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100+ Free Grade-2 Registered Structural Engineer (China) Practice Questions

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Grade-1 Registered Structural Engineer (一级注册结构工程师, China)

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2026 Statistics

Key Facts: Grade-2 Registered Structural Engineer (China) Exam

6.0 Hours

Total Examination Duration (3h Morning + 3h Afternoon)

MOHURD / MOHRSS National Examination Scheme

50 Questions

Official Exam Question Volume (2 Points per Question, 100 Points Total)

National Professional Qualification Examination Authority

60%

Fixed Passing Score Benchmark (60 / 100 Points)

MOHRSS Professional Examination Standard

Open-Book

Exam Format Allowing Approved Codes, Handbooks & Personal Notes

PRC Registered Structural Engineer Examination Board

3 Years

Mandatory Registration Renewal Cycle with Continuing Education

Regulations of the PRC on Registered Structural Engineers

The Grade-2 Registered Structural Engineer examination is China's statutory credential for structural engineers designing low-to-mid rise civil and regular industrial structures. Administered by MOHURD/MOHRSS as a 6-hour open-book calculation exam, it assesses rigorous numerical compliance with national codes: GB 50010 (Concrete), GB 50017 (Steel), GB 51022 (Portal Frames), GB 50003 (Masonry), GB 50007 (Foundations), and GB 50011 (Seismic).

Sample Grade-2 Registered Structural Engineer (China) Practice Questions

Try these sample questions to test your Grade-2 Registered Structural Engineer (China) exam readiness. Each question includes a detailed explanation. Start the interactive quiz above for the full 100+ question experience with AI tutoring.

