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1An office space in New Cairo has a calculated peak sensible cooling load of 48 kW. The indoor design condition specified by the Egyptian Code for Air Conditioning (ECP 301) is 24°C dry bulb. If supply air enters the room at 14°C dry bulb and standard air properties apply (density ρ = 1.20 kg/m³, specific heat c_p = 1.005 kJ/kg·K), what is the required supply airflow rate?

A.3.98 m³/s (approx. 14,330 m³/h)

B.2.85 m³/s (approx. 10,260 m³/h)

C.5.12 m³/s (approx. 18,430 m³/h)

D.6.24 m³/s (approx. 22,460 m³/h)

Explanation: The room sensible heat equation is Q_s = m_dot * c_p * ΔT = ρ * V_dot * c_p * (T_room - T_supply). Rearranging for volumetric flow gives V_dot = Q_s / [ρ * c_p * (T_room - T_supply)] = 48 kW / [1.20 kg/m³ * 1.005 kJ/kg·K * (24 - 14) K] = 48 / 12.06 = 3.98 m³/s. Multiplying by 3,600 s/h yields 14,328 m³/h (approx. 14,330 m³/h).

2A multi-purpose conference hall has a calculated room sensible cooling load of 140 kW and a room latent cooling load of 60 kW. What is the Sensible Heat Ratio (SHR) of the conditioned space, and what is its thermodynamic significance on the psychrometric chart?

A.SHR = 0.70; it defines the slope of the room condition line connecting the room state to the apparatus dew point (ADP).

B.SHR = 0.43; it establishes the ratio of latent heat to sensible heat for dehumidification coil sizing.

C.SHR = 2.33; it defines the fan motor heat dissipation ratio relative to envelope transmission.

D.SHR = 0.58; it indicates that the entering coil wet-bulb temperature is identical to the room dew point.

Explanation: Sensible Heat Ratio is defined as SHR = Q_sensible / Q_total = Q_sensible / (Q_sensible + Q_latent) = 140 / (140 + 60) = 140 / 200 = 0.70. On the psychrometric chart, the SHR protractor defines the directional slope of the room condition line drawn through the room design state point to intersect the saturation curve at the Apparatus Dew Point (ADP).

3Under the Egyptian Code for Air Conditioning (ECP 301), which outdoor design climatic parameters are standard for peak summer cooling load calculations in the Greater Cairo climatic zone at the 1% frequency level?

A.40.0°C Dry Bulb and 21.0°C Coincident Wet Bulb

B.35.0°C Dry Bulb and 28.0°C Coincident Wet Bulb

C.46.0°C Dry Bulb and 26.0°C Coincident Wet Bulb

D.32.0°C Dry Bulb and 18.0°C Coincident Wet Bulb

Explanation: ECP 301 specifies summer outdoor design conditions for Greater Cairo as 40.0°C dry bulb with a coincident wet bulb of 21.0°C (reflecting Cairo's hot, dry summer continental climate at the 1% annual frequency level). Coastal cities like Alexandria have lower dry bulb (e.g., 33-35°C) but significantly higher wet bulb (e.g., 24-26°C).

4A water-cooled centrifugal chiller selected for a commercial development in the New Administrative Capital has a nominal cooling capacity of 500 Tons of Refrigeration (TR). At full design load, the chiller compressor consumes 290 kW of electrical power. What are the chiller's Coefficient of Performance (COP) and its specific electrical power consumption in kW/TR?

A.COP = 6.06 and specific power = 0.58 kW/TR

B.COP = 4.85 and specific power = 0.72 kW/TR

C.COP = 3.52 and specific power = 1.00 kW/TR

D.COP = 7.20 and specific power = 0.49 kW/TR

Explanation: One Ton of Refrigeration (TR) equals 3.51685 kW of thermal cooling capacity. Total cooling rate Q_cool = 500 * 3.51685 kW = 1,758.4 kW. The Coefficient of Performance is COP = Q_cool / P_elec = 1,758.4 / 290 = 6.06. Specific power consumption is P_elec / TR = 290 kW / 500 TR = 0.58 kW/TR. Note that COP = 3.51685 / (kW/TR) = 3.51685 / 0.58 = 6.06.

