A block of mass 4.0 kg is placed at rest on an inclined plane making an angle of 30° with the horizontal. The coefficient of static friction between the block and the plane is μ_s = 0.60. Taking g = 10 m/s^2, sin(30°) = 0.50, and cos(30°) = 0.87, which statement correctly describes the friction force acting on the block?
- AThe block remains stationary, and the static friction force is exactly 20 N acting up the…
- BThe block slides down the incline because the downhill gravitational component exceeds ma…
- CThe block remains stationary, and the static friction force is 20.88 N acting up the incl…
- DThe static friction force is zero because the block is at rest.