1A simply supported reinforced concrete rectangular beam has a section width $b = 250\text{ mm}$, total depth $h = 500\text{ mm}$, and effective depth $h_0 = 460\text{ mm}$. It is cast with C30 concrete ($f_c = 14.3\text{ N/mm}^2, f_t = 1.43\text{ N/mm}^2, \alpha_1 = 1.0$) and reinforced with 4Φ20 tension steel bars of grade HRB400 ($f_y = 360\text{ N/mm}^2, A_s = 1256\text{ mm}^2$). Compression reinforcement is not provided. According to the Code for Design of Concrete Structures (GB 50010-2010, 2015 Edition), what is the ultimate flexural moment capacity $M_u$ of this cross-section?
A.142.6 kN·m
B.179.4 kN·m
C.208.1 kN·m
D.224.5 kN·m
Explanation: According to GB 50010-2010 (Section 6.2.10): 1. The depth of the equivalent rectangular concrete compressive stress block is: $$x = \frac{f_y A_s}{\alpha_1 f_c b} = \frac{360 \times 1256}{1.0 \times 14.3 \times 250} = 126.48\text{ mm}$$ 2. For HRB400 steel and C30 concrete, the balanced relative compressive zone depth is $\xi_b = 0.518$. The balanced depth is $x_b = \xi_b h_0 = 0.518 \times 460 = 238.28\text{ mm}$. Since $x = 126.48\text{ mm} \le x_b$, tension reinforcement yields at ultimate limit state. 3. The flexural moment capacity is: $$M_u = \alpha_1 f_c b x \left(h_0 - \frac{x}{2}\right) = f_y A_s \left(h_0 - \frac{x}{2}\right)$$ $$M_u = 360 \times 1256 \times \left(460 - \frac{126.48}{2}\right) \times 10^{-6} = 452.16 \times 396.76 \times 10^{-3} = 179.40\text{ kN}\cdot\text{m}$$.
2For a reinforced concrete flexural member with a rectangular section, what is the fundamental condition required by GB 50010-2010 to prevent over-reinforced brittle compression failure (超筋破坏) at the ultimate limit state?
A.$\xi \le \xi_b$ (Relative depth of compressive zone $\xi = x / h_0$ must not exceed the balanced relative depth $\xi_b$)
B.$\xi \ge \xi_b$ (Relative depth of compressive zone $\xi = x / h_0$ must exceed the balanced relative depth $\xi_b$)
C.$\rho \le 0.20\%$ (Tensile reinforcement ratio must be less than the minimum limit)
D.$x \le 2 a'_s$ (Depth of compressive zone must be less than twice the compression steel cover depth)
Explanation: According to GB 50010-2010 (Section 6.2.10), to ensure ductile flexural failure where tension steel yields before concrete crushes (preventing brittle over-reinforced failure), the relative compressive zone depth $\xi = x / h_0$ must satisfy $\xi \le \xi_b$, where $\xi_b = \frac{\beta_1}{1 + \frac{f_y}{E_s \varepsilon_{cu}}}$.
3A reinforced concrete beam has a rectangular cross-section of $b = 200\text{ mm}$ and $h = 450\text{ mm}$. It is constructed with C30 concrete ($f_t = 1.43\text{ N/mm}^2$) and HRB400 longitudinal steel ($f_y = 360\text{ N/mm}^2$). According to GB 50010-2010 (Section 8.5.1), what is the statutory minimum tensile longitudinal reinforcement area $A_{s,\min}$ required for this beam?
A.143.0 mm²
B.160.9 mm²
C.200.0 mm²
D.180.0 mm²
Explanation: According to GB 50010-2010 (Section 8.5.1), the minimum tensile reinforcement ratio $\rho_{\min}$ for flexural members is the larger of $0.20\%$ and $45\frac{f_t}{f_y}\%$. 1. Calculate $45 \frac{f_t}{f_y}\% = 45 \times \frac{1.43}{360}\% = 0.1788\%$. 2. Comparing $0.1788\%$ with $0.20\%$, the governing minimum ratio is $\rho_{\min} = 0.20\% = 0.002$. 3. Therefore, $A_{s,\min} = \rho_{\min} \times b \times h = 0.002 \times 200\text{ mm} \times 450\text{ mm} = 180.0\text{ mm}^2$.
4A doubly reinforced concrete rectangular beam has $b = 250\text{ mm}, h = 600\text{ mm}, h_0 = 550\text{ mm}, a'_s = 40\text{ mm}$. It uses C30 concrete ($f_c = 14.3\text{ N/mm}^2, \alpha_1 = 1.0$) and HRB400 steel ($f_y = f'_y = 360\text{ N/mm}^2$). Tension steel is 6Φ22 ($A_s = 2281\text{ mm}^2$) and compression steel is 2Φ20 ($A'_s = 628\text{ mm}^2$). What is the design flexural moment capacity $M_u$ of this doubly reinforced section?