5A central cooling plant serves a hospital with a design cooling load of 300 TR. The chilled water system operates with a supply temperature of 6.5°C and a return temperature of 12.5°C (ΔT = 6.0°C). Assuming water specific heat c_p = 4.186 kJ/kg·K and density ρ = 1,000 kg/m³, what is the design chilled water circulation flow rate in m³/h and US GPM?

A.150.8 m³/h (approx. 664 GPM)

B.100.5 m³/h (approx. 443 GPM)

C.201.1 m³/h (approx. 885 GPM)

D.75.4 m³/h (approx. 332 GPM)

Explanation: Cooling capacity Q = 300 TR * 3.51685 kW/TR = 1,055.05 kW. Using Q = m_dot * c_p * ΔT, mass flow rate m_dot = 1,055.05 kW / [4.186 kJ/kg·K * 6.0 K] = 1,055.05 / 25.116 = 41.90 kg/s. In volumetric terms: V_dot = 41.90 L/s * 3.6 = 150.84 m³/h. Converting to US GPM: 150.84 * 4.4029 = 664.1 GPM.

6In an open-circuit cooling tower system operating under Egyptian summer conditions, water enters the tower at 35.0°C and leaves at 29.5°C while the ambient wet-bulb temperature is 24.0°C. What are the cooling tower's 'Range' and 'Approach'?

A.Range = 5.5°C; Approach = 5.5°C

B.Range = 11.0°C; Approach = 5.5°C

C.Range = 5.5°C; Approach = 11.0°C

D.Range = 8.0°C; Approach = 2.5°C

Explanation: Cooling tower Range is the difference between the hot water entering temperature and the cold water leaving temperature: Range = T_in - T_out = 35.0°C - 29.5°C = 5.5°C. Cooling tower Approach is the difference between the cold water leaving temperature and the ambient wet-bulb temperature: Approach = T_out - T_wb = 29.5°C - 24.0°C = 5.5°C.

7When designing low-velocity supply air ductwork for commercial office buildings in accordance with ECP 301 and SMACNA standards using the Equal Friction method, what is the standard recommended design friction loss rate?

A.0.8 to 1.0 Pa/m (0.08 to 0.10 in. wg / 100 ft)

B.3.5 to 5.0 Pa/m (0.35 to 0.50 in. wg / 100 ft)

C.0.05 to 0.10 Pa/m (0.005 to 0.01 in. wg / 100 ft)

D.8.0 to 12.0 Pa/m (0.80 to 1.20 in. wg / 100 ft)

Explanation: In standard commercial HVAC design under ECP 301 and SMACNA, the Equal Friction design rate for supply ductwork is maintained between 0.8 and 1.0 Pa per linear meter (equivalent to 0.08 to 0.10 inches water gauge per 100 feet). This balances duct fabrication material cost against operating fan energy and aerodynamic regenerated noise.

8What is the primary thermodynamic principle of the Static Regain method for sizing supply air duct systems in high-rise buildings?

A.Air velocity is deliberately reduced after each takeoff so that dynamic pressure converts into static pressure, offsetting downstream friction loss.

B.Static pressure is maintained perfectly constant by increasing airflow velocity toward the terminal diffusers.

C.Total pressure is kept constant across all branches by installing motorized volume dampers at every branch connection.

D.Friction loss per unit length is doubled in each successive duct section to eliminate terminal damper throttling.

