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100+ Free TASC Mathematics Methods – Foundation Level 3 Practice Questions

TASC Mathematics Methods – Foundation Level 3 Examination (Course Code: MTM315117) practice questions are available now; exam metadata is being verified.

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Key Facts: TASC Mathematics Methods – Foundation Level 3 Exam

Prepare for the TASC Mathematics Methods – Foundation Level 3 (MTM315117) exam with this targeted 100-question practice assessment. Featuring step-by-step worked algebraic calculations across all 5 core modules, this question bank builds fluency in linear and quadratic algebra, index and logarithm laws, introductory differential calculus, and probability. These practice questions are an English-language multiple-choice study aid for revising course knowledge and are not an official TASC paper or a simulation of the written external examination format.

Sample TASC Mathematics Methods – Foundation Level 3 Practice Questions

Try these sample questions to test your TASC Mathematics Methods – Foundation Level 3 exam readiness. Each question includes a detailed explanation. Start the interactive quiz above for the full 100+ question experience with AI tutoring.

1Solve the linear equation: 3(2x - 5) + 4 = 19.
A.x = 3
B.x = 4
C.x = 5
D.x = 6
Explanation: Expanding the brackets gives 6x - 15 + 4 = 19, which simplifies to 6x - 11 = 19. Adding 11 to both sides yields 6x = 30, and dividing by 6 gives x = 5.
2Expand and simplify the algebraic expression: (4x - 3)(x + 2) - 2x(x - 1).
A.2x^2 + 7x - 6
B.2x^2 + 3x - 6
C.6x^2 + 7x - 6
D.2x^2 + 7x + 6
Explanation: Expanding the first double brackets yields (4x^2 + 8x - 3x - 6) = 4x^2 + 5x - 6. Expanding the second term yields -(2x^2 - 2x) = -2x^2 + 2x. Combining like terms: (4x^2 - 2x^2) + (5x + 2x) - 6 = 2x^2 + 7x - 6.
3Solve the linear inequality: 5 - 2x > 13.
A.x > -4
B.x < -4
C.x > 4
D.x < 4
Explanation: Subtracting 5 from both sides gives -2x > 8. Dividing both sides by -2 requires reversing the inequality sign, yielding x < -4.
4Rearrange the formula A = 1/2 * h * (a + b) to make b the subject.
A.b = (2A - ah) / h
B.b = (A - ah) / h
C.b = (2A + ah) / h
D.b = 2A / (h - a)
Explanation: Multiply both sides by 2 to clear the fraction: 2A = h(a + b). Divide by h: 2A / h = a + b. Subtract a from both sides: b = (2A / h) - a = (2A - ah) / h.
5Solve the system of simultaneous equations: 2x + 3y = 12 and 5x - 2y = 11.
A.x = 3, y = 2
B.x = 2, y = 3
C.x = 3, y = -2
D.x = 4, y = 1
Explanation: Multiply the first equation by 2: 4x + 6y = 24. Multiply the second equation by 3: 15x - 6y = 33. Adding the two equations eliminates y: 19x = 57, so x = 3. Substituting x = 3 into 2(3) + 3y = 12 gives 6 + 3y = 12, so 3y = 6 and y = 2.
6Simplify the algebraic fraction expression: 3 / (x + 2) + 2 / (x - 1).
A.(5x + 1) / ((x + 2)(x - 1))
B.(5x - 1) / ((x + 2)(x - 1))
C.5 / ((x + 2)(x - 1))
D.(5x + 5) / ((x + 2)(x - 1))
Explanation: Find a common denominator (x + 2)(x - 1): 3(x - 1) / ((x + 2)(x - 1)) + 2(x + 2) / ((x + 2)(x - 1)) = (3x - 3 + 2x + 4) / ((x + 2)(x - 1)) = (5x + 1) / ((x + 2)(x - 1)).
7Solve the fractional linear equation: (2x + 1)/3 - (x - 2)/4 = 3.
A.x = 4.8
B.x = 5.0
C.x = 5.2
D.x = 5.6
Explanation: Multiply every term by the least common denominator 12: 4(2x + 1) - 3(x - 2) = 36. Expanding gives 8x + 4 - 3x + 6 = 36, which simplifies to 5x + 10 = 36. Subtracting 10 gives 5x = 26, so x = 26/5 = 5.2.
8Solve the double inequality: -3 <= 4x - 7 < 9.
A.1 <= x < 4
B.-1 <= x < 4
C.1 <= x <= 4
D.0 < x < 4
Explanation: Add 7 across all three parts of the inequality: -3 + 7 <= 4x < 9 + 7, yielding 4 <= 4x < 16. Divide all parts by 4: 1 <= x < 4.
9An event venue sells adult tickets for $8 and child tickets for $5. A total of 150 tickets were sold for $960. How many adult tickets were sold?
A.60
B.65
C.70
D.80
Explanation: Let a be the number of adult tickets and c be child tickets. We have a + c = 150 (so c = 150 - a) and 8a + 5c = 960. Substituting c gives 8a + 5(150 - a) = 960 => 8a + 750 - 5a = 960 => 3a = 210 => a = 70 adult tickets.
10Evaluate the function f(x) = (3x - 7) / (2x + 1) at x = -2.
A.-13/3
B.13/3
C.1/3
D.-1/3
Explanation: Substitute x = -2 into numerator and denominator: f(-2) = (3(-2) - 7) / (2(-2) + 1) = (-6 - 7) / (-4 + 1) = (-13) / (-3) = 13/3.

About the TASC Mathematics Methods – Foundation Level 3 Practice Questions

Verified exam format metadata for TASC Mathematics Methods – Foundation Level 3 Examination (Course Code: MTM315117) is pending. The practice questions above remain available while official exam length, timing, passing score, fee, and administrator details are reviewed.