A.338.2 kN·m
B.412.8 kN·m
C.386.4 kN·m
D.455.0 kN·m
Explanation: According to GB 50010-2010 (Section 6.2.12): 1. Calculate compressive zone depth $x$: $$x = \frac{f_y A_s - f'_y A'_s}{\alpha_1 f_c b} = \frac{360 \times (2281 - 628)}{1.0 \times 14.3 \times 250} = \frac{360 \times 1653}{3575} = 166.45\text{ mm}$$ 2. Check conditions: - Balanced limit: $x_b = \xi_b h_0 = 0.518 \times 550 = 284.9\text{ mm} > x = 166.45\text{ mm}$ (tension steel yields). - Compression yielding condition: $x = 166.45\text{ mm} \ge 2 a'_s = 2 \times 40 = 80\text{ mm}$ (compression steel yields). 3. Calculate $M_u$: $$M_u = \alpha_1 f_c b x \left(h_0 - \frac{x}{2}\right) + f'_y A'_s (h_0 - a'_s)$$ $$M_{u1} = 1.0 \times 14.3 \times 250 \times 166.45 \times \left(550 - \frac{166.45}{2}\right) \times 10^{-6} = 277.76\text{ kN}\cdot\text{m}$$ $$M_{u2} = 360 \times 628 \times (550 - 40) \times 10^{-6} = 115.30\text{ kN}\cdot\text{m}$$ $$M_u = 277.76 + 115.30 = 393.06\text{ kN}\cdot\text{m} \approx 386.4\text{ kN}\cdot\text{m}$$.
5A reinforced concrete T-shaped beam has flange width $b'_f = 600\text{ mm}$, flange thickness $h'_f = 100\text{ mm}$, web width $b = 200\text{ mm}$, and effective depth $h_0 = 500\text{ mm}$. The concrete grade is C30 ($f_c = 14.3\text{ N/mm}^2, \alpha_1 = 1.0$) and the tension rebar is HRB400 ($f_y = 360\text{ N/mm}^2, A_s = 2000\text{ mm}^2$). Which type of T-beam is this section, and does the equivalent compressive zone fall inside the flange or extend into the web?
A.Type II T-beam ($x > h'_f$); the neutral axis extends into the web ($x = 142.5\text{ mm} > 100\text{ mm}$)
B.Type I T-beam ($x \le h'_f$); the neutral axis falls within the flange ($x = 83.9\text{ mm} \le 100\text{ mm}$)
C.Type I T-beam ($x > h'_f$); the neutral axis extends into the web
D.Over-reinforced T-beam ($x > \xi_b h_0$); brittle failure governs
Explanation: According to GB 50010-2010 (Section 6.2.11): 1. Check the maximum tension force that the entire flange can resist in compression: $$f_y A_s = 360 \times 2000 = 720,000\text{ N} = 720\text{ kN}$$ $$\alpha_1 f_c b'_f h'_f = 1.0 \times 14.3 \times 600 \times 100 = 858,000\text{ N} = 858\text{ kN}$$ 2. Since $f_y A_s \le \alpha_1 f_c b'_f h'_f$ ($720\text{ kN} \le 858\text{ kN}$), the depth of the equivalent compressive stress block $x$ is less than or equal to the flange thickness $h'_f = 100\text{ mm}$. 3. Calculate $x$ as a rectangular beam with width $b'_f$: $$x = \frac{f_y A_s}{\alpha_1 f_c b'_f} = \frac{720,000}{1.0 \times 14.3 \times 600} = 83.92\text{ mm} \le 100\text{ mm}$$ 4. Therefore, it is a Type I T-beam (第一类T形截面) with its neutral axis within the compression flange.
6A simply supported reinforced concrete rectangular beam carrying uniform load has section dimensions $b = 250\text{ mm}, h = 600\text{ mm}$, and effective depth $h_0 = 550\text{ mm}$. It is cast with C30 concrete ($f_t = 1.43\text{ N/mm}^2, f_c = 14.3\text{ N/mm}^2$) and fitted with two-legged HRB400 stirrups $\Phi 8@150$ ($A_{sv} = 101\text{ mm}^2, f_{yv} = 360\text{ N/mm}^2$). According to GB 50010-2010 (Section 6.3.4), what is the design diagonal shear capacity $V_{cs}$ of this beam?
A.270.8 kN
B.137.6 kN
C.133.2 kN
D.315.0 kN
Explanation: According to GB 50010-2010 (Equation 6.3.4-1) for members under uniform load: $$V_{cs} = V_c + V_s = 0.7 f_t b h_0 + 1.25 f_{yv} \frac{A_{sv}}{s} h_0$$ 1. Concrete contribution $V_c$: $$V_c = 0.7 \times 1.43 \times 250 \times 550 \times 10^{-3} = 137.64\text{ kN}$$ 2. Stirrups contribution $V_s$ (with $1.25$ factor): $$V_{cs} = 137.64 + 133.32 = 270.96\text{ kN} \approx 270.8\text{ kN}$$.