Explanation: The Static Regain method sizes ductwork so that the reduction in velocity pressure after each branch takeoff (due to expanding duct area relative to airflow) is converted into static pressure (ΔP_regain = R * (ρ/2) * [V1² - V2²], where R is typically 0.75). This regained static pressure ideally balances the friction loss in the subsequent duct section, ensuring nearly equal static pressure at every terminal takeoff.

9A backward-curved centrifugal supply air fan rotates at 1,450 RPM, delivering 10,000 m³/h against an external static pressure of 400 Pa while drawing 2.20 kW of shaft power. If the motor pulley is adjusted to increase fan speed by 10% to 1,595 RPM, what are the new airflow, static pressure, and shaft power according to fan affinity laws?

A.Airflow = 11,000 m³/h; Static Pressure = 484 Pa; Shaft Power = 2.93 kW

B.Airflow = 11,000 m³/h; Static Pressure = 440 Pa; Shaft Power = 2.42 kW

C.Airflow = 12,100 m³/h; Static Pressure = 484 Pa; Shaft Power = 3.25 kW

D.Airflow = 10,500 m³/h; Static Pressure = 420 Pa; Shaft Power = 2.66 kW

Explanation: Applying fan affinity laws: Flow varies directly with speed ratio: Q2 = Q1 * (N2/N1) = 10,000 * 1.10 = 11,000 m³/h. Pressure varies with the square of speed: P2 = P1 * (N2/N1)² = 400 * (1.10)² = 400 * 1.21 = 484 Pa. Shaft power varies with the cube of speed: W2 = W1 * (N2/N1)³ = 2.20 * (1.10)³ = 2.20 * 1.331 = 2.928 kW (approx. 2.93 kW).

10An open-plan office space has a net usable floor area of 600 m² and is designed for an occupancy of 50 persons. Using the Ventilation Rate Procedure of ASHRAE Standard 62.1 and ECP 301, where the outdoor air requirements for office space are R_p = 2.5 L/s·person and R_a = 0.3 L/s·m², what is the minimum outdoor airflow required in the breathing zone (V_bz)?

A.305 L/s (approx. 1,098 m³/h)

B.125 L/s (approx. 450 m³/h)

C.180 L/s (approx. 648 m³/h)

D.425 L/s (approx. 1,530 m³/h)

Explanation: According to ASHRAE 62.1 and ECP 301, breathing zone outdoor airflow is calculated as: V_bz = (R_p * P_z) + (R_a * A_z). Here, people outdoor air = 50 persons * 2.5 L/s·person = 125 L/s. Area outdoor air = 600 m² * 0.3 L/s·m² = 180 L/s. Total breathing zone outdoor air V_bz = 125 + 180 = 305 L/s. In m³/h: 305 * 3.6 = 1,098 m³/h.

About the Egypt Engineering Consultant Mechanical Exam

The Egyptian Engineers Syndicate (EEA) grants the consultant engineer title (لقب مهندس استشاري) in Mechanical Engineering across specialties including mechanical design, HVAC/MEP systems, production, power plants, maintenance, and safety. Mechanical Division requirements mandate documented responsibility for a major engineering project and submission of its comprehensive calculation note (النوتة الحسابية للمشروع). Under the July 2025 Regulation (Articles 65, 68, and 69), candidates must achieve at least 70% on both the branch evaluation and the 15-part consultant interview rubric. This bank is an English-language MCQ study adaptation of the technical, code, and interview knowledge, not an official translation or simulation of the committee defense.

Exam sponsor: Egyptian Engineers Syndicate (نقابة المهندسين المصرية). The requirements and fees below concern the certification or admission exam, separate from our free practice resources.

Assessment

Under Mechanical Division rules and the July 2025 EEA Engineering Profession Practice Regulation, candidates must possess 15 years experience, 8 years as a specialist, 250 qualification points, submit detailed project calculation notes, and achieve at least 70% on both the branch evaluation and the 100-point consultant interview. This bank provides 100 multiple-choice questions adapting the core technical, regulatory, and rubric knowledge.

