All Practice Exams
100+ Free QCAA Engineering EA Practice Questions
QCAA Engineering External Assessment (Queensland) practice questions are available now; exam metadata is being verified.
✓ No registration✓ No credit card✓ No hidden fees✓ Start practicing immediately
100+ Questions
100% Free
Loading practice questions...
Same family resources
Explore More Queensland Certificate of Education (QCE) External Assessments
Continue into nearby exams from the same family. Each card keeps practice questions, study guides, flashcards, videos, and articles in one place.
2026 Statistics
Key Facts: QCAA Engineering EA Exam
25%
Weighting of the external assessment towards final subject result
QCAA Engineering Senior Syllabus
120 min
Working time for the external written examination
QCAA Assessment Schedule
100
Free practice questions in this comprehensive question bank
OpenExamPrep
Prepare for the QCAA Engineering external examination with 100 high-quality practice questions covering statics, truss analysis, mechanics of materials, linear/rotational dynamics, gear ratios, control loops, logic gates, and fluid power.
Sample QCAA Engineering EA Practice Questions
Try these sample questions to test your QCAA Engineering EA exam readiness. Each question includes a detailed explanation. Start the interactive quiz above for the full 100+ question experience with AI tutoring.
1Two forces of 30 N and 40 N act concurrently on a point at right angles to each other. What is the magnitude of the resultant force?
A.50 N
B.10 N
C.70 N
D.1200 N
Explanation: Because the two forces act at right angles (90°), the magnitude of their resultant force R is found using Pythagoras' theorem: R = sqrt(30^2 + 40^2) = sqrt(900 + 1600) = sqrt(2500) = 50 N.
2Which set of equations defines static equilibrium for a rigid body subjected to a coplanar (2D) force system?
A.sum(Fx) = sum(Fy), sum(M) = 0
B.sum(Fx) = 0, sum(Fy) = 0, sum(M) = 0
C.sum(Fx) = 0, sum(Fy) = 0, sum(M) = F * d
D.sum(Fx) + sum(Fy) + sum(M) = 0
Explanation: For a 2D body to remain in static equilibrium, the sum of horizontal forces must equal zero (sum(Fx) = 0), the sum of vertical forces must equal zero (sum(Fy) = 0), and the sum of moments about any point must equal zero (sum(M) = 0).
3A perpendicular force of 25 N is applied to the end of a lever arm of length 0.4 m. What is the moment generated about the pivot?
A.6.25 N·m
B.62.5 N·m
C.10 N·m
D.100 N·m
Explanation: Moment is calculated as M = F * d, where F is perpendicular to the line of action. M = 25 N * 0.4 m = 10 N·m.
4A crate of mass 10 kg rests on a frictionless plane inclined at 30° to the horizontal. Taking g = 9.8 m/s², what is the component of the gravitational force acting parallel to the incline?
A.84.9 N
B.98 N
C.196 N
D.49 N
Explanation: The component of weight parallel to an inclined plane is F_parallel = m * g * sin(theta). Here, m * g = 10 kg * 9.8 m/s² = 98 N. F_parallel = 98 * sin(30°) = 98 * 0.5 = 49 N.
5A simply supported beam AB of length 6.0 m carries a single vertical point load of 12 kN located 2.0 m from support A. What is the vertical reaction force at support B?
A.4.0 kN
B.6.0 kN
C.8.0 kN
D.12.0 kN
Explanation: Taking moments about support A: sum(M_A) = 0 => (12 kN * 2.0 m) - (R_B * 6.0 m) = 0 => 24 = 6.0 * R_B => R_B = 4.0 kN.
6In a pin-jointed plane truss, how can zero-force members be identified at an unloaded joint containing two non-collinear members?
A.The longer member is zero-force and the shorter carries load
B.Both members must be zero-force members
C.One member is in tension and the other is in compression
D.Neither member is a zero-force member
Explanation: If a joint has only two non-collinear members and no external load or support reaction is applied at that joint, resolving forces along axes aligned with each member shows that both members must carry zero force (sum(F) = 0).
7A symmetrical triangular truss consists of two equal diagonal members forming a 60° angle at the top apex joint. A vertical downward load of 10.0 kN acts on the apex. What is the internal force in each diagonal member?
A.5.00 kN tension
B.8.66 kN tension
C.5.77 kN compression
D.10.0 kN compression
Explanation: Each member makes an angle of 30° with the vertical (since 60° / 2 = 30°). Resolving vertical forces at the apex joint: 2 * F * cos(30°) = 10.0 kN => 2 * F * 0.866 = 10.0 => 1.732 * F = 10.0 => F = 5.77 kN. Because the members push up to resist the downward load, they are in compression.
8When analyzing a bridge truss using the Method of Sections, what is the maximum number of unknown member forces that can generally be determined by cutting a single imaginary section line through the truss?
A.1
B.2
C.6
D.3
Explanation: For a 2D coplanar truss, there are three independent equations of equilibrium available (sum(Fx)=0, sum(Fy)=0, sum(M)=0). Therefore, a section line should cut through no more than 3 unknown members to allow direct calculation of member forces.
9A T-beam cross-section consists of a horizontal flange (width 80 mm, height 20 mm) attached to a vertical web (width 20 mm, height 80 mm). Measuring from the flat bottom surface of the web, what is the vertical coordinate (y-bar) of the centroid?
A.65 mm
B.50 mm
C.60 mm
D.70 mm
Explanation: Divide into two rectangles: Web (area A1 = 80 mm * 20 mm = 1,600 mm², centroid y1 = 40 mm) and Flange (area A2 = 80 mm * 20 mm = 1,600 mm², centroid y2 = 80 mm + 10 mm = 90 mm). Total area A = 3,200 mm². The vertical centroid coordinate y-bar = (1,600 * 40 + 1,600 * 90) / 3,200 = 65 mm.
10A wooden block of mass 20 kg rests on a horizontal steel surface. The coefficient of static friction between wood and steel is mu_s = 0.35. Taking g = 9.8 m/s², what maximum horizontal force can be applied before the block starts to slide?
A.7.0 N
B.68.6 N
C.196 N
D.560 N
Explanation: Normal force N = m * g = 20 kg * 9.8 m/s² = 196 N. Maximum static friction force F_f = mu_s * N = 0.35 * 196 N = 68.6 N.
About the QCAA Engineering EA Practice Questions
Verified exam format metadata for QCAA Engineering External Assessment (Queensland) is pending. The practice questions above remain available while official exam length, timing, passing score, fee, and administrator details are reviewed.