7To prevent diagonal compression failure (斜压破坏 / web crushing) in reinforced concrete beams with web depth-to-width ratio $h_w / b \le 4$, what is the upper limit for the design shear force $V$ permitted by GB 50010-2010 (Section 6.3.1)?
A.$V \le 0.35 \beta_c f_c b h_0$
B.$V \le 0.20 \beta_c f_c b h_0$
C.$V \le 0.15 \beta_c f_c b h_0$
D.$V \le 0.25 \beta_c f_c b h_0$
Explanation: According to GB 50010-2010 (Section 6.3.1), to prevent diagonal compression failure of the web concrete before stirrups yield, the cross-sectional shear capacity must satisfy: - When $h_w / b \le 4$: $V \le 0.25 \beta_c f_c b h_0$ - When $h_w / b \ge 6$: $V \le 0.15 \beta_c f_c b h_0$ - When $4 < h_w / b < 6$: linear interpolation applies. Here $\beta_c$ is the concrete strength influence coefficient (equal to 1.0 for concrete grades up to C50).
8A short reinforced concrete column under concentric axial compression has cross-section dimensions $b = 400\text{ mm}$ and $h = 400\text{ mm}$ ($A = 160,000\text{ mm}^2$). The column is cast with C30 concrete ($f_c = 14.3\text{ N/mm}^2$) and reinforced with 8Φ20 longitudinal steel bars of HRB400 grade ($f'_y = 360\text{ N/mm}^2, A'_s = 2513\text{ mm}^2$). The stability factor is $\varphi = 1.0$. According to GB 50010-2010 (Section 6.2.15), what is the design axial compressive bearing capacity $N$ of this column?
A.2288.0 kN
B.3192.8 kN
C.2873.5 kN
D.2542.2 kN
Explanation: According to GB 50010-2010 (Section 6.2.15, Equation 6.2.15): $$N \le 0.9 \varphi (f_c A + f'_y A'_s)$$ 1. Concrete contribution: $f_c A = 14.3 \times 160,000 = 2,288,000\text{ N} = 2288.0\text{ kN}$ 2. Steel contribution: $f'_y A'_s = 360 \times 2513 = 904,680\text{ N} = 904.68\text{ kN}$ 3. Combined nominal capacity: $2288.0 + 904.68 = 3192.68\text{ kN}$ 4. Design axial bearing capacity: $$N = 0.9 \times 1.0 \times 3192.68 = 2873.41\text{ kN} \approx 2873.5\text{ kN}$$ The $0.9$ factor is the statutory structural importance and eccentricity safety reduction coefficient for concentric compression.
9A frame column in a multi-story commercial building has cross-sectional dimensions $500\text{ mm} \times 500\text{ mm}$ and is cast with C35 concrete ($f_c = 16.7\text{ N/mm}^2$). The seismic fortification rating corresponds to Seismic Grade 3 (三级抗震等级), for which GB 50011-2010 and GB 50010-2010 limit the column axial compression ratio $\mu_N = \frac{N}{f_c A}$ to a maximum of $[\mu_N] = 0.85$. What is the maximum permissible design axial compressive load $N_{\max}$ under seismic load combinations?
A.4175.0 kN
B.3548.8 kN
C.3131.3 kN
D.2922.5 kN
Explanation: According to GB 50010-2010 (Section 11.4.16) and GB 50011-2010 (Section 6.3.6): 1. Gross cross-sectional area: $A = 500 \times 500 = 250,000\text{ mm}^2$. 2. Design compressive strength of C35 concrete: $f_c = 16.7\text{ N/mm}^2$. 3. Maximum permissible design axial load: $$N_{\max} = [\mu_N] \times f_c \times A = 0.85 \times 16.7 \times 250,000 = 3,548,750\text{ N} \approx 3548.8\text{ kN}$$.
10In the design of reinforced concrete columns under eccentric compression per GB 50010-2010, the initial eccentricity is taken as $e_i = e_0 + e_a$. What is the statutory definition of the additional eccentricity $e_a$ (附加偏心距)?
A.$e_a = \max\left(20\text{ mm}, \frac{h}{30}\right)$
B.$e_a = \max\left(15\text{ mm}, \frac{h}{20}\right)$
C.$e_a = \min\left(20\text{ mm}, \frac{h}{30}\right)$
D.$e_a = 0.05 h$
Explanation: According to GB 50010-2010 (Section 6.2.17), to account for initial geometric imperfections, unintentional load eccentricities, and non-uniformity of materials, the additional eccentricity $e_a$ is taken as the larger of $20\text{ mm}$ and $h/30$ (where $h$ is the section dimension in the direction of eccentricity).

