Laboratory Mathematics

Key Takeaways

  • C1V1 = C2V2 governs single dilutions; a 1:10 dilution multiplies the measured result by the dilution factor 10.
  • Serial dilutions multiply each step: three serial 1:10 dilutions give a final 1:1000 dilution.
  • Molarity = moles solute per liter; %w/v = grams per 100 mL; convert mg/dL to mmol/L using molecular weight.
  • Mean, SD, and coefficient of variation (CV = SD/mean x 100) quantify precision; CV allows comparison across analyte levels.
Last updated: June 2026

Dilutions And Dilution Factors

A dilution reduces concentration by adding diluent. A 1:10 dilution means 1 part specimen + 9 parts diluent for a total of 10 parts. The dilution factor (DF) is the reciprocal of the dilution (1:10 → DF = 10). To recover the original concentration, multiply the measured result by the DF.

Worked example: a serum glucose reads off-scale, so the tech makes a 1:5 dilution (1 mL serum + 4 mL saline) and the analyzer reports 90 mg/dL. The reported result is 90 × 5 = 450 mg/dL. Forgetting to multiply by the DF is the single most common dilution error.

Use the C1V1 = C2V2 equation to make a target solution: to prepare 100 mL of 0.1 M HCl from 1.0 M stock, V1 = (C2V2)/C1 = (0.1 × 100)/1.0 = 10 mL stock + 90 mL diluent.

A serial dilution repeats the same dilution stepwise; the factors multiply:

TubeStep dilutionCumulative dilution
11:101:10
21:101:100
31:101:1000
41:101:10,000

Three serial 1:10 steps therefore give a final 1:1000 dilution, not 1:30. In serology, the titer is the reciprocal of the highest dilution still showing reactivity (last reactive tube at 1:256 → titer = 256).

Concentrations, Conversions, And Precision Statistics

Know the concentration units that appear repeatedly on the exam:

  • Molarity (M) = moles of solute per liter of solution.
  • Normality (N) = equivalents per liter (N = M × valence).
  • Percent solutions: %w/v = grams per 100 mL (5% albumin = 5 g/100 mL); %v/v = mL per 100 mL.
  • mg/dL ↔ mmol/L: divide mg/dL by the molecular weight and adjust the factor of 10. For glucose (MW 180), mmol/L = mg/dL ÷ 18; a glucose of 90 mg/dL = 5.0 mmol/L.

Worked example: to make 500 mL of 0.9% NaCl, %w/v means 0.9 g per 100 mL, so 0.9 × 5 = 4.5 g NaCl dissolved and brought to 500 mL.

Precision statistics quantify reproducibility and recur in QC questions:

  • Mean = sum of values ÷ number of values (central tendency).
  • Standard deviation (SD) = spread about the mean.
  • Coefficient of variation (CV) = (SD ÷ mean) × 100, expressed as a percent.

The CV normalizes the SD to the mean, so it lets you compare precision between a low and a high control or between two methods. Worked example: a control has a mean of 100 mg/dL and SD of 4 mg/dL, so CV = (4/100) × 100 = 4%. A lower CV means better precision. By contrast, accuracy (closeness to the true/target value) is assessed against reference materials or proficiency testing, while precision (CV) reflects only reproducibility. A method can be precise but inaccurate (tight cluster off-target) — a frequent distractor pairing on the exam.

Standard Curves, Sensitivity, And Specificity

Many calculations rest on a standard (calibration) curve of absorbance versus concentration. For a linear assay, an unknown's concentration is found by proportion: C(unknown) = C(standard) × A(unknown)/A(standard). Worked example: a 100 mg/dL protein standard reads 0.40 absorbance; a patient reads 0.30. C = 100 × (0.30/0.40) = 75 mg/dL. Always confirm the reading falls within the linear range of the curve before applying the proportion; readings beyond linearity require dilution.

Diagnostic math also appears. Build a 2×2 table (true disease vs test result) and apply:

MetricFormulaMeaning
SensitivityTP / (TP + FN)detects disease when present
SpecificityTN / (TN + FP)rules out disease when absent
PPVTP / (TP + FP)% of positives truly diseased
NPVTN / (TN + FN)% of negatives truly disease-free

Worked example: of 100 diseased patients, a test detects 90 (TP) and misses 10 (FN), giving sensitivity = 90/100 = 90%. PPV and NPV depend on disease prevalence; sensitivity and specificity do not — a classic distractor.

Enzyme Units, Osmolality, And Common Conversions

Enzyme activity is reported in International Units (IU): one IU = the amount of enzyme converting 1 micromole of substrate per minute under defined conditions. Activity is derived from the rate of absorbance change (ΔA/min) using the molar absorptivity of the product.

Calculated values that recur on the MLS exam:

  • Anion gap = Na − (Cl + HCO₃); reference ~8–12 mmol/L. A patient with Na 140, Cl 100, HCO₃ 16 has a gap of 140 − 116 = 24, an elevated (high) anion gap metabolic acidosis.
  • Corrected calcium (mg/dL) = measured Ca + 0.8 × (4.0 − albumin).
  • Calculated osmolality = 2(Na) + glucose/18 + BUN/2.8; an osmolal gap (measured − calculated > 10) suggests an unmeasured solute such as ethanol or methanol.
  • Creatinine clearance = (U × V) / P, where U is urine creatinine, V is urine volume in mL/min, and P is plasma creatinine; correct to body surface area when asked.

Watch unit conversions: 1 dL = 100 mL, 1 L = 1000 mL, 1 g = 1000 mg, 1 mg = 1000 µg, and 1 mole = 1000 mmol. A frequent trap mixes dL and mL — confirm the denominator before computing. As with every operations item, solve the math, then verify the chosen option actually answers the question the stem asked, since a correct number applied to the wrong quantity still produces the wrong best answer.

Test Your Knowledge

A potassium specimen is too concentrated, so a technologist prepares a 1:4 dilution (1 part serum + 3 parts diluent) and the analyzer reads 1.5 mmol/L. What is the correct reported result?

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Test Your Knowledge

A control material has a mean of 200 mg/dL and a standard deviation of 6 mg/dL. What is the coefficient of variation?

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Test Your Knowledge

A technologist performs three sequential 1:10 dilutions of a specimen. What is the final cumulative dilution?

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