Time Limit

Not published for the written/technical evaluation; committee interview time is scheduled per applicant by the Mechanical Division Consultant Committee.

Passing Score

70% on the branch professional evaluation and 70% on the committee interview

Exam / Certification Fees

Not published (determined by Egyptian Engineers Syndicate branch fee schedules)

Exam sponsor website

Fees, eligibility, and exam policies can change. Confirm them with the exam sponsor before applying or paying.

Official sources

Our practice resources: topics covered

We aim to reflect publicly available exam outlines and topic information in our study resources. Coverage, format, and difficulty may differ from the actual exam, and we cannot guarantee that every detail is accurate or current. Confirm exam requirements, fees, and policies with the official exam sponsor.

20%

HVAC, Thermal Systems & Ventilation

ECP 301 air conditioning code, cooling loads, psychrometrics, duct design, and central chiller plants.

20%

Fire Protection, Hydraulics & Life Safety

ECP 206 fire fighting code, NFPA sprinkler/standpipe standards, and hydraulic calculations.

15%

Plumbing, Drainage, Water Supply & Medical Gases

Domestic water networks, drainage venting, pump head calculations, and medical gas distribution.

15%

Mechanical Design, Calculation Notes & Machinery

Project calculation notes (النوتة الحسابية), pressure vessels, piping stress, and machine design.

15%

Maintenance, Asset Integrity & Project Management

Condition monitoring, RCM maintenance, commissioning testing, and site supervision.

Power Plants, Boilers, Turbines & OHS

Steam/gas turbines, thermal cycles, industrial safety regulations, and environmental controls.

Syndicate Regulations & Consultant Rubric

EEA 2025 Practice Regulation, Article 69 interview criteria, and professional ethics.

Preparing for the Egypt Engineering Consultant Mechanical Exam

What You Need to Know

Passing score: 70% on the branch professional evaluation and 70% on the committee interview
Assessment: Under Mechanical Division rules and the July 2025 EEA Engineering Profession Practice Regulation, candidates must possess 15 years experience, 8 years as a specialist, 250 qualification points, submit detailed project calculation notes, and achieve at least 70% on both the branch evaluation and the 100-point consultant interview. This bank provides 100 multiple-choice questions adapting the core technical, regulatory, and rubric knowledge.
Time limit: Not published for the written/technical evaluation; committee interview time is scheduled per applicant by the Mechanical Division Consultant Committee.
Exam / certification fees: Not published (determined by Egyptian Engineers Syndicate branch fee schedules) Official sources

Using Our Practice Resources

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Egypt Engineering Consultant Mechanical: Suggested Study Strategy

1Review the calculation steps in your submitted project's calculation note, especially cooling load calculations, hydraulic friction loss, and fire pump head determinations.

2Ensure thorough knowledge of Egyptian codes ECP 301 and ECP 206 alongside international standards (ASHRAE, NFPA 13, NFPA 20).

3Prepare structured responses for the Article 69 consultant interview rubric focusing on engineering decision-making, team leadership, and technology transfer.

Frequently Asked Questions

What is the calculation note requirement for Mechanical Consultant candidates?

The Mechanical Division explicitly mandates that candidates submit the complete engineering calculation note (النوتة الحسابية) for a major project they designed or supervised, demonstrating all thermal, hydraulic, stress, and equipment sizing calculations.

What Egyptian codes govern mechanical engineering consultant practice?

Key codes include the Egyptian Code for Air Conditioning and Refrigeration (ECP 301), the Egyptian Code for Fire Protection in Buildings (ECP 206), the Egyptian Plumbing Code, and Unified Building Law No. 119 of 2008.

Is this practice question bank an official EEA exam?

No. This question bank is an English-language MCQ study adaptation developed to help senior mechanical engineers review technical formulas, Egyptian codes, and consultant interview defense topics. It is not an official translation or an administrative substitute for the Syndicate's assessment.