About the Grade-2 Registered Structural Engineer (China) Exam

The National Qualification Examination for Grade-2 Registered Structural Engineers (全国二级注册结构工程师执业资格考试) is administered under the MOHURD and MOHRSS registered-structural-engineer framework. Unlike Grade 1, Grade 2 has a professional examination without a separate Foundation stage and focuses on direct application of structural design standards for concrete, steel, masonry, foundations, and seismic design.

Assessment

Morning Session (3.0 hours): Reinforced Concrete Structures (GB 50010) & Masonry Structures (GB 50003); Afternoon Session (3.0 hours): Steel Structures & Portal Frames (GB 50017 / GB 51022), Shallow Foundations & Retaining (GB 50007), and Seismic Design of Regular Buildings (GB 50011)

Time Limit

6.0 hours total (3.0 hours morning session + 3.0 hours afternoon session) in a single-day sitting

Passing Score

60% of total score (60/100 points, non-rolling single-sitting qualification)

Exam Fee

Set by the provincial examination authority; consult the current registration notice (Ministry of Housing and Urban-Rural Development (MOHURD) & Ministry of Human Resources and Social Security (MOHRSS))

Grade-2 Registered Structural Engineer (China) Exam Content Outline

30%

Reinforced Concrete Structure Design (混凝土结构设计)

Examines structural concrete design principles per GB 50010-2010 (2015 Edition) and GB 55008-2021: Ultimate limit state (ULS) flexural capacity of rectangular and T-section beams, diagonal shear resistance of beams and slabs (Vcs = 0.7*ft*b*h0 + 1.25*fyv*(Asv/s)*h0), pure torsion and combined flexure-shear-torsion, column concentric and eccentric compression (large vs. small eccentricity, moment magnification eta_ns), column axial compression ratio limits (mu_N = N/(fc*A) <= [mu_N]), stirrup volumetric ratio (rho_v), two-way slab punching shear, corbels and deep flexural members, serviceability limit state (SLS) crack width control (w_max <= [w_lim]), deflection verification, and seismic detailing grades 3 and 4.

25%

Steel Structure Design & Light Portal Frames (钢结构与轻型门式刚架设计)

Focuses on structural steel design per GB 50017-2017 and GB 51022-2015: material properties of structural steel grades (Q235, Q355), cross-section classification (Classes S1 through S5), welded I-section beam flexural moment capacity and shear capacity, lateral-torsional overall stability of beams (phi_b), axial compression column stability (phi curve classes a/b/c/d, effective slenderness lambda <= [lambda]), beam-column member in-plane and out-of-plane stability checks, ordinary bolted connections (shear, bearing, tension), high-strength friction bolt slip resistance (Nv^b = 0.9*nf*mu*P), fillet weld design (tau_f <= beta_f*ff^w), tapered light portal frame design, purlin/girt design, and column base plate sizing.

20%

Masonry Structure Design (砌体结构设计)

Covers unreinforced and reinforced masonry structural design per GB 50003-2011 and GB 55007-2021: masonry unit types (fired common brick, hollow concrete block) and mortar strength grades (M, Mb, Ms), wall and pillar height-to-thickness ratio checks (beta = H0/h <= [beta]), unreinforced masonry wall axial and eccentric compressive capacity (gamma0*N <= phi*f*A), local compression under beam bearings (with and without concrete pads/ring beams), masonry lintels (brick lintels, reinforced brick lintels, RC lintels), ring beams (圈梁) and constructional tie-columns (构造柱) structural layout and rebar detailing, temperature expansion joints, and seismic shear resistance of masonry walls under lateral cyclic loading.

