Using the API 650 one-foot method, td = 2.6 D (H − 1) G / Sd, find the required design thickness for D = 40 ft, H = 32 ft, G = 1.0, Sd = 23,200 psi, and CA = 0. API 650 also requires a 3/16 in minimum for tanks under 50 ft in diameter. What thickness governs?
- A0.094 in, because half the calculated value is always used
- B0.139 in, the calculated one-foot value, because it is less than 3/16 in
- C3/16 in (0.1875 in), because it is greater than the calculated 0.139 in
- D3/8 in, the minimum for tanks larger than 200 ft