8.2 Curve Staking, Deflections, Offsets, and Coordinate Points

Key Takeaways

  • The total deflection angle from the PC tangent to the PT equals Δ/2; any intermediate point's deflection is proportional to the arc length to that point.
  • Per-station deflection accrues at D/2 per 100-ft arc, or δ = (arc/L)·(Δ/2) for an arc of given length.
  • Subchords occur at the start and end of a curve where the alignment does not land on a full 100-ft station.
  • Coordinate (COGO) staking from PC northing/easting and a computed chord bearing is the modern check on hand deflection tables.
  • Field crews tape chords while stationing measures arc; the difference is negligible for flat curves but real for sharp ones.
Last updated: June 2026

Deflection-Angle Layout

Once a curve is designed, the field crew needs stakeable points. The classic method occupies the PC with the instrument backsighted along the tangent and turns deflection angles to set successive points along the arc. The governing rule is that the total deflection from the PC tangent to the PT is exactly Δ/2 (half the central angle). Each intermediate point's deflection is proportional to the arc length from the PC to that point:

δ = (arc length to point ÷ total arc length L) × (Δ/2)

Equivalently, the deflection accrues at a constant rate of D/2 per 100-ft station under the arc definition. So for a 4° curve the deflection grows 2°00' for each full 100 ft of arc. The chord distance set with a tape to each point is C = 2R·sin(δ), where δ is the deflection to that point.

QuantityRelationship
Total deflection PC→PTΔ/2
Deflection to a point(arc/L)·(Δ/2)
Deflection rate per 100 ftD/2 (arc def.)
Chord to a point2R·sin(δ)

Because the deflection to the PT is Δ/2, summing all incremental deflections must close on Δ/2 — a built-in arithmetic check before the crew leaves the PC. The instrument operator turns the cumulative deflection for each station while a chainman tapes the corresponding chord from the previous point, so the two crew members independently fix every stake. When the line of sight is long enough to hold the whole curve, the entire layout can be run from a single PC setup, which is why the deflection method remained the field standard for decades before electronic stakeout.

Subchords and Partial Stations

Real alignments rarely place the PC on an even station. Suppose PC = 47+87.44. The first full station to be staked is 48+00, only 12.56 ft of arc ahead. This short leading piece is a subchord (more precisely a sub-arc). Its deflection is computed from its own short arc, not from a full 100 ft:

δ₁ = (12.56 ÷ L)·(Δ/2)

Using R = 1000, Δ = 24°, L = 418.88: δ₁ = (12.56/418.88)(12°) = 0.3597° ≈ 0°21.6'. From station 48+00 onward, full 100-ft sub-arcs each add the same increment ((100/418.88)(12°) = 2.864° ≈ 2°51.8'), until a closing subchord reaches the PT. The leading and trailing subchords almost never match, so candidates must treat each end separately.

Tape chord vs. arc

Field crews tape chords, but stationing measures arc. For flat curves the difference is trivial; for sharp curves it is not. A 100-ft arc on a 6° curve corresponds to a chord of about 99.95 ft. When chord-definition layout is specified, the 100-ft increments are chords by definition and the arc between them is slightly longer than 100 ft.

Offsets and Coordinate (COGO) Staking

Where line of sight from the PC is blocked, crews use tangent offsets or chord offsets: a point is located by a distance along a reference line plus a perpendicular offset to the arc. The middle ordinate M = R(1 − cos(Δ/2)) is itself the offset from the long-chord midpoint to the curve, and shorter offsets follow the same circular geometry.

Modern practice replaces hand deflection tables with coordinate geometry (COGO). If the PC coordinates (N, E) and the tangent bearing are known, each curve point's coordinates are computed from the chord length and the chord's bearing, which equals the back-tangent bearing rotated by the deflection δ. The crew then stakes by radial stakeout (bearing and distance from a control point) using a total station or RTK GPS. The advantages:

  • Points integrate directly with the project's control network and CAD model.
  • The instrument need not occupy the PC; any visible control point works.
  • An independent check: compute the PT coordinates by COGO and confirm they match the design PT within tolerance.

The enduring exam point is that COGO does not replace understanding — a coordinate that disagrees with the deflection-method check signals a data or geometry error, not a reason to trust the software blindly.

A Full Deflection Table Walkthrough

To see the method end to end, take R = 1000 ft, Δ = 24°, L = 418.88 ft, PC at station 47+87.44, and PT at 52+06.32, staking at full 100-ft stations.

  1. Leading subchord to station 48+00: arc = 12.56 ft. Deflection δ = (12.56/418.88)(12°) = 0°21.6'.
  2. Full stations 49+00, 50+00, 51+00, 52+00: each adds (100/418.88)(12°) = 2°51.8'. Cumulative deflections become 3°13.4', 6°05.2', 8°57.1', and 11°48.9'.
  3. Closing subchord from 52+00 to the PT at 52+06.32: arc = 6.32 ft → 0°10.9'.
  4. Final cumulative deflection = 11°48.9' + 0°10.9' = 12°00.0' = Δ/2. The table closes exactly on half the central angle — the built-in check.
StationArc from PC (ft)Cumulative δ
PC 47+87.4400°00.0'
48+0012.560°21.6'
50+00212.566°05.2'
52+00412.5611°48.9'
PT 52+06.32418.8812°00.0'

The chord taped to each point is C = 2R·sin(δ); for station 50+00, C = 2000·sin(6°05.2') = 212.13 ft from the PC. Because deflections accumulate proportionally to arc and must total Δ/2, any arithmetic slip surfaces immediately as a non-closing final angle — the reason deflection tables remain a trusted manual check even in a COGO-driven workflow.

Test Your Knowledge

On a simple circular curve with Δ = 30°, what is the total deflection angle from the PC tangent to the PT?

A
B
C
D
Test Your Knowledge

A leading subchord covers 18.40 ft of arc on a curve with L = 460.0 ft and Δ = 28°. What deflection angle is turned to that first point?

A
B
C
D
Test Your Knowledge

Why is computing PT coordinates by COGO and comparing them to the design PT a valuable field check?

A
B
C
D
Test Your Knowledge

When a complete deflection table is built from the PC to the PT, the sum of all incremental deflection angles should equal which value?

A
B
C
D