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100+ Free Saarland Abitur Technik-Mathematik Practice Questions

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Key Facts: Saarland Abitur Technik-Mathematik Exam

Saarland's Technik-Mathematik

Saarland's Technik-Mathematik Abitur (eN) is examined by the Ministerium für Bildung und Kultur (MBK) Saarland under the GOS-VO framework for the Fachrichtung Technik.

GOS-VO Saarland

Trigonometry/technical geometry and diff

Trigonometry/technical geometry and differential calculus together account for the largest share of exam content weighting.

GOS-VO Saarland

Technik-Mathematik is taught in close co

Technik-Mathematik is taught in close coordination with Technische Kommunikation and Physik.

GOS-VO Saarland

Statics calculations, including force eq

Statics calculations, including force equilibrium and moments, are a core applied-mechanics skill tested on this exam.

GOS-VO Saarland

This free practice bank contains 100 que

This free practice bank contains 100 questions covering all major Technik-Mathematik Abitur content areas, including genuine calculation problems.

GOS-VO Saarland

Sample Saarland Abitur Technik-Mathematik Practice Questions

Try these sample questions to test your Saarland Abitur Technik-Mathematik exam readiness. Each question includes a detailed explanation. Start the interactive quiz above for the full 100+ question experience with AI tutoring.

1In a right triangle, which trigonometric ratio is defined as the length of the opposite side divided by the length of the hypotenuse?
A.Sine
B.Cosine
C.Tangent
D.Cotangent
Explanation: Sine is defined as opposite/hypotenuse in a right triangle — the standard SOH from the mnemonic SOH-CAH-TOA.
2In a right triangle, which trigonometric ratio is defined as the length of the adjacent side divided by the length of the hypotenuse?
A.Cosine
B.Sine
C.Tangent
D.Secant
Explanation: Cosine is defined as adjacent/hypotenuse in a right triangle — the CAH from SOH-CAH-TOA.
3A right triangle has a hypotenuse of 10 cm and one angle of 30°. What is the length of the side opposite the 30° angle?
A.5 cm
B.8.66 cm
C.10 cm
D.3 cm
Explanation: Opposite = hypotenuse × sin(30°) = 10 × 0.5 = 5 cm.
4A right triangle has a hypotenuse of 10 cm and one angle of 30°. What is the length of the side adjacent to the 30° angle (to the nearest 0.1 cm)?
A.8.7 cm
B.5.0 cm
C.10.0 cm
D.6.0 cm
Explanation: Adjacent = hypotenuse × cos(30°) = 10 × 0.866 ≈ 8.7 cm.
5A ladder leans against a wall, making a 60° angle with the ground. If the base of the ladder is 2 m from the wall, how long is the ladder (to the nearest 0.1 m)?
A.4.0 m
B.2.0 m
C.3.5 m
D.1.7 m
Explanation: cos(60°) = adjacent/hypotenuse = 2/hypotenuse. Since cos(60°) = 0.5, hypotenuse = 2/0.5 = 4.0 m.
6A technical drawing shows a right triangle with legs of 3 cm and 4 cm. Using the Pythagorean theorem, what is the length of the hypotenuse?
A.5 cm
B.7 cm
C.12 cm
D.25 cm
Explanation: c = √(3² + 4²) = √(9 + 16) = √25 = 5 cm — the classic 3-4-5 right triangle.
7The Pythagorean theorem states that for a right triangle with legs a and b and hypotenuse c:
A.a² + b² = c²
B.a + b = c
C.a × b = c²
D.a² - b² = c²
Explanation: The Pythagorean theorem states that the sum of the squares of the two legs equals the square of the hypotenuse: a² + b² = c².
8An engineer needs to find the height of a tower. Standing 50 m from the base, the angle of elevation to the top is measured as 40°. Using tan(40°) ≈ 0.839, the height of the tower (to the nearest meter) is approximately:
A.42 m
B.50 m
C.32 m
D.65 m
Explanation: tan(40°) = height/distance, so height = 50 × 0.839 ≈ 41.96 m, which rounds to 42 m.
9The sum of the interior angles of any triangle always equals:
A.180°
B.360°
C.90°
D.270°
Explanation: The interior angles of any triangle, regardless of shape, always sum to exactly 180°.
10A regular hexagon (6 equal sides) has interior angles that each measure:
A.120°
B.90°
C.60°
D.180°
Explanation: Sum of interior angles = (n−2) × 180° = (6−2) × 180° = 720°. Divided equally among 6 angles: 720°/6 = 120°.

About the Saarland Abitur Technik-Mathematik Practice Questions

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