For the beam in the previous question (b = 0.25 m, d = 0.45 m, M_u = 120 kN·m, mu_bu = 0.167, f_su = 434.78 MPa), calculate the neutral axis depth parameter alpha = 1.25 * (1 - sqrt(1 - 2 * mu_bu)), the internal lever arm z = d * (1 - 0.4 * alpha), and the required tensile steel reinforcement area A_s.
- Aalpha = 0.230; z = 0.409 m; A_s = 6.75 cm²
- Balpha = 0.167; z = 0.420 m; A_s = 5.25 cm²
- Calpha = 0.315; z = 0.393 m; A_s = 8.15 cm²
- Dalpha = 0.412; z = 0.375 m; A_s = 9.80 cm²