g = 9.8 m/s², calculate the impact toughness (resilience, KCV) of the material.
A.220.5 J/cm²
B.367.5 J/cm²
C.147.0 J/cm²
D.176.4 J/cm²
Explanation: Energy absorbed by specimen: E = m · g · (h1 - h2) = 20 kg · 9.8 m/s² · (1.5 m - 0.6 m) = 196 N · 0.9 m = 176.4 J. Impact resilience KCV = E / S = 176.4 J / 0.8 cm² = 220.5 J/cm².
10A binary alloy composed of components A and B contains 40% of B overall. At temperature T1, the alloy separates into a solid phase α containing 10% B and a liquid phase L containing 60% B. Applying the lever rule (regla de la palanca), what is the mass fraction of the solid phase α?
A.60.0%
B.40.0%
C.50.0%
D.33.3%
Explanation: According to the lever rule, the mass fraction of solid phase α is f_α = (w_L - w_0) / (w_L - w_α), where w_0 = 40%, w_L = 60%, and w_α = 10%. f_α = (60 - 40) / (60 - 10) = 20 / 50 = 0.40 = 40.0%.
About the Castilla-La Mancha PAU Technology and Engineering II (Tecnología e Ingeniería II - UCLM 2026) Practice Questions
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