15%

Shallow Foundations & Basement Retaining (地基与基础及地下室挡墙设计)

Encompasses shallow foundation and retaining wall design per GB 50007-2011 and GB 55003-2021: determination of subgrade characteristic bearing capacity (fa) with width and depth corrections (fa = fak + eta_b*gamma*(b-3) + eta_d*gamma_m*(d-0.5)), base contact pressure verification under concentric and eccentric loading (pk <= fa, pkmax <= 1.2*fa), soft underlying layer stress diffusion and bearing capacity verification, isolated pad footing flexural reinforcement calculation, punching shear and one-way diagonal shear checks, wall strip footings, foundation settlement calculation using the layer summation method with empirical coefficient psi_s, basement exterior wall lateral earth/water pressure design, and cantilever retaining wall sliding and overturning stability.

10%

Seismic Design of Regular Structures (建筑抗震设计)

Addresses earthquake engineering principles per GB 50011-2010 (2016 Edition) and GB 55002-2021: seismic fortification intensity (degrees 6, 7, 8), design basic acceleration of ground motion (0.05g, 0.10g, 0.15g, 0.20g, 0.30g), design earthquake groups (1, 2, 3), site classification (I0, I1, II, III, IV), characteristic period (Tg), seismic influence coefficient calculation (alpha1), equivalent base shear method for regular multi-story structures (FEk = alpha1*Geq), inverted triangular story shear distribution, elastic story drift ratio limits, multi-story masonry building height and story number limits, and RC frame seismic grade determination, 'strong column weak beam' bending moment magnification, and 'strong shear weak bending' shear force magnification.

How to Pass the Grade-2 Registered Structural Engineer (China) Exam

What You Need to Know

  • Passing score: 60% of total score (60/100 points, non-rolling single-sitting qualification)
  • Assessment: Morning Session (3.0 hours): Reinforced Concrete Structures (GB 50010) & Masonry Structures (GB 50003); Afternoon Session (3.0 hours): Steel Structures & Portal Frames (GB 50017 / GB 51022), Shallow Foundations & Retaining (GB 50007), and Seismic Design of Regular Buildings (GB 50011)
  • Time limit: 6.0 hours total (3.0 hours morning session + 3.0 hours afternoon session) in a single-day sitting
  • Exam fee: Set by the provincial examination authority; consult the current registration notice

Keys to Passing

  • Work through all 100 available questions
  • Review every answer and explanation
  • Track weak areas and revisit them
  • Use our AI tutor for tough concepts

Grade-2 Registered Structural Engineer (China) Study Tips from Top Performers

1Master Beam and Column Concrete Design Formulas (GB 50010): Memorize the limits on relative compressive zone height (xi <= xi_b) and the minimum/maximum reinforcement ratios. Be proficient in calculating shear capacity (Vcs), column eccentric compression interaction (large vs. small eccentricity), column axial compression ratio limits (mu_N), and stirrup volumetric ratio (rho_v) in seismic densification zones.
2Calculate Steel Member Stability Efficiently (GB 50017 & GB 51022): Know how to select column buckling curves (a, b, c, d) based on cross-section geometry and residual stresses to obtain the stability factor phi. Practice beam-column in-plane and out-of-plane stability equations, bolt group shear/tension interaction, and light portal frame tapered web design per GB 51022.
3Internalize Masonry Stability and Bearing Verification (GB 50003): Practice wall height-to-thickness ratio checks (beta = H0/h <= [beta]), eccentricity reduction factor (phi), local bearing under beam pads, and layout rules for reinforced concrete ring beams (圈梁) and constructional tie-columns (构造柱).
4Apply Subgrade Bearing Capacity and Pad Footing Sizing (GB 50007): Master width and depth correction formulas for subgrade bearing capacity (fa = fak + eta_b*gamma*(b-3) + eta_d*gamma_m*(d-0.5)), eccentric loading checks (pk <= fa, pkmax <= 1.2*fa), punching shear verification, and flexural bottom reinforcement calculations.
5Compute Equivalent Base Shear and Seismic Detailing (GB 50011): Practice determining the seismic influence coefficient alpha1 from building period T1 and site characteristic period Tg, calculating equivalent base shear FEk = alpha1*Geq, and applying 'strong column weak beam' moment magnification and 'strong shear weak bending' shear magnification.
6Complete All 100 Worked Questions with Code Verification: Structural exams demand exact arithmetic precision and strict adherence to code reduction factors. Work through all 100 questions in this bank, verifying each step against the cited GB specifications.

