All Practice Exams
100+ Free VCE Foundation Mathematics Practice Questions
VCE Foundation Mathematics (Units 3 & 4) practice questions are available now; exam metadata is being verified.
✓ No registration✓ No credit card✓ No hidden fees✓ Start practicing immediately
100+ Questions
100% Free
Loading practice questions...
Same family resources
Explore More VCE (Victorian Certificate of Education)
Continue into nearby exams from the same family. Each card keeps practice questions, study guides, flashcards, videos, and articles in one place.
2026 Statistics
Key Facts: VCE Foundation Mathematics Exam
VCE Foundation Mathematics Units 3 & 4 practice question bank for senior secondary exam revision.
Sample VCE Foundation Mathematics Practice Questions
Try these sample questions to test your VCE Foundation Mathematics exam readiness. Each question includes a detailed explanation. Start the interactive quiz above for the full 100+ question experience with AI tutoring.
1Round 0.004072 to two significant figures.
A.0.0041
B.0.0040
C.0.004
D.0.00407
Explanation: Leading zeros are not significant, so the first two significant figures of 0.004072 are the 4 and the 0. The next digit is 7, which is 5 or more, so the second significant figure rounds up from 0 to 1, giving 0.0041.
2A concrete mix uses cement, sand and aggregate in the ratio 1 : 2 : 4. A batch has a total mass of 21 kg. What mass of cement is required?
A.3 kg
B.5.25 kg
C.7 kg
D.2.1 kg
Explanation: The ratio 1 : 2 : 4 has 1 + 2 + 4 = 7 parts in total. One part is 21 kg divided by 7, which is 3 kg. Cement is 1 part, so 3 kg of cement is needed.
3A steel rod should be 5.00 m long. A measurement records it as 4.85 m. What is the percentage error of the measurement?
A.3%
B.1.5%
C.15%
D.0.3%
Explanation: Percentage error is the size of the difference divided by the true value, expressed as a percentage. The difference is 5.00 - 4.85 = 0.15 m, so the percentage error is 0.15 / 5.00 x 100 = 3%.
4The circumference of a circle is given by C = 2 x pi x r. A circular garden bed has a circumference of 31.4 m. Correct to one decimal place, what is its radius?
A.5.0 m
B.10.0 m
C.15.7 m
D.9.9 m
Explanation: Transpose the formula to make r the subject: r = C / (2 x pi). Substituting gives r = 31.4 / (2 x 3.1416) = 31.4 / 6.2832 = 5.0 m.
5The cost y of a job varies directly with the number of hours x worked. When x = 4.5 hours the cost is AUD 18.00. What is the cost for 7 hours?
A.AUD 28.00
B.AUD 25.00
C.AUD 31.50
D.AUD 20.50
Explanation: Direct variation means y = kx. From 18 = k x 4.5, the constant of variation is k = 4. For x = 7 hours, y = 4 x 7 = AUD 28.00.
6Six landscapers can complete a job in 10 days. Assuming all work at the same rate, how long would 4 landscapers take to complete the same job?
A.15 days
B.6.7 days
C.12 days
D.20 days
Explanation: This is inverse variation, so the number of worker-days stays constant. The job takes 6 x 10 = 60 worker-days. With 4 workers the time is 60 / 4 = 15 days.
7A market stall has costs C = 500 + 8n dollars and revenue R = 18n dollars, where n is the number of items sold. How many items must be sold to break even?
A.50 items
B.28 items
C.63 items
D.100 items
Explanation: Break-even occurs where revenue equals cost. Setting 18n = 500 + 8n gives 10n = 500, so n = 50 items.
8For a stall with costs C = 500 + 8n and revenue R = 18n dollars, what is the total revenue at the break-even point?
A.AUD 900.00
B.AUD 500.00
C.AUD 400.00
D.AUD 1,400.00
Explanation: Break-even occurs at n = 50 items, because 18n = 500 + 8n gives 10n = 500. Revenue is then R = 18 x 50 = AUD 900.00, which equals the total cost of 500 + 8 x 50 = AUD 900.00.
9Which of these numbers is irrational?
A.The square root of 50
B.0.75
C.22/7
D.3.14
Explanation: An irrational number cannot be written as a ratio of two integers, and its decimal expansion never terminates or repeats. 50 is not a perfect square, so its square root is irrational. The other three values are ratios of integers or terminating decimals.
10A 3.5 litre tin of paint covers 42 square metres. How many litres are needed to cover 90 square metres at the same coverage rate?
A.7.5 L
B.6.0 L
C.10.5 L
D.8.4 L
Explanation: The coverage rate is 42 / 3.5 = 12 square metres per litre. Covering 90 square metres requires 90 / 12 = 7.5 litres.
About the VCE Foundation Mathematics Practice Questions
Verified exam format metadata for VCE Foundation Mathematics (Units 3 & 4) is pending. The practice questions above remain available while official exam length, timing, passing score, fee, and administrator details are reviewed.