Electricity, Circuits, and Magnetism
Key Takeaways
- Ohm's Law (V = IR) is the fundamental equation for electrical circuits on the OAR.
- In series circuits, current is the same everywhere but voltage divides; in parallel circuits, voltage is the same but current divides.
- Power in electrical circuits: P = IV = I²R = V²/R.
- Resistors in series add directly (R_total = R₁ + R₂); in parallel, use 1/R_total = 1/R₁ + 1/R₂.
- Capacitors store electrical energy; inductors resist changes in current — both appear in OAR questions.
Electricity, Circuits, and Magnetism
Electrical concepts appear regularly on the OAR MCT. You do not need advanced electrical engineering knowledge — focus on Ohm's Law, circuit types, and basic component behavior.
Fundamental Electrical Quantities
| Quantity | Symbol | Unit | Water Analogy |
|---|---|---|---|
| Voltage | V | Volts (V) | Water pressure |
| Current | I | Amperes (A) | Water flow rate |
| Resistance | R | Ohms (Ω) | Pipe narrowness |
| Power | P | Watts (W) | Rate of energy use |
The Water Analogy
Think of electricity like water flowing through pipes:
- Voltage is the pressure pushing water through
- Current is the amount of water flowing per second
- Resistance is how narrow or blocked the pipe is
- Higher pressure (voltage) pushes more water (current) through
- A narrower pipe (higher resistance) reduces flow (current)
Ohm's Law
V = I × R
This is the most important electrical equation for the OAR.
| Find | Formula |
|---|---|
| Voltage | V = IR |
| Current | I = V/R |
| Resistance | R = V/I |
Example: A circuit has a 12V battery and a 4Ω resistor. What is the current? I = V/R = 12/4 = 3 A
Example: A 2A current flows through an 8Ω resistor. What voltage is across the resistor? V = IR = 2 × 8 = 16 V
Series Circuits
Components are connected end-to-end in a single path.
Series Rules
| Property | Rule |
|---|---|
| Current | Same through all components: I_total = I₁ = I₂ = I₃ |
| Voltage | Divides among components: V_total = V₁ + V₂ + V₃ |
| Resistance | Adds directly: R_total = R₁ + R₂ + R₃ |
Example: Three resistors (2Ω, 3Ω, 5Ω) are connected in series to a 20V battery.
- R_total = 2 + 3 + 5 = 10Ω
- I = V/R = 20/10 = 2A (same through all)
- V across 2Ω: V = IR = 2 × 2 = 4V
- V across 3Ω: V = IR = 2 × 3 = 6V
- V across 5Ω: V = IR = 2 × 5 = 10V
- Check: 4 + 6 + 10 = 20V ✓
Series Circuit Facts
- If one component breaks, the entire circuit stops (think: old Christmas lights)
- Larger resistors drop more voltage
- Adding more resistors decreases total current
Parallel Circuits
Components are connected side-by-side, each with its own path to the power source.
Parallel Rules
| Property | Rule |
|---|---|
| Voltage | Same across all branches: V_total = V₁ = V₂ = V₃ |
| Current | Divides among branches: I_total = I₁ + I₂ + I₃ |
| Resistance | Reciprocal formula: 1/R_total = 1/R₁ + 1/R₂ + 1/R₃ |
Example: Two resistors (6Ω and 3Ω) are in parallel with a 12V battery.
- 1/R_total = 1/6 + 1/3 = 1/6 + 2/6 = 3/6 = 1/2 → R_total = 2Ω
- I_total = 12/2 = 6A
- I through 6Ω: I = 12/6 = 2A
- I through 3Ω: I = 12/3 = 4A
- Check: 2 + 4 = 6A ✓
Parallel Circuit Shortcut (Two Resistors)
R_total = (R₁ × R₂) / (R₁ + R₂)
Example: 4Ω and 12Ω in parallel: R_total = (4 × 12)/(4 + 12) = 48/16 = 3Ω
Parallel Circuit Facts
- If one branch breaks, others continue working (think: modern house wiring)
- Total resistance is ALWAYS less than the smallest individual resistor
- Adding more branches decreases total resistance and increases total current
Series vs. Parallel Comparison
| Feature | Series | Parallel |
|---|---|---|
| Current | Same everywhere | Divides among branches |
| Voltage | Divides among components | Same across all branches |
| Total resistance | Sum of all R | Less than smallest R |
| One component fails | Whole circuit stops | Other branches continue |
| Adding components | Increases total R, decreases I | Decreases total R, increases I |
Electrical Power
P = I × V = I²R = V²/R
| Find | Formula | When to Use |
|---|---|---|
| Power | P = IV | When you know I and V |
| Power | P = I²R | When you know I and R |
| Power | P = V²/R | When you know V and R |
Example: A 120V appliance draws 5A. What power does it consume? P = 120 × 5 = 600 W
Example: What is the resistance of a 100W light bulb at 120V? R = V²/P = 120²/100 = 14,400/100 = 144Ω
Key Components
Capacitors
- Store electrical energy in an electric field
- Charge up when connected to a voltage source, discharge when the source is removed
- Block DC current but pass AC current
- In series: 1/C_total = 1/C₁ + 1/C₂ (opposite of resistors!)
- In parallel: C_total = C₁ + C₂ (opposite of resistors!)
Inductors
- Resist changes in current using a magnetic field
- Oppose increases in current when energized, oppose decreases when de-energized
- Pass DC current but resist AC current (opposite of capacitors)
Transformers
- Change voltage levels using electromagnetic induction
- V₁/V₂ = N₁/N₂ (voltage ratio equals turns ratio)
- Step-up transformer: increases voltage, decreases current
- Step-down transformer: decreases voltage, increases current
- Power is conserved: V₁I₁ = V₂I₂
Magnetism
Key Concepts
- Electric current creates a magnetic field
- Moving a conductor through a magnetic field generates voltage (electromagnetic induction)
- Electromagnets: coils of wire with current produce magnetic fields; more turns = stronger field
- Permanent magnets: like poles repel, opposite poles attract
A 9V battery is connected to a 3Ω resistor. What current flows through the circuit?
Two resistors of 10Ω and 10Ω are connected in parallel. What is the total resistance?
In a series circuit, if one light bulb burns out, what happens to the other bulbs?
A 120V outlet supplies power to a 60W light bulb. What current does the bulb draw?
A transformer has 100 turns on the primary coil and 500 turns on the secondary coil. If the input voltage is 120V, what is the output voltage?