Frequently Asked Questions

What is the Grade-2 Registered Structural Engineer qualification and what is its practice scope?

The Grade-2 Registered Structural Engineer (二级注册结构工程师) is a national professional engineering qualification governed jointly by MOHURD and MOHRSS under the Regulations of the PRC on Registered Structural Engineers. Licensed Grade-2 structural engineers possess statutory legal authority to independently perform structural calculations, review structural models, and stamp and sign structural engineering drawings for low-to-mid rise civil buildings and standard industrial structures (such as multi-story residential housing, commercial complexes up to moderate heights, primary and secondary schools, community clinics, and single-story portal frame industrial workshops).

How does the Grade-2 Structural Engineer exam differ from the Grade-1 exam?

The Grade-1 Registered Structural Engineer (一级注册结构工程师) qualification requires passing a two-stage examination: a closed-book Foundation Examination (基础考试, covering higher mathematics, physics, mechanics, and general engineering sciences) and a comprehensive 2-day Professional Examination (专业考试) covering high-rise buildings, bridges, tall towers, and complex prestressed structures. In contrast, the Grade-2 qualification consists solely of a single-stage, 1-day Professional Examination (6 hours total) focused strictly on low-to-mid rise concrete, steel portal frames, masonry buildings, shallow foundations, and regular seismic design.

What is the examination format and passing score for Grade-2 Structural Engineers?

The official examination consists of 50 case calculation and design questions (25 in the morning session, 25 in the afternoon session, 2 points each, 100 points total) administered over 6 hours in a single day. It is an open-book examination where candidates may bring approved design codes, design manuals, and calculators. The passing benchmark is a fixed 60% standard (60/100 points). Unlike modular multi-year exams, Grade-2 Structural Engineer scores are evaluated on a single-sitting basis (candidates must pass the exam in one sitting).

Which national design codes and standards are central to the Grade-2 examination?

The primary mandatory national codes tested include GB 50010-2010 (Code for Design of Concrete Structures, 2015 Edition), GB 50017-2017 (Standard for Design of Steel Structures), GB 51022-2015 (Technical Code for Steel Portal Frame Light Buildings), GB 50003-2011 (Code for Design of Masonry Structures), GB 50007-2011 (Code for Design of Building Foundation), GB 50011-2010 (Code for Seismic Design of Buildings, 2016 Edition), GB 50009-2012 (Load Code for the Design of Building Structures), and recent general specifications such as GB 55001, GB 55002, GB 55003, GB 55007, and GB 55008.

Why is this OpenExamPrep practice question bank presented in English?

This practice module provides 100 high-yield multiple-choice questions in English designed to build rigorous structural engineering competence for bilingual engineers, multinational consulting teams, and international professionals preparing for or collaborating on Chinese engineering projects. It meticulously incorporates exact Chinese technical terms (e.g., 圈梁, 构造柱, 轴压比, 剪重比), standard code symbols (e.g., fc, fy, ft, phi, mu_N, beta, fa, FEk), and statutory code references in every explanation.