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100+ Free ACCA Residential HVAC Design Practice Questions
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In Manual J, the heat transfer multiplier (HTM) for an opaque surface such as a wall is best described as:
A
B
C
D
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2026 Statistics
Key Facts: ACCA Residential HVAC Design Exam
5
Core Standards (J/S/D/T + 5)
ACCA
95-115%
Manual S Cooling Sizing
ACCA Manual S
0.06-0.18
Manual D Friction Rate (in. w.c./100 ft)
ACCA Manual D
8th Ed
Manual J Edition
ANSI/ACCA 2
5 yrs
Certificate Validity
ACCA
+/-15%
QI Airflow Tolerance
ANSI/ACCA 5
The ACCA Residential HVAC Design exam tests the full residential design workflow across Manual J, S, D, and T plus Standard 5 Quality Installation. Manual J 8th Edition drives load calculation using design conditions and block versus room-by-room loads; Manual S selects equipment within a 95-115% cooling sizing window using OEM expanded performance data; Manual D sizes ducts with the friction-rate method, FR = (ASP x 100) / TEL; Manual T selects registers and grilles; and ANSI/ACCA Standard 5 verifies airflow, refrigerant charge, and documentation. The certificate is valid for 5 years.
Sample ACCA Residential HVAC Design Practice Questions
Try these sample questions to test your ACCA Residential HVAC Design exam readiness. Each question includes a detailed explanation. Start the interactive quiz above for the full 100+ question experience with AI tutoring.
1Per ACCA Manual J 8th Edition, which load calculation should be used to select cooling and heating equipment for a typical single-family home with one central system?
A.The block (whole-house) load
B.The largest single room load
C.The sum of all peak room loads regardless of timing
D.The connected appliance nameplate load
Explanation: Equipment for a single-zone central system is sized from the block load, which accounts for the simultaneous peak of the entire house rather than adding non-coincident room peaks. Room-by-room loads are used to size the air distributed to each room, not the equipment.
2Manual J specifies default indoor design conditions for cooling. What indoor dry-bulb temperature and relative humidity does Manual J use as the standard cooling design point?
A.70 degrees F and 30% RH
B.75 degrees F and 50% RH
C.72 degrees F and 60% RH
D.78 degrees F and 55% RH
Explanation: Manual J uses a default indoor cooling design condition of 75 degrees F dry-bulb and 50% relative humidity. The heating indoor default is 70 degrees F. These defaults set the indoor-outdoor temperature differences that drive the load.
3When selecting outdoor design conditions in Manual J, the cooling outdoor dry-bulb is typically taken at which ASHRAE annual percentile?
A.0.4% cooling design dry-bulb
B.5% cooling design dry-bulb
C.1% cooling design dry-bulb
D.10% cooling design dry-bulb
Explanation: Manual J commonly uses the 1% cooling design dry-bulb (with the mean coincident wet-bulb) so the system is sized for conditions exceeded only about 1% of the cooling hours. Using a more extreme percentile like 0.4% would oversize the equipment for residential comfort.
4A heating design temperature difference (Delta T) is needed for a Manual J calculation. If the indoor heating design is 70 degrees F and the outdoor 99% heating design dry-bulb is 5 degrees F, what is the heating Delta T?
A.60 degrees F
B.70 degrees F
C.75 degrees F
D.65 degrees F
Explanation: Heating Delta T equals the indoor design temperature minus the outdoor design temperature: 70 - 5 = 65 degrees F. This temperature difference drives the conductive (transmission) and infiltration heating losses through the building envelope.
5In Manual J, the heat transfer multiplier (HTM) for an opaque surface such as a wall is best described as:
A.The U-value multiplied by the design temperature difference
B.The R-value divided by surface area
C.The CFM of infiltration times 1.1
D.The latent load per square foot of glazing
Explanation: The HTM is the heat flow per square foot of surface and equals the surface U-value times the applicable design temperature difference. Multiplying the HTM by the net surface area gives the conductive load for that component.
6A wall has a U-value of 0.065 Btu/h.ft2.F and a heating Delta T of 65 degrees F. What is the heating HTM for this wall?
A.1.0 Btu/h.ft2
B.4.2 Btu/h.ft2
C.6.5 Btu/h.ft2
D.13.0 Btu/h.ft2
Explanation: HTM equals U times Delta T: 0.065 x 65 = 4.225, rounded to about 4.2 Btu/h per square foot. Multiplying this HTM by the net wall area yields the wall's conductive heating loss.
7Fenestration cooling loads in Manual J depend strongly on which two glazing properties?
A.Visible transmittance and emissivity only
B.Frame width and glazing thickness only
C.U-factor and Solar Heat Gain Coefficient (SHGC)
D.Air leakage and condensation resistance only
Explanation: Window cooling load combines a conductive component driven by the U-factor and a solar component driven by the SHGC. Manual J uses both, along with orientation and shading, to compute the window heat gain.
8In Manual J, window solar gains are strongly affected by orientation. Which orientation typically produces the highest peak instantaneous solar gain for a vertical window during the cooling design hour in summer?
A.North
B.Directly overhead (skylight aside)
C.Northeast at sunrise only
D.East or West
Explanation: East and west vertical glazing receive intense low-angle sun in the morning and afternoon, producing the largest peak solar gains for the cooling load. North glass gets the least direct solar gain in summer in the Northern Hemisphere.
9The Manual J sensible infiltration/ventilation load is calculated with which standard relationship (I-P units)?
A.Q_sensible = 1.1 x CFM x Delta T
B.Q_sensible = 4.5 x CFM x Delta h
C.Q_sensible = 0.68 x CFM x Delta W_grains
D.Q_sensible = 500 x GPM x Delta T
Explanation: The sensible air-side load uses Q = 1.1 x CFM x Delta T, where 1.1 bundles air density and specific heat at standard conditions. The 4.5 and 0.68 constants apply to total enthalpy and latent (grains) calculations respectively.
10Using Q = 1.1 x CFM x Delta T, what is the sensible heating load from 60 CFM of infiltration at a heating Delta T of 65 degrees F?
A.2,145 Btu/h
B.4,290 Btu/h
C.3,300 Btu/h
D.5,400 Btu/h
Explanation: Q = 1.1 x 60 x 65 = 4,290 Btu/h. This is the sensible heating load attributable to that infiltration airflow under the design temperature difference.
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