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100+ Free Saarland Abitur Mathematics Practice Questions

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2026 Statistics

Key Facts: Saarland Abitur Mathematics Exam

Compulsory Kernfach

Mathematik is one of three Kernfächer every Saarland Abitur candidate must take as a written Prüfungsfach

GOS-VO Saarland

270–300 / 210–240 min

Written exam time: Leistungsfach 270–300 minutes, Grundfach 210–240 minutes

GOS-VO Saarland written-exam time bands

06.05.2026

Fixed statewide written main date for Mathematik in the 2026 Abitur

Termine Gymnasien 2026 (Bildungsserver Saarland)

3 core areas

Content is organized around Analysis, Analytische Geometrie/Lineare Algebra, and Stochastik

GOS-VO Saarland; Lehrpläne Gymnasiale Oberstufe

200 / 100 points

Minimum Gesamtqualifikation: 200+ points from Block I, 100+ points from the five Abiturprüfungsfächer (Block II)

GOS-VO Saarland

Free 100-question MCQ study bank for Saarland Abitur Mathematik (compulsory Kernfach). Official exam: structured problems across Analysis, Analytische Geometrie, and Stochastik; Leistungsfach 270–300 / Grundfach 210–240 min. Written date 06.05.2026. Not an official format simulation; no fee for regular school candidates.

Sample Saarland Abitur Mathematics Practice Questions

Try these sample questions to test your Saarland Abitur Mathematics exam readiness. Each question includes a detailed explanation. Start the interactive quiz above for the full 100+ question experience with AI tutoring.

1What is the derivative of f(x) = x^5?
A.f'(x) = 5x^4
B.f'(x) = x^4
C.f'(x) = 5x^5
D.f'(x) = x^6/6
Explanation: By the power rule, d/dx[x^n] = n·x^(n-1), so the derivative of x^5 is 5x^4.
2Given f(x) = x^3 − 3x, what are the x-coordinates of the critical points where f'(x) = 0?
A.x = 1 and x = −1
B.x = 0 only
C.x = 3 and x = −3
D.x = 1 only
Explanation: f'(x) = 3x^2 − 3. Setting 3x^2 − 3 = 0 gives x^2 = 1, so x = 1 or x = −1.
3For f(x) = x^3 − 3x, using f''(x) = 6x, what type of extremum occurs at x = 1?
A.A local minimum, since f''(1) = 6 > 0
B.A local maximum, since f''(1) = 6 > 0
C.A local minimum, since f''(1) = 6 < 0
D.An inflection point, since f''(1) = 0
Explanation: Since f''(1) = 6 > 0, the function is concave up at x = 1, indicating a local minimum (second derivative test).
4What is the y-value of the local minimum of f(x) = x^3 − 3x at x = 1?
A.f(1) = −2
B.f(1) = 2
C.f(1) = 0
D.f(1) = −4
Explanation: f(1) = 1^3 − 3(1) = 1 − 3 = −2.
5What is the derivative of f(x) = x^2 · sin(x), using the product rule?
A.f'(x) = 2x·sin(x) + x^2·cos(x)
B.f'(x) = 2x·cos(x)
C.f'(x) = x^2·cos(x)
D.f'(x) = 2x·sin(x) − x^2·cos(x)
Explanation: The product rule gives (uv)' = u'v + uv'. With u = x^2 (u' = 2x) and v = sin(x) (v' = cos(x)), f'(x) = 2x·sin(x) + x^2·cos(x).
6What is the derivative of f(x) = (2x + 1)^3, using the chain rule?
A.f'(x) = 6(2x + 1)^2
B.f'(x) = 3(2x + 1)^2
C.f'(x) = 6(2x + 1)^3
D.f'(x) = 2(2x + 1)^2
Explanation: By the chain rule, the derivative of (2x+1)^3 is 3(2x+1)^2 multiplied by the derivative of the inner function (2x+1)', which is 2, giving 6(2x+1)^2.
7What is the derivative of f(x) = 1/x (for x ≠ 0)?
A.f'(x) = −1/x^2
B.f'(x) = 1/x^2
C.f'(x) = −1/x
D.f'(x) = ln(x)
Explanation: Rewriting f(x) = x^(−1) and applying the power rule gives f'(x) = −1·x^(−2) = −1/x^2.
8Where does f(x) = x^3 have an inflection point (Wendepunkt)?
A.x = 0, since f''(x) = 6x changes sign there
B.x = 1, since f'(1) = 3
C.x = −1, since f(−1) = −1
D.There is no inflection point
Explanation: f''(x) = 6x; this equals zero and changes sign at x = 0, confirming a genuine inflection point (concavity changes from down to up).
9For a quartic function with negative leading coefficient, f(x) = −x^4 + 2x^2, what is the end behavior as x → ±∞?
A.f(x) → −∞ in both directions
B.f(x) → +∞ in both directions
C.f(x) → −∞ as x→∞ and f(x) → +∞ as x→−∞
D.f(x) approaches a constant value
Explanation: For an even-degree polynomial with a negative leading coefficient, both ends of the graph point downward, so f(x) → −∞ as x → ±∞.
10What is the derivative of f(x) = e^x?
A.f'(x) = e^x
B.f'(x) = x·e^(x−1)
C.f'(x) = e^(x−1)
D.f'(x) = 1
Explanation: The exponential function e^x is its own derivative: d/dx[e^x] = e^x.

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